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臨床試驗 Analysis of 2x2 Crossover Design
授課老師: 劉仁沛教授 國立台灣大學 與 國家衛生研究院 臨床試驗 Analysis of 2x2 Crossover Design 【本著作除另有註明外,採取創用CC「姓名標示-非商業性-相同方式分享」台灣3.0版授權釋出】
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Inference for 2x2 Crossover Design
References: Chow, SC, and Liu, JP (2014) Design and Analysis of Clinical Trials, 3rd Ed. Wiley Chow, SC and liu, JP (2008) Design and Analysis of Bioavailability and Bioequivalence, 3rd Ed., Chapman & Hall/ CRC, Chapter 3 Chow, SC and Liu, JP (1998) Design and Analysis of Animal Studies in Pharmaceutical Development, Marcel Dekker. PhRMA (2007) Drug Discovery and Development: understanding the R&D process, The Pharmaceutical Research and Manufactures of America
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Inferences for the 2x2 Design
3.1 Introduction Data Structure Sequence Period I Period II 1 (RT) Reference Test Data: Yi11 Data:Yi21 2 (TR) Test Reference Data: Yi12 Data:Yi22
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Inferences for the 2x2 Design
The general model for the standard 2x2 crossover design Yijk = + Sik + Pj + F(j,k) + C(j-1,k) + eijk where i(subject) = 1,…,nk, j(period) = 1,2, k(sequence) = 1,2.
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Inferences for the 2x2 Design
FR, if k=j F(j,k) = { k=1,2; j=1,2 FT, if kj CR, if k=1, j=2 C(j-1,k) = { CT, if k=2, j=2
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Inferences for the 2x2 Design
Fixed effects Sequence Period I Period II 1 (RT) 11= +P1+FR 21 = +P2+FT+CR 2 (TR) 12= +P1+FT 22= +P2+FR+CT where P1 + P2 = 0, FR + FT = 0, and CR + CT =0.
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Inferences for the 2x2 Design
Assumptions Sik iid ~ N(0, S2) eijk iid ~ N(0, e2) Sik and eijk are mutually independent
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Inferences for the 2x2 Design
3.2 The Carryover Effects Subject totals: Uik = Yi1k + Yi2k 2 + CR, if sequence 1 E(Uik) = { 2 + CT, if sequence 2 V(Uik) = 2(e2 + 2s2) = u2 {U11…,Un11} and {U12…,Un22} are independent samples with the same variance u2
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Inferences for the 2x2 Design
Define C = CT - CR Ho: C = 0 vs. Ha: C 0 U.k = (1/nk)Uik, k=1,2. The MVUE OF C is given as Ĉ =U.2 – U.1 = (Y.12+ Y.22) - (Y.11+ Y.21)
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Inferences for the 2x2 Design
V(Ĉ) = u2 [(1/n1) + (1/n2)] V(Ĉ) = su2 [(1/n1) + (1/n2)], where su2 = (Uik - U.k)2 /(n1+n2 –2) Tc = c/v(c)
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Inferences for the 2x2 Design
Reject Ho if Tc > t(/2, n1+n2 –2) Confidence interval c t(/2, n1+n2 –2)v(c) The carryover effect is confounded with the sequence effect
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Inferences for the 2x2 Design
2.3 The Direct Drug Effect Period differences dik = (Yi2k – Yi1k)/2 [(P2 - P1) + (FT - FR) + CR]/2, if sequence = 1 E(dik) = { [(P2 - P1) + (FR - FT) + CT]/2, if sequence = 2 V (dik) = d2 = e2/2
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Inferences for the 2x2 Design
{d11…,dn11} and {d12…,dn22} are independent samples with the same variance d2 Sample means of period differences d.k = (1/nk)dik, k=1,2 Define F = FT - FR E(d.1 - d.2) = F – C/2.
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Inferences for the 2x2 Design
Unless C = 0, no unbiased estimator for F based on the data from both period exists f = d.1 – d.2 = (Y.21 - Y.11) - (Y.22 - Y.12) = (Y.21+ Y.12) - (Y.11+ Y.12) = Y.T - Y.R f is a linear combination of the sequence-by-period means and the least squares estimator of F
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Inferences for the 2x2 Design
V(f) = d2 [(1/n1) + (1/n2)] v(f) = sd2 [(1/n1) + (1/n2)], where sd2 = (dik - d.k)2 /(n1+n2 –2) Ho: F = 0 vs. Ha: F 0 Test Statistic Td = f/v(f)
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Inferences for the 2x2 Design
Under the assumption of C=0 Reject Ho if TF > t(/2, n1+n2 –2) Confidence interval f t(/2, n1+n2 –2)v(f)
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Inferences for the 2x2 Design
When C 0, f is not unbiased for F. However, unbiased estimator can be obtained as the difference of sample means of the first period between the two sequences: f C = Y Y.12 V(f C) = (e2 + s2) [(1/n1) + (1/n2)] V(f C) – V(f) = (e2/2 + s2) [(1/n1) + (1/n2)]
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Inferences for the 2x2 Design
3.4 The Period Effect Crossover difference dik , if sequence = 1 Oik = { -dik , if sequence = 2
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Inferences for the 2x2 Design
[(P2 - P1) + (FT - FR) + CR]/2, if sequence = 1 E(Oik) = { [(P1 – P2) + (FT - FR) - CT]/2, if sequence = 2 V (Oik) = d2 = e2/2 {O11…,On11} and {O12…,On22} are independent samples with the same variance d2. The inference for the period effect can be performed as that for the carryover effects and direct effect. (homework)
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Inferences for the 2x2 Design
3.5 The Analysis of Variance SStotal = (Yijk - Y…)2 = (Yijk - Yi.k + Yi.k - Y... )2 = (Yijk - Yi.k)2 + (Yi.k - Y... )2 = SSwithin + SSbetween
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Inferences for the 2x2 Design
SSbetween = SScarry + SSinter SScarry = [2n1n2/(n1+n2)][(Y.12+ Y.22) - (Y.11+ Y.21)]2 df = 1 SSinter = Y2i.k/2 - Y2..k/2nk, df = n1+n2-2 E(MScarry) = [2n1n2/(n1+n2)](CT - CR)2 + e2 + 2s2 E(MSinter) = e2 + 2s2
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Inferences for the 2x2 Design
SSwithin = SSdrug + SSperiod + SSintra SSdrug = [2n1n2/(n1+n2)]{1/2[(Y.21 - Y.11) - (Y.22+ Y.12)]}2 df =1 SSperiod = [2n1n2/(n1+n2)]{1/2[(Y.21 - Y.11) - (Y.12+ Y.22)]}2 df = 1 SSintra = Y2ijk - Y2i.k/2 - Y2.jk /nk - Y2..k/2nk, df = n1+n2-2
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Inferences for the 2x2 Design
E(MSdrug)=[2n1n2/(n1+n2)][(FT - FR)+(CT - CR)/2]2+e2 E(MSperiod) = [2n1n2/(n1+n2)](P2 – P1)2 + e2 E(MSintra) = e2
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Inferences for the 2x2 Design
Carryover effect: Fc = MScarry/MSinter Direct Drug Effect: Fd = MSdrug/MSintra Period Effect : FP = MSperiod/MSintra Intersubject variability Fv = MSinter/MSintra
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Inferences for the 2x2 Design
3.6 Example (Chow and Liu, 2008) Sequence Sequence Period I Period II Mean 1 (RT) Y.11= Y.21= (TR) Y.12= Y.22= Period mean
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Inferences for the 2x2 Design
Summary of Inference for the Fixed Effects Estimated Effect MVUE Variance 95% C.I. T p-value Carryover (-42.10, 22.91) Direct Drug (-10.03, 5.46) Period ( -9.47, 6.01)
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Inferences for the 2x2 Design
The Analysis of Variance Table SOV df SS MS F p-value Intersubject Carryover Residual Intrasubject Direct Drug Period Residual Total
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Inferences for the 2x2 Design
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Inferences for the 2x2 Design
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臨床試驗 Evaluation of Equivalence and Non-inferiority
授課老師: 劉仁沛教授 國立台灣大學 與 國家衛生研究院 【本著作除另有註明外,採取創用CC「姓名標示-非商業性-相同方式分享」台灣3.0版授權釋出】
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Design and Analysis of Bioequivalence Studies
References: Chow, S.C. and Liu, J.P. (2008)Design of Bioavailability and Bioequivalence Studies, 3rd Ed., CRC/Chapman & Hall, Chapter 4 and 5 FDA (2003) Guidance on Bioavailability and Bioequivalence Studies for Orally Administered Drug Products – General Considerations FDA(2001) Guidance on Statistical Approaches to Establishing Bioequivalence
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Methods for Average Bioavailability
4.1 Introduction 4.2 Interval Hypothesis Testing 4.3 The Confidence Interval Approach 4.4 Log-transformation 4.4 Discussion
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Methods for Average Bioavailability
4.1 Introduction The general model for the 2x2 crossover design without carryover effect: Yijk = + Sik + Pj + F(j,k) + eijk where i(subject) = 1,…,nk, j(period), k(sequence) = 1,2. Define T = + FT and R = + FR Y.R = (Y.11+ Y.22) and Y.T = (Y.21+ Y.12) E(Y.T) = T and E(Y.R) = R
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Methods for Average Bioavailability
Issues on Assessment of ABE Selection of ABE measures difference T - R vs ratio T/R Raw Data vs Log-transformed Data Determination of ABE limits 20/20 in difference or 80/125 in ratio 4. Hypotheses Differences vs equivalence
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Methods for Average Bioavailability
Raw Data: L < T - R < U 20/20 rule: L= -0.2R and U = 0.2R, R is unknown L < T/R < U (L – 1)R < T - R < (U – 1)R, R is unknown. Log-transformed data: L < T/R < U ln(L)< ln(T) – ln(R) < log(U) Limits are not functions of unknown R
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Methods for Average Bioavailability
4.2 Interval Hypotheses Testing Difference: Ho: T - R L or T - R U vs. Ha: L < T - R < U Ratio: Ho: T/R L or T/R U vs. Ha: L < T/R < U
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Methods for Average Bioavailability
Two one-sided hypotheses HoL: T - R L vs. HaL: T - R > L and HoU: T - R U vs. HaU:T - R < U The parameter space of Ho is the union of the parameter spaces of HoLand HoU. The parameter space of Ha is the intersection of the parameter spaces of HaLand HaU.
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Methods for Average Bioavailability
4.2.2 Schuirmann’s Two One-sided Tests (TOST) Procedure Conclude ABE if TL = (f - L)/v(f) > t(, n1+n2 –2) and TU = (f - U)/v(f) < -t(, n1+n2 –2). TOST procedure control the type I error rate at its nominal level. Nonparametric TOST is also available.
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Methods for Average Bioavailability
Example 4.2.1: Y.R = , and Y.T = t(0.05, 22) = and sd = 9.145 U = -L = 0.2(82.559) = 16.51 TL = [( ) ]/9.145sqrt(1/6) = 3.810 TU = [( ) ]/9.145sqrt(1/6) = Issue: U = -L is actually an estimate.
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Methods for Average Bioavailability
4.3 Confidence Interval Approach Data: Raw and untransformed data If a (1-2)100% confidence interval for the difference T - R or the ratio T/R is within the acceptance limits as recommended by the regulatory agency, then accept the test formulation; otherwise reject it. The confidence interval approach is operationally equivalent to the TOST procedure based on the difference T - R = 5% 90% C.I. T - R: 20% T/R: (80%, 120%).
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Methods for Average Bioavailability
4.3.1 The Classical Confidence Interval: L1= (Y.T - Y.R) - t(, n1+n2 –2)sd2 [(1/n1) + (1/n2)], U1= (Y.T - Y.R) + t(, n1+n2 –2)sd2 [(1/n1) + (1/n2)]. and L2= (L1/Y.R + 1)x100%, and U2= (U1/Y.R + 1)x100% Conclude ABE if (1) (L1, U1) (L, U), L,= -0.2R and U = 0.2R or (2) (L2, U2) (80%, 120%)
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Methods for Average Bioavailability
Example 4.3.1 Y.R = , and Y.T = t(0.05, 22) = and sd = 9.145 U= -L = 0.2(82.559) = 16.51 (L1, U1) = (-8.698, 4.123) (-16.51, 16.51) (L1, U1) = (89.46%, %) (80%, 120%) Issue: U = -L is actually an estimate.
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Methods for Average Bioavailability
4.3.2 CI Based on Fieller’s Theorem 1. For ratio T/R based on raw data 2. Take variability of estimator of R into account = T/R = ( + FT)/( + FR) Define (Yi21 - Yi11) , if sequence 1 U*ik = { (Yi12 - Yi22) , if sequence 2
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Methods for Average Bioavailability
{U*11,…, U*n11} are iid normal with mean (P2 - P1) and variance 2, {U*12,…, U*n22} are iid normal with mean -(P2 - P1) and variance 2, where 2 = (T2+S2) - 2S2+ 2(R2+S2). T = (U*.1 + U*.2)/sqrt(wS2U) t(n1+n2 –2). U*.1 + U*.2 = Y.T - Y.R, w = [(1/n1) + (1/n2)]/4 S2U = S2TT - 2S2TR + 2S2RR.
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Methods for Average Bioavailability
S2RR = [1/(n1+n2-2)][(Yi11- Y.11)2 + (Yi22- Y.22)2] S2TT = [1/(n1+n2-2)][(Yi21- Y.21)2 + (Yi12- Y.12)2] SSTR = [1/(n1+n2-2)][(Yi11- Y.11)(Yi21 - Y.21) + (Yi12- Y.12)(Yi22 - Y.22)]
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Methods for Average Bioavailability
T = (Y.T - Y.R.)/sqrt[w(S2TT - 2STR + 2S2RR)] A (1-2)100% CI for is the set that {| T2 < t2(, n1+n2 –2)}. To solve the following quadratic equation (Y.T - Y.R.)2 - t2(,n1+n2 –2)[w(S2TT - 2STR + 2S2RR)] Conditions for the limits are positive real numbers: Y.R/sqrt(wS2RR) > t(,n1+n2 –2) and Y. T/sqrt(wS2TT) > t(,n1+n2 –2).
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Methods for Average Bioavailability
Example 4.3.2: Y.R/sqrt(wS2RR) = > t(0.05, 22) = 1.717 Y. T/sqrt(wS2TT) = > t(0.05, 22) = 1.717 90% CI for is given as (89.78%, %)
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4.4 Log-transformation The distributions of PK measures such as AUC and Cmax are skewed. FDA 2003 guidance suggest that statistical evaluation for BE should be performed based on the log-transformation of AUC and Cmax.
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Log-transformation The multiplicative (log-transformed) model Xijk = ’S’ikP’jF’(j,k)C’(j-1,k)e’ijk or Yijk = ln(Xijk) = +Sik+Pj+F(j,k)+C(j-1,k)+eijk Xijk = exp( + Sik + Pj + F(j,k) + C(j-1,k) + eijk)
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Log-transformation (Xi1k, Xi2k) follows a bivariate lognormal distn.
Sequence-by-period means and medians in log-transformed model Seq Period I Period II 1 Mean exp[(+P1+FR)+(R2+S2)/2] exp[(+P2+FT)+(T2+S2)/2] Median exp(+P1+FR) exp(+P2+FT) 2 Mean exp[(+P1+FT)+(T2+S2)/2] exp[(+P2+FR)+(R2+S2)/2] Median exp(+P1+FT) exp(+P2+FR)
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Log-transformation BE measures 1 Ratio of Medians = ’T/’R = (’ + F’T)/(’ + F’R) = exp[( + FT)/( + FR)] = exp[(FT - FR)] = exp(F) 2. Ratio of Means M = exp[F +(T2-R2)/2].
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Log-transformation Ho: ’T/’R L or ’T/’R U vs. Ha: L < ’T/’R < U Ho: ln(’T) – ln(’R) ln(L) or ln(’T)-ln(’R) ln(U) vs. Ha: ln(L) < ln(’T) - ln(’R) < ln(U) Ho: T - R L or T - R L vs. Ha: L < T - R < U L and U are known nonrandom constants, i.e., ± for 80/125.
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Log-transformation The Confidence interval approach and Schuirmann’s TOST can be directly applied to the log-transformed data for assessment of ABE. The period difference on the log-scale is the period ratio on the original scale dik = (Yi2k – Yi1k)/2 = ln (Xi2k/Xi1k)/2 = ln(rik)/2.
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Log-transformation f = d.1 – d.2 = Y.T - Y.R
f = d.1 – d.2 = Y.T - Y.R The MLE under the normality assumption for the log-transformed data is given as f’ = exp(f) = exp(d.1 – d.2) = exp(Y.T - Y.R)
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Log-transformation Let Rk be the geometric mean of period ratios obtained from sequence k, k =1,2. f’ = (R1/R2)1/2 f’ follows an univariate log-normal distribution with mean exp(md2/2). f’is biased for The (1-2)100% CI for is given as [exp(L1), exp(U1)]
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Log-transformation Under 80/125 rule, ABE is concluded if exp(L1) > 0.8 and exp(U1) < 1.25, or L1 > and U1 < Reasons of selection of 80% and 125% as ABE limits 1. Symmetric about 0 on log-scale. 2. Maximal power occurs when ratio is Maximal power for 80/120 limit occurs at 0.98.
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Log-transformation The MVUE for is give as f’MVUE = f’(-mSSD), where SSD is the pooled SS of period differences on the log-transformed data, is df, (-mSSD)={(/2)/[(/2+j)j!}[(-m/4)SSD]j and (.) is gamma function. E[(cSSD)] = exp[(c/2)d2] E{[(cSSD)]2} = exp[cd2](c d4)
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Log-transformation Theorem Bias(f’) = [exp(md2/2) –1]. MSE(f’) = 2[exp(md2/2) –1]2 + 2exp(md2/2)[exp(md2/2) –1] V(f’MVUE) = 2{exp(md2/2)[(md2)2] – 1} v(f’MVUE) = exp(2f){[(-mSSD)]2 - (-4mSSD)}
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Log-transformation Example Data: p181 of Chow and Liu (2008)
ANOVA Table based on log-transformed data SS df SS MS F p-value Intersubject Carryover Residuals Intrasubject Formulation Period l Residual
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Log-transformation Y.T = , Y.R= , f = SSD = 2.472, sd2 = (L1, U1) = ( , ) f’ = exp( ) = [exp( ), exp( )] = (0.5145, ) Bias (f’) = , MSE(f’) = = f’MVUE = (0.7110)(0.9831) = v(f’) = v(f’MVUE) = [( – ] = Eff(f’MVUE, f’) = / = %
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本作品轉載自Microsoft Office 2010 PowerPoint 設計主題範本-Blends,依據Microsoft 服務合約及著作權法第46、52、65條合理使用。 3-4 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.77。本作品依據著作權法第 46、52、65 條合理使用。 5-6 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.78。本作品依據著作權法第 46、52、65 條合理使用。 8 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.79。本作品依據著作權法第 46、52、65 條合理使用。 9 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.80。本作品依據著作權法第 46、52、65 條合理使用。
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版權聲明 頁碼 作品 版權圖示 來源/作者 51-52 53-54 55-56 57-58 59-60
《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.186。本作品依據著作權法第 46、52、65 條合理使用。 53-54 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.188。本作品依據著作權法第 46、52、65 條合理使用。 55-56 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.189。本作品依據著作權法第 46、52、65 條合理使用。 57-58 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.190。本作品依據著作權法第 46、52、65 條合理使用。 59-60 《Design and Analysis of Bioavailability and Bioequivalence》, 作者:Chow, SC, Liu, JP ,出版社: Chapman & Hall/ CRC (third edition),p.203。本作品依據著作權法第 46、52、65 條合理使用。
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