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5.6 Complex Numbers
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Complex number: a + bi where a is the real number part and bi is the imaginary number part
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imaginary number (i)
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Ex 1
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Ex 2 Write in a + bi form
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Ex 3 Find the additive inverse of -7 – 9i
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Ex 4 (6 – 2i) + (-5 + i) (3 + 6i) – (4 – 8i)
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Ex 5 (3i)(8i) (3i)(-5 + 2i) (4 + 3i)(-1 – 2i)
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MEMORIZE!!!!!!!!!!
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Simplify i47
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Solve: 9x2 + 54 = 0 Factor: x2 + 81 Factor: 2x2 + 32
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(a + bi) and (a – bi) are called complex conjugates
The product of complex conjugates is a REAL number. (2 + 3i)(2 – 3i) Why can you not have ‘i’ in the denominator of a fraction?
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Simplify:
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Think: Explain the difference between the additive inverse of a complex number and a complex conjugate.
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