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Warmβup #5 1. Simplify (π₯+π¦) 7 2. Multiply β1
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Warmβup #5 Solutions 1. Simplify (π₯+π¦) 7 3 2β2β3β3β3 3 (π₯+π¦)(π₯+π¦)(π₯+π¦)(π₯+π¦)(π₯+π¦)(π₯+π¦)(π₯+π¦) =3 (π₯+π¦) 2 3 4(π₯+π¦)
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Warmβup #5 Solutions 2. Multiply β1 = β β1 3 =2 7β7β3 β β3β7 β 3 =2 7 3 β β 3 =14 3 β β 3 =
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Homework Log Wed 9/23 Lesson 1 β 8 Learning Objective:
To simplify radical expressions into simplest radical form Hw: #113 Pg. 77 #47 β 99 odd
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9/23/15 Lesson 1 β 8 Simplest Radical Form Day 2
Advanced Math/Trig
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Learning Objective To simplify radical expressions into simplest form
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Simplest Radical Form 1. No negative or zero exponents 2. Radicand doesnβt have power β₯ index 3. No in denom 4. No fractions in 5. Index as small as possible index radicand
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Rationalizing Denominator
No radicals in the denominators! = β7 = = β2 = 3 3β β2β2 = = Need a group of 3 β β
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Rationalizing Denominator
β (3+ 5 ) (3+ 5 ) π₯ 9 π¦ 2 = 3 2π₯ 3β3βπ¦βπ¦ = 3 6π₯π¦ 3π¦ 4. 3 3β 5 Use difference of squares (a + b)(a β b) = π 2 β π 2 = 3(3+ 5 ) (3) 2 β ( 5 ) 2 = β5 = β 3 3π¦ 3 3π¦
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Simplify π₯ 2 9 π¦ 10 Need groups of 6 = 6 π₯ π¦ 10 = π₯ 2 π¦ π¦ 12 = π₯ 2 π¦ π¦ 2 π¦ 3 π§ π¦ 4 π§ 3 Same index, reduce first! = 1 2π¦ π§ 2 = 2π¦ 2π¦π§ β π¦ π¦ 2 β 2π¦ 2π¦ = 3 9π₯π¦ 3 π¦ 2
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Simplify 7. 3 2β3 2 β 2 β1 2 = β3 2 2 β3(6) (2 2 ) 2 β (6) 2 = β6 2 β β36 = β β28 = 3 2 β β3(2) β = β18 8β36 = 3β Can all be divided by β2
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Simplify = = (3) = = 1 3 3β3 = 3 3 3 β = β
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Simplify β β 3 = (2 5 ) 2 β ( 3 ) 2 = β3 =
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Simplify 11. 3 π₯ 3 + π₯ π₯+4 = π₯ 2 (3π₯+1) + 4(3π₯+1) = x 3π₯ π₯+1 =(x+2) 3π₯+1
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Simplify 12. (2β 3 ) β2 = 1 (2β 3 ) 2 = (7) 2 β (4 3 ) 2 = = 7+4 3 = 1 4β β = 1 7β4 3 = β16(3)
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Ticket Out the Door Simplify π₯ 3 π₯ 6 Explain what you did to simplify.
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Homework #113 Pg. 77 #47 β 99 odd
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