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Published byTodd Knight Modified over 6 years ago
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Ex. Factor a) x2 + 5x + 6 b) x2 + 3x – 40 c) 5x2 – 17x + 6 d) 9x2 – 25
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Quadratic Equations Ex. Solve 2x2 + 9x + 7 = 3 2 2
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Ex. Solve 6x2 – 3x = 0 3 3
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Ex. Solve (x – 3)2 = 7 4 4
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Ex. Solve x2 + 2x – 6 = 0 by completing the square
“Completing the Square” means making the equation look like (x + b)2 = c Ex. Solve x2 + 2x – 6 = 0 by completing the square 5 5
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Ex. Solve 3x2 – 4x – 5 = 0 by completing the square
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Thm. The Quadratic Formula The solutions to ax2 + bx + c = 0 are
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Ex. Solve x2 + 3x = 9 8 8
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Ex. The number of internet users in the US can be modeled by the equation
I = t t where t is years since Using this model, find the year when the number of users will surpass 180. 9 9
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Practice Problems Section 1.4 Problems 9, 29, 37, 39, 75, 109, 123 10
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Complex Numbers You learned that we can’t take the square root of a negative number. Guess again… The solution to x2 + 1 = 0 is x = , which we define as “ i ”. 4 is called a real number 5i is called an imaginary number 4 + 5i is called a complex number 11 11
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When adding, combine like terms. Ex. (4 + 7i) + (1 – 6i)
Ex. (3 + 2i) + (4 – 5i) – (7 + i) 12
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Ex. (2 – i)(4 + 3i) Ex. (3 + 2i)(3 – 2i) Ex. (3 + 2i)2 14
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Def. a + bi and a – bi are complex conjugates.
3 + 2i and 3 – 2i are complex conjugates because their product was a real number. Def. a + bi and a – bi are complex conjugates. When you have a fraction that involves complex number, it is not OK to have any complex numbers on the bottom. We can use the complex conjugate to “rationalize” the fraction. 15
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Ex. Simplify 16
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We should express square roots of negative numbers as complex numbers.
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Ex. Solve 3x2 – 2x + 5 = 0 18
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Practice Problems Section 1.5 Problems 17, 27, 37, 49, 59, 65 19
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