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Consider a beam of electrons with energy exactly 1 eV, flying exactly

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Presentation on theme: "Consider a beam of electrons with energy exactly 1 eV, flying exactly"— Presentation transcript:

1 Consider a beam of electrons with energy exactly 1 eV, flying exactly
in y-direction (i.e. no momentum in x-direction, px=0 and Dpx=0). You now measure the x-position of the electrons by placing an aperture with 5 nm width into the beam. What is the consequence? x y (A) I now know the x-position of the electrons within 5 nm The electrons continue straight on along the y-direction, just like before the measurement. (B) I now know the x-position of the electrons within 5 nm The electrons are deflected and acquire some momentum in x-direction, now flying faster than before. (C) I now know the x-position of the electrons within 5 nm The electrons are deflected and acquire some momentum in x-direction, slowing down accordingly w.r. to their momentum along y-direction.

2 Consider a beam of electrons with energy exactly 1 eV, flying exactly
in y-direction (i.e. no momentum in x-direction, px=0 and Dpx=0). You now measure the x-position of the electrons by placing an aperture with 5 nm width into the beam. What is the consequence? x (A) I now know the x-position of the electrons within 5 nm The electrons continue straight on along the y-direction, just like before the measurement. (B) I now know the x-position of the electrons within 5 nm The electrons are deflected and acquire some momentum in x-direction, now flying faster than before. (C) I now know the x-position of the electrons within 5 nm. The electrons are deflected and acquire some momentum in x-direction, slowing down accordingly w.r. to their momentum along y-direction. Before slit: Dpx = 0  we do not know the y-position of the electrons at all! Dx =  After slit: Dx = 5 nm  Dpx = ħ/10 nm .... we cannot circumvent HUP! y

3 Note: The slit results in diffraction of the matter wave, which
introduces the uncertainty in py as shown below. You already know this behavior from diffraction of light at a slit! y x screen

4 The conservation of total mechanical energy of a particle means that …
(A) … the sum of heat and kinetic energy is a constant. (B) … the potential energy of the system is a constant. (C) … the sum of kinetic and potential energy is a constant. (D) … the particle has always the same velocity.

5 The conservation of total mechanical energy of a particle means that …
(A) … the sum of heat and kinetic energy is a constant. (B) … the potential energy of the system is a constant. (C) … the sum of kinetic and potential energy is a constant. (D) … the particle has always the same velocity.


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