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Electronics The Thirteenth and Fourteenth Lecture
Tenth week 21- 24/ 2/ 1438 هـ أ / سمر السلمي
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Outline for today Chapter 3: Bipolar junction transistor
Finding minority carrier distributions & terminal currents in BJT First: the solution of diffusion equation in the base region in BJT Second: Evaluation Values of Terminal Currents in BJT minority carrier distributions for modes of operation for BJT for npn Chapter 4: Field Effect Transistor FET parts Types FET JFET junction field-effect transistor Structure What happens inside JFET Solving the third homework
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Time of Periodic Exams The third homework
The Second periodic exam in / 3 / 1438 هـ , Please everyone attend in her group The third homework I put the third homework in my website in the university homework Due Tuesday 22 / 2/ 1438 H in my mailbox in Faculty of Physics Department , I will not accept any homework after that , but if you could not come to university you should sent it to me by in the same day To improve your grads (optional) Look in the news in my website (
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Finding minority carrier distributions & terminal currents in BJT
we deal with active mode and base common configuration to npn . At the beginning and to make calculation ease, we assume the following : 1- the thickness of base WB is small, therefore, the diffusion here for electronic current from emitter to collector . In addition, we neglects drift current at base. 2- emitter efficiency γ ≈ 1 because emitter current is only electronic current 3- reverse leakage current or reverse saturation current is neglected 4- the action part in base and two junctions have regular section area and electronic current move in one direction or one dimension which is x 5- all currents and voltages are stable A VEB VCB WB xp n p ΔnE ΔnC
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First: the solution of diffusion equation in the base region in BJT
we deal with active mode and base common configuration to npn . Previously, we study about a excess of minority -carriers of electrons concentration in p-type in base region. Electronic current enter to base from emitter, also come out from base to collector. To calculate excess of electrons to two end-sides of base at two depletion regions from emitter side and collector side to obtain : excess of electrons concentration from end-side depletion regions of emitter end-side depletion regions of collector A VEB VCB WB xp n p ΔnE ΔnC
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First: the solution of diffusion equation in the base region in BJT
If we assume that emitter & base junction has strong forward bias which means and base & collector junction has strong reverse bias which means , we will obtain We mentioned before of minority carrier diffusion equations which is quadratic equation, hence the solution are Where Ln the diffusion length of minority carrier electron . We must remember that thickness of base is small which means that WB ≤ Ln to move all electronic current from emitter to collector. A VEB VCB WB xp n p ΔnE ΔnC
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First: the solution of diffusion equation in the base region in BJT
Finding constants C with boundary conditions at the two end-sides of base When multiply the first equation with , we obtain And collected with second equation to obtain C1 by substituting in the first equation to obtain C2
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First: the solution of diffusion equation in the base region in BJT
by substituting with constants C in we mentioned that high reverse voltage to obtain We can write equation in this from where
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First: the solution of diffusion equation in the base region in BJT
the figure shows the distribution of minority carriers in the base also in the emitter and collector where δn ΔnE M1ΔnE M2ΔnE
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Second: Evaluation Values of Terminal Currents in BJT
We will find current by known current density to two end-sides of base At driven excess of electron in base reign in p-type respect of xp This driven at borders of depletion region from emitter Therefore, electronic emitter current by substituting in constants since the So emitter current
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Second: Evaluation Values of Terminal Currents in BJT
This derivation at the borders of the depletion region from collector side Therefore, collector current is By substituting in constants
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Second: Evaluation Values of Terminal Currents in BJT
Finally, we can find base current from emitter and collector currents When taking into consideration , we obtain threse approximate value
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minority carrier distributions for modes of operation for BJT for npn
Active mode: the figure shows the distribution of minority carriers in the base also in the emitter and collector in active mode
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minority carrier distributions for modes of operation for BJT for npn
Saturation mode: the figure shows the distribution of minority carriers in the base also in the emitter and collector in saturation mode
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minority carrier distributions for modes of operation for BJT for npn
Cut - off mode the figure shows the distribution of minority carriers in the base also in the emitter and collector in cut off mode
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minority carrier distributions for modes of operation for BJT for npn
Inverted mode :the figure shows the distribution of minority carriers in the base also in the emitter and collector in inverted mode
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Field Effect Transistor
The field effect transistor uses electric field to control the conduction shape of channel for type extrinsic semiconductor either n-type or p-type . Therefore, it called n-channel or p-channel, respectively. Also, we will focus at majority carriers of channel. because of this, it called also unpolar junction transistor FET parts As any transistor, it has three parts. Their name are Source: a majority carrier enters from it which is the start point of channel. Drain : a majority carrier comes out from it which is the end point of channel Gates: the third part which controls of conduction of a majority carrier of channel which is above the channel
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Types FET famous types in field-effect transistor are
1- (JFET (junction field-effect transistor 2- (MESFET) metal–semiconductor field-effect transistor 3- (MISFET) metal– Insulator –semiconductor field-effect transistor 4- (MOSFET) metal–oxide–semiconductor field-effect transistor We will focus on the first type JFET and last type MOSFET in our study
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JFET junction field-effect transistor
JFET Structure As BJT structure, it distribute three extrinsic types of n-type & p-type in respectively way. Here the channel is in the center of 3 three types either n-channel or p-channel. Source (S) and Drain (D) are metal bars at start & end of the channel. Gates (G) is metal bar contact with other extrinsic type (which has more impurities than in channel),and places above and blow the channel. P+
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JFET junction field-effect transistor
What happens inside JFET (n-channel) We will focus at n-channel. At the beginning, we contact transistor with two voltage sources . One of them contacts with circle between source (S) and drain (D), the other contacts as voltage bias to gates (G). We must notice that source contacts with grounded. When we look at figure below, we notice that battery voltage VDS is the reason to current exit which come out from positive battery to negative battery in n-channel (which here is drain current direction ID ). therefore, the direction of electronic current (majority carrier in n-channel) invert ID direction and move from source to drain. However, applied voltage VGS at gates p+ and n-channel is reverse bias or reverse voltage. Thus, length of the depletion region between p+n and n p+ junctions is big which controls of moving electronic current which move from source S to drain D.
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JFET junction field-effect transistor
What happens inside JFET n-channel Notice that the depletion region between p+n and n p+ junctions depend on dimension x . the width of depletion region different in place x =0 from place x =L Where is wide in L duo to applied voltage change VD. The voltage at source is less than voltage at drain. Thus, it controls with the cross-section area of conduction n-channel and narrows from drain side. The depletion region works as side door or gate which open and close the channel.
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JFET junction field-effect transistor
What happens inside JFET n-channel Notice from below figure The depletion region cause closing gate in the drain. Therefore, there no electronic current get out, also drain current (real current in circuit) ID = 0 (correct to be constant). This condition is called saturated state to current. At the beginning of saturated state , we called pinch–off or pinch–off voltage Vp. Channel resistivity is constant duo to impurities constant. it controls with channel resistivity by change the cross-section area of it.
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Solving the third homework
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