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IGCSE Completing the Square
Dr J Frost Objectives: (from the specification) Last modified: 22nd August 2015
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RECAP π₯ 2 β4π₯=π πβπ π₯ 2 β3π₯β40= π+π πβπ π₯ 2 β9= π+π πβπ 2 π₯ 2 βπ₯β6=(ππ+π)(πβπ) ? ? ? ?
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What makes this topic Further Maths-ey?
Youβre used to expressing for example π₯ 2 +4π₯β3 in the form π₯+2 2 β7 But youβve (probably) never had to deal with the coefficient of π₯ 2 not being 1!
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Reminder ? π π₯ 2 +ππ₯+π π π₯+__ 2 +__ ?
What the devil is βcompleting the squareβ? ? π π₯ 2 +ππ₯+π π π₯+__ 2 +__ It means putting a quadratic expressions in the form on the right, i.e. where π₯ only appears once. Whatβs the point? ? It has four uses, the first two of which we will explore: Solving quadratic equations (including deriving the quadratic formula!). Sketching quadratic equations. Helps us to βintegrateβ certain expressions (an A Level topic!) Helps us do something called βLaplace Transformsβ (a university topic!)
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π₯ 2 β2π₯= π₯β1 2 β1 π₯ 2 β6π₯+4= π₯β3 2 β5 π₯ 2 +8π₯+1= π₯+4 2 β15
Recap of π₯+π 2 +π π₯ 2 β2π₯= π₯β1 2 β1 π₯ 2 β6π₯+4= π₯β3 2 β5 π₯ 2 +8π₯+1= π₯+4 2 β15 π₯ 2 +10π₯β3= π₯+5 2 β28 π₯ 2 +4π₯+3= π₯+2 2 β1 π₯ 2 β20π₯+150= π₯β ? ? ? ? ? ? Reminder of method: π₯ 2 β6π₯+4 = π₯β3 2 β9+4 = π₯β3 2 β5 π₯ 2 +8π₯+1= π₯+4 2 β16+1 = π₯+4 2 β15 Remember we halve the coefficient of π₯, then square it and βthrow it awayβ.
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π π₯ 2 +β¦ So far the coefficient of the π₯ 2 term has been 1. What if it isnβt? Express 3 π₯ 2 +12π₯β6 in the form π π₯+π 2 +π 3 π₯ 2 +12π₯β6 =3 π₯ 2 +4π₯β2 =3 π₯+2 2 β4β2 =3 π₯+2 2 β6 =3 π₯+2 2 β18 Just factorise out the coefficient of the π₯ 2 term. Now we have an expression just like before for which we can complete the square! ? ? Now expand out the outer brackets. To be sure about your answer you could always expand and check you get the original expr. ? Express 2β4π₯β2 π₯ 2 in the form πβπ π₯+π 2 β2 π₯ 2 β4π₯+2 =β2 π₯ 2 +2π₯β1 =β2 π₯+1 2 β1β1 =β2 π₯+1 2 β2 =β2 π₯ =4β2 π₯+1 2 ? Bro Tip: Reorder the terms so you always start with something in the form π π₯ 2 +ππ₯+π ? ? Bro Tip: Be jolly careful with your signs! Bro Tip: You were technically done on the previous line, but itβs nice to reorder the terms so itβs more explicitly in the requested form. ? ?
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One more example ? 2 π₯ 2 +6π₯+7=2 π₯ 2 +3π₯ =2 π₯ β =2 π₯ =2 π₯ ? ? ? This was the actual example on the specification!
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Test Your Understanding
Put the expression 3 π₯ 2 β12π₯+5 in the form π π₯+π 2 +π. ? =3 π₯ 2 β4π₯ =3 π₯β2 2 β =3 π₯β2 2 β =3 π₯β2 2 β7
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Proof of the Quadratic Formula!
by completing the squareβ¦ π π₯ 2 +ππ₯+π=0 π₯ 2 + π π π₯+ π π =0 π₯+ π 2π 2 β π 2 4 π 2 + π π =0 π₯+ π 2π ππβ π 2 4 π 2 =0 π₯+ π 2π 2 = π 2 β4ππ 4 π 2 π₯+ π 2π =Β± π 2 β4ππ 2π π₯= βπΒ± π 2 β4ππ 2π ? ? ? ? ? ?
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Exercises Express π₯ 2 β4π₯+5 in the form π₯βπ 2 +π: πβπ π +π Work out the values of π and π such that π₯ 2 β6π₯+5β‘ π₯+π 2 +π π=βπ, π=βπ [June 2013 Paper 1] Express 2 π₯ 2 β12π₯β7 in the form π π₯+π 2 +π. π πβπ π βππ 2 π₯ 2 β4π₯+5β‘π π₯+π 2 +π Work out the values of π, π, π π=π, π=βπ, π=π Express the following in the form π π₯+π 2 +π 2 π₯ 2 +16π₯=π π+π π βππ 5 π₯ 2 +20π₯β10=π π+π π βππ 9 π₯ 2 β18π₯+27=π πβπ π +ππ 3 π₯ 2 β6π₯+4=π πβπ π +π 4 π₯ 2 +16π₯β1=π π+π π βππ 1 6 Express the following in the form π π₯+π 2 +π: 3 π₯ 2 βπ₯=π πβ π π π β π ππ 4 π₯ 2 +π₯β1=π π+ π π π Express the following in the form πβπ π₯+π 2 : 3+6π₯β π₯ 2 =ππβ πβπ π 10β8π₯β π₯ 2 =ππβ π+π π 10π₯β8β5 π₯ 2 =βπβπ πβπ π 1β36π₯β6 π₯ 2 =ππβπ π+π π ? ? a 2 ? ? b 3 7 ? ? a 4 b ? c ? ? d ? 5 a ? b ? c ? d ? e ?
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