Download presentation
Presentation is loading. Please wait.
1
Lab 9: Electrochemistry
Spring 2018 Lab 9: Electrochemistry
2
Goals Measure voltage of a galvanic cell
Determine how concentration affects voltage Graphically determine value of Faraday constant
3
Oxidation-Reduction Reactions
A.k.a. Redox reactions Involve electron transfer Oxidation = Loss of electrons Reduction = Gain of electrons Balanced using half-reactions Representations of oxidation and reduction
4
Half-Reactions Show how substances lose or gain electrons
Electrons written into reactions Balance charge between reactants/products Example: Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) Fe(s) → Fe+2(aq) + 2e- (oxidation) Cd2+(aq) + 2e- → Cd(s) (reduction) 0 charge = 0 charge
5
Balancing Redox Reactions
Balanced with half-reactions Need same # of electrons in both so they cancel Example: Unbalanced Reaction: Fe(s) + Cl2(aq) → Fe3+(aq) + Cl-(aq) Half-Reactions: Fe(s) → Fe3+(aq) + 3e- Cl2(aq) + 2e- → 2Cl-(aq) Balanced Half-Reactions: 2Fe(s) → 2Fe3+(aq) + 6e- 3Cl2(aq) + 6e- → 6Cl-(aq) Balanced Reaction: 2Fe(s) + 3Cl2(aq) → 2Fe3+(aq) +6Cl-(aq)
6
Galvanic Cells Produce voltage by separating half-reactions into half-cells Necessary components: Electrodes in matching solutions Salt bridge External circuit between electrodes to allow electron flow Electron flow Salt Bridge Cu Zn Cu2+ Zn2+
7
Electrodes Solid surface for redox reaction Two types:
Anode – site of Oxidation (-) Cathode – site of Reduction (+) Current carried from anode to cathode “The RED CAT gets FAT”
8
The Experiment The reaction: Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
The set-up: Half-cells in beral pipets Agar plug salt bridge Voltmeter attached to electrodes measures cell potential (Ecell)
9
Cell Potential Symbol: Ecell Units: Volts (V)
Related directly to Gibbs Free Energy: n = # moles of transferred electrons (see half reactions) F = Faraday’s constant (96,485 C/mol) Potential in a galvanic cell is positive (spontaneous)
10
Standard Cell Potential
Symbol: E°cell Units: Volts (V) Voltage under standard conditions 1 M and 1 bar Can be calculated for reaction using standard reduction potentials
11
Standard Reduction Potential (E°red)
Assigned to reduction half reactions (e.g.) Cu2+(aq) + 2e- → Cu(s) E°red = V See next slide for other values Magnitude unaffected by balancing coefficients I.e. Don’t multiply value! Same number for reverse direction (oxidation) Reversing direction leads to sign change.
12
More (+), more likely to be reduced
More (-), more likely to be oxidized
13
Calculating E°cell Combination of potentials for both half-cells:
E cell ° = E red ° − E ox ° Example: Fe(s) + Cl2(aq) → Fe3+(aq) + Cl-(aq) E red ° Oxidation: 2Fe(s) → 2Fe3+(aq) + 6e V Reduction: 3Cl2(aq) + 6e- → 6Cl-(aq) V E cell ° = V – ( V) = V Note: Eox is the same as Ered for a particular half-reaction (subtraction accounts for sign change associated with opposite direction).
14
Non-Standard Conditions
Potential (Ecell) affected by concentration Concentrations used to calculate Ecell using the Nernst Equation: R = gas constant (8.314 J/(K*mol) T = temperature (K) n = # moles of transferred electrons (see half reactions) F = Faraday’s constant (96,485 C/mol) Q = Reaction quotient that incorporates the concentrations
15
Reaction Quotient (Q) Same set-up as equilibrium constant expression:
Products as numerator raised to coefficient Reactants as denominator raised to coefficient Concentrations NOT at equilibrium Can be initial concentrations Example: N2O4(g) ⇌ 2NO2(g)
16
Determining F Graphically
Nernst equation can be graphed as a straight-line equation: Slope used to calculate Faraday’s constant y = b m * x Experimentally—measured potential for the five trials Natural log of ratio of solution concentrations for the five trials
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.