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IGCSEFM Proof Dr J Frost Objectives: (from the specification)

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Presentation on theme: "IGCSEFM Proof Dr J Frost Objectives: (from the specification)"β€” Presentation transcript:

1 Dr J Frost (jfrost@tiffin.kingston.sch.uk)
IGCSEFM Proof Dr J Frost Objectives: (from the specification) Last modified: 22nd February 2016

2 Overview From GCSE, you should remember that a β€˜proof’ is a sequence of justified steps, sometimes used to prove a statement works in all possible cases. Algebraic Proofs Geometric Proofs β€œProve that the sum of three consecutive even numbers is a multiple of 6.” ? πŸπ’+ πŸπ’+𝟐 + πŸπ’+πŸ’ =πŸ”π’+πŸ” =πŸ”(𝒏+𝟏) which is a multiple of 6. Prove that 𝑦=π‘₯ Recall that the key at the end is to factorise out the 6. (We will need to recap some circle theorems)

3 Algebraic Proof ? ? Two common types of question:
Prove that the difference between the squares of two consecutive odd numbers is a multiple of 8. ? Let numbers be πŸπ’βˆ’πŸ and πŸπ’+𝟏. πŸπ’+𝟏 𝟐 βˆ’ πŸπ’βˆ’πŸ 𝟐 =πŸ’ 𝒏 𝟐 +πŸ’π’+πŸβˆ’ πŸ’ 𝒏 𝟐 βˆ’πŸ’π’+𝟏 =πŸ’ 𝒏 𝟐 +πŸ’π’+πŸβˆ’πŸ’ 𝒏 𝟐 +πŸ’π’βˆ’πŸ =πŸ–π’ which is divisible by 8. We could have also used 2𝑛+1 and 2𝑛+3. Prove that π‘₯ 2 βˆ’4π‘₯+7>0 for all π‘₯. ? 𝒙 𝟐 βˆ’πŸ’π’™+πŸ• = π’™βˆ’πŸ 𝟐 βˆ’πŸ’+πŸ• = π’™βˆ’πŸ 𝟐 +πŸ‘ Since π’™βˆ’πŸ 𝟐 β‰₯𝟎, thus π’™βˆ’πŸ 𝟐 +πŸ‘>𝟎 Bro Hint: We know that anything β€˜squared’ is at least 0. Could we perhaps complete the square?

4 Test Your Understanding
[Specimen2 Q12] 𝑛 is an integer. Prove that π‘›βˆ’2 2 +𝑛 8βˆ’π‘› is always a multiple of 4. 𝒏 𝟐 βˆ’πŸ’π’+πŸ’+πŸ–π’βˆ’ 𝒏 𝟐 =πŸ’π’+πŸ’ =πŸ’(𝒏+𝟏) [June 2013 P2 Q12] Prove that 5𝑛+3 π‘›βˆ’1 +𝑛(𝑛+2) is a multiple of 3 for all integer values of 𝑛. =πŸ“ 𝒏 𝟐 +πŸ‘π’βˆ’πŸ“π’βˆ’πŸ‘+ 𝒏 𝟐 +πŸπ’ =πŸ” 𝒏 𝟐 βˆ’πŸ‘ =πŸ‘ 𝟐 𝒏 𝟐 βˆ’πŸ [Jan 2013 P1 Q5] 𝑛 is a positive integer. Write down the next odd number after 2π‘›βˆ’ πŸπ’+𝟏 Prove that the product of two consecutive odd numbers is always one less than a multiple of 4. πŸπ’βˆ’πŸ πŸπ’+𝟏 =πŸ’ 𝒏 𝟐 βˆ’πŸ πŸ’ 𝒏 𝟐 is a multiple of 4. 1 4 Prove that for all values of π‘₯, π‘₯ 2 βˆ’6π‘₯+10>0 𝒙 𝟐 βˆ’πŸ”π’™+𝟏𝟎= π’™βˆ’πŸ‘ 𝟐 +𝟏 π’™βˆ’πŸ‘ 𝟐 β‰₯𝟎 thus π’™βˆ’πŸ‘ 𝟐 +𝟏>𝟎 [Set 4 P1 Q16] Prove that, for all values of π‘₯, 2 π‘₯ 2 βˆ’8π‘₯+9>0 𝟐 𝒙 𝟐 βˆ’πŸ’π’™+ πŸ— 𝟐 =𝟐 π’™βˆ’πŸ 𝟐 βˆ’πŸ’+ πŸ— 𝟐 =𝟐 π’™βˆ’πŸ 𝟐 + 𝟏 𝟐 =𝟐 π’™βˆ’πŸ 𝟐 +𝟏 π’™βˆ’πŸ 𝟐 β‰₯𝟎 therefore 𝟐 π’™βˆ’πŸ 𝟐 +𝟏>𝟎 ? ? 5 2 ? ? 3 ? ?

5 Identities π‘₯ is 2 or -2 π‘₯ 2 =4 π‘₯ 2 βˆ’π‘₯=π‘₯ π‘₯βˆ’1 π‘₯ could be anything! ? ? ?
What values of π‘₯ make the following equality hold true? π‘₯ 2 =4 π‘₯ is 2 or -2 ? π‘₯ 2 βˆ’π‘₯=π‘₯ π‘₯βˆ’1 π‘₯ could be anything! ? ! The identity 𝑓(π‘₯)≑𝑔(π‘₯) means that 𝑓 π‘₯ =𝑔(π‘₯) for all values of π‘₯. e.g. π‘₯ 2 βˆ’π‘₯≑π‘₯ π‘₯βˆ’1 So π‘₯ 2 ≑4 would be wrong as it is not true when say π‘₯ is 1. When you have a quadratic/cubic/etc, all the coefficients must match to guarantee both sides of the identity are equal for all 𝒙. [Set 4 P1 Q2] In this identity, β„Ž and π‘˜ are integer constants. 4 β„Žπ‘₯βˆ’1 βˆ’3 π‘₯+β„Ž =5 π‘₯+π‘˜ Work out the values of β„Ž and π‘˜ πŸ’π’‰π’™βˆ’πŸ’βˆ’πŸ‘π’™βˆ’πŸ‘π’‰=πŸ“π’™+πŸ“π’Œ Comparing 𝒙 terms: πŸ’π’‰βˆ’πŸ‘=πŸ“ β†’ 𝒉=𝟐 Comparing constant terms: βˆ’πŸ’βˆ’πŸ‘π’‰=πŸ“π’Œ β†’ π’Œ=βˆ’πŸ ?

6 Test Your Understanding
[Set 3 P1 Q2] 5 3π‘₯βˆ’2 βˆ’3 π‘₯βˆ’β„Ž ≑4(π‘˜π‘₯+2) Work out the values of β„Ž and π‘˜. ? πŸπŸ“π’™βˆ’πŸπŸŽβˆ’πŸ‘π’™+πŸ‘π’‰β‰‘πŸ’π’Œπ’™+πŸ– πŸπŸπ’™βˆ’πŸπŸŽ+πŸ‘π’‰=πŸ’π’Œπ’™+πŸ– Comparing 𝒙 terms: 𝟏𝟐=πŸ’π’Œ β†’ π’Œ=πŸ‘ Comparing constant terms: βˆ’πŸπŸŽ+πŸ‘π’‰=πŸ– β†’ 𝒉=πŸ”

7 AQA Worksheet (Algebraic Proof)
BONUS QUESTIONS: Prove algebraically that the sum of two consecutive odd numbers is divisible by 4. πŸπ’βˆ’πŸ + πŸπ’+𝟏 =πŸ’π’ which is divisible by 4. Prove that the difference between two consecutive cubes is one more than a multiple of 6. 𝒏+𝟏 πŸ‘ βˆ’ 𝒏 πŸ‘ = 𝒏 πŸ‘ +πŸ‘ 𝒏 𝟐 +πŸ‘π’+πŸβˆ’ 𝒏 πŸ‘ =πŸ‘ 𝒏 𝟐 +πŸ‘π’+𝟏 =πŸ‘π’ 𝒏+𝟏 +𝟏 The product of two consecutive integers is even, thus πŸ‘π’(𝒏+𝟏) is divisible by 6. 1 3 ? ? [GCSE] I think of two consecutive integers. Prove that the difference of the squares of these integers is equal to the sum of the two integers. Two numbers are: 𝒙 and 𝒙+𝟏 Difference of squares: 𝒙+𝟏 𝟐 βˆ’ 𝒙 𝟐 =πŸπ’™+𝟏 Sum of numbers: 𝒙+ 𝒙+𝟏 =πŸπ’™+𝟏 These are equal. 2 ? Prove that the product of four consecutive numbers is one less than a square number. 𝒂 𝒂+𝟏 𝒂+𝟐 𝒂+πŸ‘ = 𝒂 𝟐 +𝒂 𝒂 𝟐 +πŸ“π’‚+πŸ” = 𝒂 πŸ’ +πŸ” 𝒂 πŸ‘ +𝟏𝟏 𝒂 𝟐 +πŸ”π’‚+𝟏 = 𝒂 𝟐 +πŸ‘π’‚+𝟏 𝟐 4 ?

8 Geometric Proof A recap of general angle theorems and Circle Theorems: ? Alternate angles are equal. Corresponding angles are equal. (Sometimes known as β€˜F’ angles) ? π‘Ž π‘Ž+𝑏=180Β° 𝑏 ? Vertically opposite angles are equal. Cointerior angles sum to πŸπŸ–πŸŽΒ°. ?

9 RECAP :: Circle Theorems
? Angle between radius and tangent is 90Β°. ? Angle in semicircle is 90Β° ? Angles in same segment are equal. Angle at centre is twice angle at circumference. ? Opposite angles of cyclic quadrilateral are equal. ? ? Tangents from a point to a circle are equal in length. ? Alternate Segment Theorem.

10 Form of a Geometric Proof
Set 1 Paper 1 Q8 ! Write statements in the form: ∠𝐴𝐡𝐢=π‘£π‘Žπ‘™π‘’π‘’ (π‘Ÿπ‘’π‘Žπ‘ π‘œπ‘›) βˆ π‘‚πΆπ΅=π‘₯ (base angles of isosceles triangle are equal) βˆ π΅π‘‚πΆ=2π‘₯ (angle at centre is double angle at circumference) Angles in Δ𝑂𝐡𝐢 add to 180Β° ∴ π‘₯+π‘₯+2π‘₯=180 4π‘₯=180 π‘₯=45 βˆ π΅π‘‚πΆ=2π‘₯=90Β° ? ? ?

11 Test Your Understanding
Triangle 𝐴𝐡𝐢 is isosceles with 𝐴𝐢=𝐡𝐢. Triangle 𝐢𝐷𝐸 is isosceles with 𝐢𝐷=𝐢𝐸. 𝐴𝐢𝐷 and 𝐷𝐸𝐹 are straight lines. Prove that angle 𝐷𝐢𝐸=2π‘₯ ∠π‘ͺ𝑩𝑨=𝒙 (base angles of isosceles triangle are equal) βˆ π‘¨π‘ͺ𝑩=πŸπŸ–πŸŽβˆ’πŸπ’™ (angles in πš«π‘¨π‘©π‘ͺ add to 180) βˆ π‘«π‘ͺ𝑬=πŸπ’™ (angles on straight line add to 180) Prove that 𝐷𝐹 is perpendicular to 𝐴𝐡. βˆ π‘«π‘¬π‘ͺ= πŸπŸ–πŸŽβˆ’πŸπ’™ 𝟐 =πŸ—πŸŽβˆ’π’™ (base angles of isosceles triangle are equal) βˆ π‘«π‘­π‘¨=πŸπŸ–πŸŽβˆ’ πŸ—πŸŽβˆ’π’™ βˆ’π’™=πŸ—πŸŽΒ° βˆ΄π‘«π‘­ is perpendicular to 𝑨𝑩. ? ?

12 Last Step What do you think we would be the last step in your proof in each of these cases? 𝐷 Prove that 𝐴𝐡𝐢 is a straight line. … βˆ π‘¨π‘©π‘«+βˆ π‘«π‘©π‘ͺ=πŸπŸ–πŸŽ therefore 𝑨𝑩π‘ͺ is a straight line. 𝐢 ? Bro Tip: It’s a good idea to finish by stating the thing you’re trying to prove. 𝐡 𝐴 𝐡 Prove that the line 𝐴𝐢 bisects ∠𝐡𝐴𝐷. … βˆ π‘©π‘¨π‘ͺ=∠π‘ͺ𝑨𝑫 therefore 𝑨π‘ͺ bisects βˆ π‘©π‘¨π‘«. 𝐢 ? 𝐴 𝐷 𝐡 Prove that triangle 𝐴𝐡𝐢 is isosceles. … βˆ π‘©π‘¨π‘ͺ=βˆ π‘¨π‘ͺ𝑩 therefore πš«π€ππ‚ is isosceles. ? 𝐴 𝐢

13 Exercises ? Question 1 [Set 4 Paper 1 Q4]
𝐴𝐡𝐢 is a right-angled triangle. Angle 𝐴𝐢𝐡=π‘₯. Angle 𝐡𝐴𝐷=90βˆ’2π‘₯. Prove that 𝐴𝐢𝐷 is an isosceles triangle. ?

14 Question 2 𝐴𝐡𝐢𝐷 is a quadrilateral. Prove that π‘₯=𝑦. ?

15 Question 3 𝐴𝐡 is parallel to 𝐢𝐷. Is 𝑃𝑄 parallel to 𝑆𝑅? You must show your working. ?

16 Question 4 ? 𝑃𝑄𝑅𝑆 is a cyclic quadrilateral. 𝑄𝑆=𝑄𝑅. 𝑉𝑆𝑇 is a tangent to the circle. Work out the value of π‘₯. You must show your working.

17 Question 5 𝐴, 𝐡, 𝐢 and 𝐷 are points on the circumference of a circle such that 𝐡𝐷 is parallel to the tangent to the circle at 𝐴. Prove that 𝐴𝐢 bisects angle 𝐡𝐢𝐷. Give reasons at each stage of your working. ?

18 Question 6 Prove that 𝐴𝐡 is parallel to 𝐷𝐢. ?

19 Question 7 𝐴𝐡𝐢 is a triangle. 𝑃 is a point on 𝐴𝐡 such that 𝐴𝑃=𝑃𝐢=𝐡𝐢. Angle 𝐡𝐴𝐢=π‘₯. Prove that angle 𝐴𝐡𝐢=2π‘₯. You are also given that 𝐴𝐡=𝐴𝐢. Work out the value of π‘₯. ?


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