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Triple Integrals
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Triple Integrals Triple integrals over a box:
By Fubiniβs Theorem we can change the order of integration in six possible ways. Applications: is the volume of the solid E. If π(π₯,π¦,π§) is the mass density of the solid E (e.g. in kg/m3), then is the total mass of the solid (in kg.)
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Triple integrals Example: Evaluate where E is the solid defined by
By Fubiniβs Theorem we can change the order of integration: All these integrals give the same result.
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Triple Integrals Type 1 Triple integrals over more general regions:
There are six different orders of integration possible in a triple iterated integral. Type 1: Let D be the projection of the solid on the xy-plane and let π§= π’ 1 (π₯,π¦) and π§= π’ 2 (π₯,π¦) be the surfaces forming the βbottomβ and the βtopβ of the solid respectively. There are two different orders of integration on D. For instance, as a type I region we obtain the integral:
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Triple Integrals Type 2 Let D be the projection of the solid on the yz-plane and let π₯= π’ 1 (π¦,π§) and π₯= π’ 2 (π¦,π§) be the surfaces forming the βbackβ and βfrontβ of the solid. There are two different orders of integration on D. For instance, as a type I region we obtain the integral:
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Triple Integrals Type 3 Let D be the projection of the solid on the xz-plane and let π¦= π’ 1 (π₯,π§) and π¦= π’ 2 (π₯,π§) be the surfaces forming the βleftβ and βrightβ sides of the solid. There are two different orders of integration on D. For instance, as a type I region we obtain the integral: Remarks: The limits of integration for the middle integral can involve only the outmost variable of integration. The outside limits must be constant.
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Triple Integrals Example 1
Evaluate where E is the tetrahedron bounded by the coordinate planes and The solid is bounded below by π§=0 and above by Let D be the projection of the tetrahedron on the xy-plane. The arrow enters and exits the solid at the limit of integration for z D
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Triple Integrals Example 2
Use a triple integral to find the volume of the solid bounded by the paraboloid π₯=4 π¦ 2 +4 π§ 2 and the plane x = 4. A line parallel to the x-axis intersects the solid at π₯=4 π¦ 2 +4 π§ 2 and at x = 4. These are the limits of integration for x. Let D be the projection of the solid in the yz-plane. π π + π π =π The surfaces π₯=4 π¦ 2 +4 π§ 2 and x = 4 intersect on a curve C: 4y2 + 4z2 = 4 β y2 + z2 = 1 The circle is the boundary of the region D: polar coordinates:
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Triple Integrals - Example 3
Let E be the solid bounded by π§=0, π§=π¦ and π¦=9β π₯ 2 . Express in the form: a. Limits for z: 0β€π§β€π¦ Let D be the projection of the solid on the π₯π¦-plane.
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Triple Integrals - Example 3 continued
b. A line parallel to the y-axis intersects the solid on the surface π¦=π§ (left surface) and on the surface π¦=9β π₯ 2 (right surface). These are the limits of integration for the y-variable. Let D be the projection of the solid on the π₯π§-plane. The arrow enters and exits the solid at the limit of integration for y The surfaces z = y and y = 9 β x2 intersect in a curve C. The projection of this curve on the xz plane has equation z = 9 β x2 and it is the boundary of the domain D
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Triple Integrals - Example 3 continued
A line parallel to the x-axis intersects the solid on the surface π₯=β 9βπ¦ (back surface) and on the surface π₯= 9βπ¦ (front surface). These are the limits of integration for the x-variable. Let D be the projection of the solid on the π¦π§-plane. y The arrow enters and exits the solid at the limit of integration for x
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