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8.4 Areas of Regular Polygons
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Area of Regular Polygons
A regular polygon has equal sides and equal angles The radius of the polygon is the distance from the center to a vertex radius center
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Area of Regular Polygons
Drawing all of the radii will create several congruent, isosceles triangles.
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Area of Regular Polygons
The apothem is the perpendicular distance from the center to the midpoint of one of the sides. center apothem
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Area of Regular Polygons
An apothem bisects one of the angles created by two radii, creating another pair of congruent triangles radii apothem
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Apothems: All apothems of a regular polygon are congruent.
Only regular polygons have apothems. An apothem is a radius of a circle inscribed in the polygon. An apothem is the perpendicular bisector of a side. A radius of a regular polygon is a radius of a circle circumscribed about the polygon. A radius of a regular polygon bisects an angle of the polygon.
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Area of Regular Polygons
Example: Find the measure of each numbered angle m∠1= m∠2= m∠3= 360∕6 = 60° 60∕2 = 30° =60° 1 2 3
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Area of Regular Polygons
Example: Find the measure of each numbered angle 6 4 5 m∠4= m∠5= m∠6= 360∕8 = 45° 45∕2 = 22.5° =67.5°
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Area of Regular Polygons
Example: Find the measure of each numbered angle m∠7= m∠8= m∠9= 360∕5= 72° 72∕2 = 36° =54° 7 8 9
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Area of Regular Polygons
The area of a regular polygon equals one half the product of the apothem and the perimeter or Perimeter equals the side length times the number of sides: p = s*n A= ½ asn
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Area of Regular Polygons
Example: Find the area of the regular polygon 8 in 12.3 in
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Area of Regular Polygons
Example: Find the area of the regular polygon Use Pythagorean Theorem! 18 ft 23.5 ft 21.7 ft 9 ft
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Area of Regular Polygons
Example: Find the area of the regular polygon Use Pythagorean Theorem! 6.1 4.9 3.6 7.2
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Area of Regular Polygons
Example: Find the area of the regular polygon Use shortcut for triangle! 10 cm 30 10 5√3 60 5
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Area of Regular Polygons
Example: Find the area of the regular polygon Use shortcut for triangle! 60 4.5 15.6 m 30 7.8
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Team Challenge: A square is inscribed in an equilateral triangle as shown. Find the area of the shaded region.
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A (shaded) = ½ (12)(6√3) – [12(2 – √3)√3]2 = 1764√3 - 3024
2x + x√3 = 12 x = √3 x = 12(2 – √3) A (shaded) = ½ (12)(6√3) – [12(2 – √3)√3]2 = 1764√ x√3 x x√3 x
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