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Percent Composition & Empirical and Molecular Formulas

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Presentation on theme: "Percent Composition & Empirical and Molecular Formulas"— Presentation transcript:

1 Percent Composition & Empirical and Molecular Formulas

2 Percent Composition Gives the percent, by mass, of each element in a compound. 1st – Determine the mass of each element. If there are more than one atom of the element in the compound, be sure to multiply by the number of atoms. 2nd – Calculate the sum of all the masses of the elements to find the molar mass of the compound. 3rd – Determine the percent by mass of each element by taking their total mass, divided by the molar mass, and multiplying by 100.

3 Examples H2O %H - %O - C6H12O6 %C – %H – %O –

4 Try this one on your own Calculate the percent composition of aspartame, C14H18N2O5.

5 Empirical Formula Gives the lowest whole-number ratio of the atoms of the elements in a compound. This may, or may not, be the same as the molecular formula. Hydrogen Peroxide Molecular Formula – H2O2 Empirical Formula – HO Glucose Molecular Formula – C6H12O6 Empirical Formula – CH2O Tetranitrogen decoxide Molecular Formula – N4O10 Empirical Formula – N2O5

6 Calculating Empirical Formulas
Step 1 – Treat compound as 100g. This will make all percentages become grams. Step 2 – Convert each mass to moles. Step 3 – Divide each of the moles by the smallest number. Step 4 – If this creates a fraction of a mole, for any element, multiply all moles by a number to convert this to a whole number. Ex. If you get N – 1 and O – 2.5 Multiply by 2, and get N – 2, and O – 5.

7 Example Determine the empirical formula of a molecule containing the following percent composition. 65.5% C 5.5% H 29.0% O If the molar mass of the compound is 110 g/mol, what is the molecular formula?

8 Example Determine the empirical formula of a molecule containing the following percent composition. 18.7% Li 16.3% C 65% O If the molar mass of the compound is 73.8 g/mol, what is the molecular formula?


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