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Chapter 3 Hubs, Bridges and Switches
Lecture 3
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Interconnecting LANs Q: Why not just one big LAN?
Limited amount of supportable traffic: on single LAN, all stations must share bandwidth Ethernet: limited length: specifies maximum cable length Ethernet: large “collision domain” (can collide with many stations) collision domain: set of stations such that simultaneous transmission of any two of them will generate a collision Token Ring: token passing delay per station: limits number of stations per LAN: Lecture 3
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Hubs Physical Layer devices: essentially multi-leg repeaters operating at bit levels: repeat bits received on one interface to all other interfaces Hubs can be arranged in a hierarchy (or multi-tier design), with backbone hub at its top Lecture 3
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Hubs (more) Each connected LAN referred to as LAN segment
Hubs do not isolate collision domains: node may collide with any node residing at any segment in LAN Hub Advantages: simple, inexpensive device Multi-tier provides graceful degradation: portions of the LAN continue to operate if one hub malfunctions extends maximum distance between node pairs (100m per Hub) Lecture 3
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Hub limitations single collision domain results in no increase in max throughput multi-tier throughput capacity same as single segment throughput individual LAN restrictions pose limits on number of nodes in same collision domain and on total allowed geographical coverage cannot connect different Ethernet types (e.g., 10BaseT and 100baseT) Qn: Why? Lecture 3
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Bridges Link Layer devices: forward Ethernet frames selectively:
learn where each station is located examine the header of each frame forward on the proper link (if known) if dest. and source on same link, drop frame WHY? if not known where dest. is, broadcast frame except on originating link, of course also called Layer 2 switches Lecture 3
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Bridges Bridge isolates collision domains
buffers frame then forwards it, if needed, using CSMA/CD A broadcast frame is forwarded on all interfaces (except the incoming one) thus broadcast frames propagate across bridges A set of segments connected by bridges and hubs is called a broadcast domain Lecture 3
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Bridges (more) Bridge advantages:
Isolates collision domains resulting in higher total throughput capacity, and does not limit the number of nodes nor geographical coverage Can connect different type Ethernet since it is a store and forward device (e.g. 10 & 100BaseT) Transparent: no need for any change to hosts LAN adapters (invisible to them) Lecture 3
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Backbone Bridge Lecture 3
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Interconnection Without Backbone
Not recommended for two reasons: - single point of failure at Computer Science hub - all traffic between EE and SE must path over CS segment Lecture 3
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Bridges: frame filtering, forwarding
bridges filter packets same-LAN -segment frames not forwarded onto other LAN segments forwarding: how to know on which LAN segment to forward frame? Lecture 3
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Bridge Filtering bridges learn which hosts can be reached through which interfaces: maintain filtering tables when frame received, bridge “learns” location of sender: incoming LAN segment records sender location in filtering table filtering table entry: (Node MAC Address, Bridge Interface, Time Stamp) stale entries in Filtering Table dropped (TTL can be 60 minutes) Lecture 3
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Bridge Operation pseudocode
Init: set filtering table to void Case: frame arrives on port P, src MAC , dest MAC /* Table Update stage */ if not listed, or mapped to port not equal P then add mapping P with expiration time else update expiration time /* if listing fits */ /* Frame Forwarding stage */ look up in filtering table: listing “ Q” /* if listed */ if not listed, forward on all ports except P /* “flood */ else,if Q= P , drop the frame /* WHY ? */ otherwise, forward the frame on port Q only Lecture 3
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Bridge Learning: example
Suppose C sends frame to D and D replies back with frame to C C sends frame, bridge has no info about D, so floods to both LANs 2 and 3 bridge notes that C is on port 1 frame ignored on upper LAN frame received by D Lecture 3
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Bridge Learning: example
C D generates reply to C, sends it bridge sees frame from D bridge notes that D is on interface 2 bridge knows C on interface 1, so selectively forwards frame out via interface 1 only Lecture 3
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What will happen with loops? Incorrect learning
Frame sent from A to B A B 1 2 A , 1 Problems: (1) frame loops infinitely (2) unstable filtering tables Lecture 3
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Loop-free: tree C B A message from A will mark A’s location A
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Loop-free: tree C B A: A message from A will mark A’s location A
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Loop-free: tree A: C B A: A message from A will mark A’s location
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Loop-free: tree A: A: A: C B A: A:
A message from A will mark A’s location A Lecture 3
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Loop-free: tree A: A: A: C B A: A:
A message from A will mark A’s location A Lecture 3
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Loop-free: tree A: A: A: C B A: A:
A message from A will mark A’s location So a message to A will go by marks… A Lecture 3
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Bridges-Spanning Tree
for increased reliability, it is desirable to have redundant, alternative paths from source to dest this causes cycles - bridges may multiply and forward frame forever solution: organize bridges in a spanning tree and disable all ports not belonging to the tree Disabled Lecture 3
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Introducing Spanning Tree
Objective: Find tree spanning all LAN segments each bridge transmits on a single port each LAN transmits on a single bridge Bridges run the Spanning Tree Protocol Use a distributed algorithm Objective: select what ports should actively forward frames, and which ports should accept frames Bridges communicate using special configuration messages (BPDUs) to perform this selection BPDU = Bridge Protocol Data Unit STP standardized in IEEE 802.1D Lecture 3
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Method Each bridge sends periodically a BPDU to all its neighbors
BPDU contains: ID of bridge the sender views as root (my_root_ID) known distance to that root senders own bridge ID port ID of the port from which BPDU sent Lecture 3
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Introductory STP In order to help understanding STP we first present it as 3 separate algorithms How to agree on a root bridge? How to compute a ST for bridges? How to compute a ST for LAN segments? Actual STP does all 3 functions in the same iterative process Note: we assume throughout that the network is connected Lecture 3
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1. Choosing a root bridge Assume
each bridge has a unique identifier (ID) within a bridge each port has a unique ID Each bridge remembers smallest bridge ID seen so far (= my_root_ID) including own ID Periodically, send my_root_ID to all neighbors (“flooding”) (included in BPDU) When receiving ID, update if necessary Qn: Is that enough for universal agreement? Lecture 3
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2. Compute ST given a root Idea: each bridge finds its shortest path to the root generate shortest paths tree Output: At each node, parent pointer and distance to root (parent=bridge leading to root along shortest path) Spanning tree T: A link belongs to T iff it connects some bridge to its parent Qn: Does this idea fully specify an algorithm producing a spanning tree? How: Bellman-Ford algorithm Lecture 3
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Distributed Bellman-Ford
Assumption: There is a unique root node s this was done in Step 1 Idea: Each node, periodically, tells all its neighbors what is its distance from s But how can they tell? s: easy. dists = 0 always! Another node v: Bridge calls the neighbor with least distance to root - its “parent” If bridges tie: choose bridge with lowest ID Lecture 3
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Why does this work? Suppose all nodes start with distance , and suppose that updates are sent every time unit. 2 1 ID=3 E ID=21 1 1 D C 1 ID=17 A 1 2 G ID=7 3 B 1 F Means: BPDU Means: link admitted to bridge spanning tree B sees same distance from A and E; A chosen since has smaller ID Lecture 3
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Bellman-Ford: properties
Works for any positive link weights w(u,v): Works also when the system operates asynchronously. Works regardless of the initial distances Lecture 3
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Actual STP What is missing so far?:
Can’t discard redundant links, since we need to connect host, not just bridges Instead can disable redundant bridge ports leading to them Graph model too simple, since there can be many bridges on one LAN (see next slide) We need to look at forwarding paths and not just graph paths STP protocol does all the “steps” together: Selection of root bridge Evaluation of distance to root and parent bridge Selection of the active ports and blocked ports Lecture 3
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Example of a network L6 L2 L5 B A D C E L1 L3 F L7 L4
Note: LAN L2 connects three bridges, 4 ports Lecture 3
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STP plan Objective: prune given network to render a forwarding tree, i.e: between any two hosts there is a single forwarding path through the network, no loops possible Method: Classify all ports into three types: Root ports: one for each bridge Designated ports: one for each LAN All other ports are blocked Root and designated ports transfer data frames in both directions. Blocked ports don’t transfer data Lecture 3
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BPDU’s (1) Each bridge sends BPDUs on all its ports.
Based on received BPDUs, bridge determines: determines Root finds own distance/cost to root classifies of own ports: root/designated/blocked The BPDU contains bridge’s current view of: the root bridge of the network own distance to this root own ID number the sending port’s ID number Lecture 3
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BPDUs (2) A BPDU is computed by a bridge for each of its ports and sent out on that port it will reach all ports attached to port’s LAN STP prerequisites each bridge is given a bridge ID number The ID number is unique in the network Each port is given a port ID number The port ID is unique within its bridge ID numbers assigned manually or automatically Each link (LAN) has a positive cost Lecture 3
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BPDU Processing in a bridge (1)
Determine current view of root: this is lowest root ID received, including own bridge ID. Only BPDUs reporting this root are considered in sequel Compare all reported distances to root. own distance to root= lowest received distance + + cost of the link to the reporting bridge Lecture 3
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Designated Ports all BPDUs received on a port are compared, including own message sent on it; the best message has: smallest root ID and smallest distance to that root if tied, choose the one with lowest bridge ID if tied, choose lowest port ID Qn: When does the last tie happen? If the message sent by the bridge on that port is best, label it a designated port there is exactly one designated port on each LAN Lecture 3
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Root Ports now compare the best messages received on all the ports of the bridge, according to the same criteria as above the port on which best message was received is labeled root port root bridge has no root port there is exactly one root port per bridge only root and designated ports receive and send data. BPDU’s are sent periodically even after convergence of algorithm indicate bridge is active / discover failures Lecture 3
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Summary after convergence: all bridges agree which bridge is the root
each LAN has exactly one designated port frames from LAN enter the bridge on that port on the way to root (upstream) frames coming from root exit the bridge on that port on the way to remote LANs (downstream) all bridges on LAN agree who is the designated port a LAN may have any ≥ 0 number of root ports on it each bridge has exactly one root port the port leads through a LAN to the parent bridge this is the next bridge on a shortest path to root a bridge may have any ≥ 0 number of designated ports a bridge with no designated ports blocks also the root port, and so becomes inactive Lecture 3
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Notes only bridges make decisions, LANs are passive
More discussion of the validity of STP will be given in homework and recitation Lecture 3
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Example Spanning Tree Protocol operation: B8 Pick a root
Each bridge picks a root port B8 B3 B5 B7 B2 B1 B6 B4 Lecture 3
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Example Spanning Tree Spanning Tree: Root B8 B3 B5 B7 B2 B1 B6
port Spanning Tree: B3 B5 B1 root port B7 B2 B2 B4 B5 B6 B7 B1 Root B3 B8 B6 B4 LANs not connecting bridges omitted here Lecture 3
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Spanning Tree Protocol: Execution
(B8,root=B8, dist=0) B8 B3 ignore msg B5 B7 B2 B1 (B1,root=B1,dist=0) (B1,root=B1, dist=0) B6 B4 WHY? (B4, root=B1, dist=1) (B6, Root=B1, dist=1) Lecture 3
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Bridges vs. Routers both are store-and-forward devices
routers: network layer devices (examine network layer headers) bridges are link layer devices routers have routing tables, use routing algorithms, designed for Wide Area addressing bridges have filtering tables, use filtering, learning & spanning tree algorithms, designed for local area Lecture 3
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Routers vs. Bridges Bridges + and -
+ bridge operation is simpler, requiring less processing - topologies are restricted with bridges: a spanning tree must be built to avoid cycles (with routers cycles are avoided by the Layer 3 routing algorithm) - bridges do not offer protection from broadcast storms (endless broadcasting by a faulty host will be forwarded by a bridge) Lecture 3
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Routers vs. Bridges Routers + and -
+ arbitrary topologies can be supported, cycling is limited by TTL counters (and good routing protocols) + provide barrier protection against broadcast storms - require IP address configuration (not plug and play) - require higher processing bridges do well in small (few hundred hosts) while routers used in large networks (thousands of hosts) and in Internet core Lecture 3
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Ethernet Switches = a powerful bridge
layer 2 (frame) forwarding, filtering using LAN addresses Switching: A-to-B and A’-to-B’ with no collisions large number of interfaces often: individual hosts, star-connected into switch Ethernet w. no collisions! = Switched Ethernet often: includes L3 function Lecture 3
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Ethernet Switches cut-through switching: frame forwarded from input to output port without awaiting for assembly of entire frame slight reduction in latency allow combinations of shared/dedicated, 10/100/1000 Mbps interfaces Lecture 3
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Ethernet Switches (more)
Dedicated Shared Lecture 3
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Data Link: Summary Chapter 5 Kurose and Ross
principles behind data link layer services: error detection, optional: error correction sharing a broadcast channel: multiple access link layer addressing, ARP various link layer technologies Ethernet hubs, bridges, switches (require STP) IEEE LANs PPP Chapter 5 Kurose and Ross Lecture 3
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Optional: Wireless LAN and PPP
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IEEE 802.11 Wireless LAN wireless LANs: mobile networking
IEEE standard: MAC protocol unlicensed frequency spectrum: 900Mhz, 2.4Ghz Basic Service Set (BSS) (a.k.a. “cell”) contains: wireless hosts access point (AP): base station BSS’s combined to form distribution system (DS) Lecture 3
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Ad Hoc Networks Ad hoc network: IEEE stations can dynamically form network without AP Applications: “laptop” meeting in conference room, car interconnection of “personal” devices battlefield IETF MANET (Mobile Ad hoc Networks) working group Lecture 3
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IEEE 802.11 MAC Protocol: CSMA/CA
CSMA: sender - if sense channel idle for DIFS sec. then transmit entire frame (no collision detection) -if sense channel busy then binary backoff CSMA receiver: if received OK return ACK after SIFS Why Needed? Sifs= Short Interframe Space DIFS = DCF Interframe Space DCF = Distributed Coordination Function (requires listening before sending) Lecture 3
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IEEE 802.11 MAC Protocol 802.11 CSMA Protocol: others
NAV: Network Allocation Vector frame has transmission time field others (hearing data) defer access for NAV time units Lecture 3
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Hidden Terminal effect
hidden terminals: A, C cannot hear each other obstacles, signal attenuation collisions at B goal: avoid collisions at B CSMA/CA: CSMA with Collision Avoidance Lecture 3
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Collision Avoidance: RTS-CTS exchange
CSMA/CA: explicit channel reservation sender: send short RTS: Request To Send receiver: reply with short CTS: Clear To Send CTS reserves channel for sender, notifying (possibly hidden) stations avoid hidden station collisions Lecture 3
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Collision Avoidance: RTS-CTS exchange
RTS and CTS short: collisions less likely, of shorter duration end result similar to collision detection IEEE allows: CSMA CSMA/CA: reservations polling from AP Lecture 3
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Point to Point Data Link Control
one sender, one receiver, one link: easier than broadcast link: no Media Access Control no need for explicit MAC addressing e.g., dialup link, ISDN line popular point-to-point DLC protocols: PPP (point-to-point protocol) HDLC: High level data link control (Data link used to be considered “high layer” in protocol stack!) Lecture 3
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PPP Design Requirements [RFC 1557]
packet framing: encapsulation of network-layer datagram in data link frame carry network layer data of any network layer protocol (not just IP) at same time ability to demultiplex upwards bit transparency: must be able to carry any bit pattern in the data field error detection (no correction) connection livenes: detect, signal link failure to network layer network layer address negotiation: endpoint can learn/configure each other’s network address Lecture 3
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PPP non-requirements no error correction/recovery no flow control
out of order delivery OK no need to support multipoint links (e.g., polling) Error recovery, flow control, data re-ordering all relegated to Transport layer!!! Lecture 3
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PPP Data Frame (1) Flag: delimiter (framing)
Address: does nothing (only one option) Control: does nothing; in the future possible multiple control fields Protocol: upper layer protocol to which frame delivered (eg, PPP-LCP, PPP-NCP, IP, IPCP, etc) Lecture 3
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PPP Data Frame (2) info: upper layer data being carried
check: cyclic redundancy check (CRC) for error detection Lecture 3
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Byte Stuffing “data transparency” requirement: data field must be allowed to include flag pattern < > Q: is received < > data or flag? Byte Stuffing procedure Sender: adds (“stuffs”) extra < > byte before each < > or < > data byte Receiver: when receive discard the byte, Next byte is data, regardless of value Receive : flag byte Lecture 3
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Byte Stuffing flag byte pattern in data to send flag byte pattern plus
stuffed byte in transmitted data Lecture 3
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PPP Data Control Protocols
Before exchanging network-layer data, data link peers must PPP-LCP: configure PPP link (max. frame length, authentication) learn/configure network layer information for IP: carry IP Control Protocol (PPP-IPCP) msgs (protocol field: 8021) to configure/learn IP address Lecture 3
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EXTRA SLIDES Lecture 3
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Spanning Tree Concepts: Path Cost
A cost is associated with each segment = “weight” of the segment = cost associated with transmission on the LAN segment connected to the port bridge associates the weight with relevant port default segment weight is 1 Can be manually or automatically assigned Can be used to alter the path to the root bridge Path cost is the sum of the component segment weights Lecture 3
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Spanning Tree Concepts: Root Port
Each non-root bridge has a Root port: The port on the path towards the root bridge = parent pointer The root port is part of the lowest cost path towards the root bridge If port costs are equal on a bridge, the port leading to parent port with lowest ID becomes root port Finally if several ports lead to the same parent port, choose lowest own port ID Lecture 3
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ST Concepts: Designated Port
Each LAN has a single designated bridge all other bridges on LAN know which one it is all tfc of LAN towards root goes thru that bridge This is the bridge reporting minimum cost path to the root bridge for the LAN ties broken by choosing lowest ID Only designated & root ports remain active in a bridge. designated ports connect to downstream bridges/LANs root ports connect to upstream bridges/LANs (toward the tree root) Bridge with no designated port becomes inactive network objective: connecting hosts, bridges are a tool Lecture 3
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STP Requirements Each bridge has a unique identifier
A multicast address for bridges on a LAN A unique port identifier for all ports on all bridges Bridge id + port number Lecture 3
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Forwarding/Blocking State
Only root and designated ports are active for data forwarding Other ports are in the blocking state: no forwarding! If bridge has no designated port, no forwarding at all block root port too. All ports send BPDU messages including blocked ones some presentations don’t send BPDU on blocked ports To adjust to changes Lecture 3
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