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Calculus for AP physics

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1 Calculus for AP physics
When using math to do our work We’re not a bunch of dopes! Cuz we know integral means area, And derivatives is slopes!

2 Pre-Fab Vo cab FUNCTIONS a relation that uniquely specifies the values of one quantity in terms of some other quantity. Example- for position: r = r(t) Where ‘r’ is the dependent variable and ‘t’ is the independent variable It is possible for a quantity to depend upon more than one independent variable – we will see some later in the course. LINEAR FUNCTIONS the independent variable appears as the first power. The equation for the function follows the equation for a straight line: y = mx +b where the slope m tells how the function is changing NON-LINEAR FUNCTIONS does not have a well defined slope. Derivatives are used to determine the slope over a small segment or the instantaneous slope

3 Pre-Fab Vo cab (cont.) DERIVATIVE the derivative is a measurement of how a function changes when the values of its inputs change. The derivative of a function at a chosen input value describes the behavior of the function near that input value. The process of finding a derivative is DIFFERENTIATION. DERIVATIVES ARE SLOPES!! A derivative is used when the function being analyzed approximates a straight line – this typically occurs when the change in values is very small Recall the slope of a straight line is determined using DELTA NOTATION (Dy/Dx) since the derivative is over a small interval, the notation changes to: Which is pronounced dee why dee eks

4 Pre-Fab Vo cab (cont.) INTEGRAL in most cases, an integral is an anti-derivative. Integration is used to determine the area under a curve by breaking the entire area into smaller geometric shapes and making a summation. The Fundamental Theorem of Calculus gives us this definition for integrals: “Suppose the function G(x) is such that its derivative gives F(x): then

5 STANDARD FORMS – derivatives (Appendix E, p. A-11)

6 EXAMPLES THE POWER RULE WITH THE SUM/DIFFERENCE RULE (the derivative of a sum/difference is equal to the sum/difference of the derivatives) Given the function: Recognize it is the form: Substitute and solve to obtain:

7 EXAMPLES PRODUCT RULE Substitute and solve to obtain:
Given the function: Substitute and solve to obtain: Let: u=(x2+4) and v=(3x3-2x) and recognize it is in the form: Check the result by multiplying the terms and using the power and sum rules

8 THE QUOTIENT RULE – A SPECIAL CASE
Sometimes it is easier to convert a division problem into a multiplication problem and apply the product rule. Other times – it is easier to work with the division problem as it is written The standard form of the QUOTIENT RULE is:

9 EXAMPLE OF THE QUOTIENT RULE
Use the quotient rule to determine the derivative (ds/dt) of the following equation Let u = t and v =3 – t2 Determine du/dt and dv/dt Put in standard form Simplify Result:

10 THE CHAIN RULE This is applied when a function contains another function [(x2-4)3 , sin(wt), etc] Typically the functions are referred to as the outer and inner functions. The definition of the chain rule is: the derivative of the outer function evaluated at the inner function, all multiplied by the derivative of the inner function As a formula, the chain rule is:

11 CHAIN RULE EXAMPLE Substitute and solve:
Given the formula: y(x) =(x2-4)3 Let u =(x2-4) and y =(u)3. This makes (x2-4) the inner function and u3 the outer function also, recall the standard form. Substitute and solve: Finally: 3(x2-4)2 (2x) = 6x(x2-4)2

12 INTEGRALS INTEGRALS ARE AREAS
Integrals are used to calculate the effects of a quantity when that quantity is not constant An integral is a limit of a summation DEFINITE INTEGRALS have limits – INDEFINITE INTEGRALS require the addition of a constant

13 STANDARD FORMS – integrals (Appendix E, p. A-11)

14 EXAMPLE 10t2 + 2t Determine the integral of the following function:
x(t) = 20t + 2 The standard forms for this function are: 10t2 + 2t Substitute and solve to obtain:

15 INTEGRAL APPLICATION Determining mass – Consider a rod of length L with a non-uniform mass per unit length l dx X = 0 dm (l0 = constant) L A small piece of the rod (dx) will have a small mass (dm) and the ratio dm/dx = l. Adding up all of the pieces will provide the total mass. integrate and evaluate

16 STUDY AND PRACTICE!! If you take physics long enough,
You’ll find that math’s a tool. And if you don’t take physics class- You’ll just remain a fool!


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