Presentation is loading. Please wait.

Presentation is loading. Please wait.

Redox Reactions and Electrolysis

Similar presentations


Presentation on theme: "Redox Reactions and Electrolysis"— Presentation transcript:

1 Redox Reactions and Electrolysis
Chapter 7 Redox Reactions and Electrolysis

2 What is a Redox Reaction?
7.1 What is a Redox Reaction?

3 A. Oxidation and Reduction
Gain of oxygen 2Mg(s) + O2(g)  2MgO(s) Mg has been oxidized Loss of oxygen CuO(s) + H2(g)  Cu(s) + H2O(l) CuO has been reduced

4 B. Redox Reactions Redox Reactions – oxidation-reduction reactions take place together

5 A. Oxidation and Reduction
Gain of oxygen 2Mg(s) + O2(g)  2MgO(s) Mg has been oxidized Removal of hydrogen from a compound (organic) Loss of oxygen CuO(s) + H2(g)  Cu(s) + H2O(l) CuO has been reduced Addition of hydrogen to a compound (organic)

6 Check-Up-#1- Pg. 107

7

8 Redox and Electron Transfer
7.2 Redox and Electron Transfer

9 Redox and Electron Transfer
We can define oxidation and reduction with respect to electron transfer and changes in oxidation number

10 Oxidation and Reduction
Gain of oxygen 2Mg(s) + O2(g)  2MgO(s) Mg has been oxidized Removal of hydrogen from a compound (organic) Oxidation Is Loss of electrons (OIL) Loss of oxygen CuO(s) + H2(g)  Cu(s) + H2O(l) CuO has been reduced Addition of hydrogen to a compound (organic) Reduction Is Gain (RIG)

11 A. Half-Equations We can divide a reaction into two half equations – show separate oxidation-reduction reactions 2Na(s) + Cl2(g)  2NaCl(s) Redox-Reaction Video

12 A. Half-Equations We can divide a reaction into two half equations – show separate oxidation-reduction reactions Fe(s) + Cu2+(aq) Fe2+(aq) + Cu(s)

13 B. Balancing Half-Equations
Use 2 half-reactions to write a balanced ionic equation - # electrons lost and gained in a redox reaction must be equal

14 Worked Example #1 – Pg. 108 Construct a balanced ionic equation for the reaction between nickel and iron (III) ions, from the half equations: Ni(s) → Ni2+ (aq) + 2e- Fe3+ (aq) + e- → Fe2+ (aq) Ni(s) → Ni2+ (aq) + 2e- 2(Fe3+ (aq) + e- → Fe2+ (aq)) 2Fe3+ (aq) + 2e- → 2Fe2+ (aq)) 2Fe3+ (aq) + 2e- → 2Fe2+ Ni(s) + 2Fe3+ (aq) → Ni2+ (aq) + 2Fe2+

15 Worked Example #2 – Pg. 108

16 Check-Up-#2 – Pg. 109

17 7.3 Oxidation Numbers

18 A. What are oxidation numbers?
Oxidation Number – number given to each atom or ion in a compound which shows us its degree of oxidation (represents the charge an atom would have if e- were transferred completely to the atoms with the greater attraction for them in a given situation) +, -, 0 High (+) = more oxidized High (-) = more reduced

19 B. Oxidation Number Rules

20 B. Oxidation Number Rules

21 C. Applying the Oxidation # Rules
Metal & Nonmetal

22 C. Applying the Oxidation # Rules
Nonmetal & Nonmetal – most electronegative element given negative sign

23 C. Applying the Oxidation # Rules
Compound Ions

24 Check-Up- #3 – Pg. 114

25 D. Redox and Oxidation Numbers
We can define oxidation and reduction in terms of oxidation # changes of particular atoms during a reaction

26 Oxidation and Reduction
Gain of oxygen 2Mg(s) + O2(g)  2MgO(s) Mg has been oxidized Removal of hydrogen from a compound (organic) Oxidation Is Loss of electrons (OIL) Increase in oxidation # Loss of oxygen CuO(s) + H2(g)  Cu(s) + H2O(l) CuO has been reduced Addition of hydrogen to a compound (organic) Reduction Is Gain (RIG) Decrease in oxidation #

27 D. Redox and Oxidation Numbers
Sn + 4HNO3  SnO2 + 4NO2 + 2H2O

28 D. Redox and Oxidation Numbers
Oxidizing Agent Reducing Agent Increases ox. # of another atom Deceases in ox. # Substance that gets reduced (gains e-) Decreases ox. # of another atom Increases in ox. # Substance that gets oxidized (loses e-)

29

30 Check-Up - #4 – Pg. 114

31 E. Naming Compounds Iron(II) Chloride Iron(III) Chloride

32 E. Naming Compounds Oxides of Nitrogen N2O NO NO2

33 E. Naming Compounds Nitrate Ions NaNO2 NaNO3

34 E. Naming Compounds Ions w/ Oxygen + 1 other element = end -ate
Cl + oxygen = S + oxygen =

35 E. Naming Compounds Inorganic Acids w/ Oxygen = end in -ic H3PO3 =
HClO4 =

36 Check-Up - #5 – Pg. 116 Sodium sulfate (IV) Sodium sulfate (VI)
Iron(II) nitrate(V) Iron(III) nitrate(V) Iron(II) sulfate(VI) Copper(I) oxide Sulfuric(IV) acid Manganese(VII) oxide

37 Worked Example - #3 – Pg. 117 Sodium Chlorate (V)

38 Check-Up - #6 – Pg. 117

39 F. Balancing Chemical Equations Using Ox. #
We can use ox. #s to balance equations involving redox reactions

40 Worked Example #4 – Pg. 117 Write a balanced chemical equation

41 Worked Example #5 – Pg. 117 Write a balanced chemical equation

42 Check-Up - #7 – Pg. 118

43 7.4 Electrolysis

44 Electrolytic Cells Electrolysis – decomposition of a compound into its elements by an electric current Used to extract metals which ore are high in reactivity series Used to produce non-metals such as chlorine and to purify some metals

45

46 Check-Up - #8 – Pg. 119

47 B. Redox Reactions in Electrolysis

48

49 Check-Up - #9 – Pg. 119

50 C. Extracting Aluminum 6O2-  3O2 + 12e-
O2 reacts w/ hot carbon electrodes Oxidizes them to CO2 which escapes from cell Electrodes must be replaced periodically C. Extracting Aluminum Al3+ + 3e-  Al Reduced Dense, sinks to bottom

51 C. Extracting Aluminum Al2O3 molten via passing a high electric current through electrolyte (40,000 A) However, Al2O3 has a high MP = lots of E needed = $$$ Energy needed is lowered by dissolving Al2O3 in large amounts of cryolite (Na3AlF6) Lowers MP of Al2O3 to 970oC Improves electrical conductivity of electrolyte

52

53 Check-Up - #7 – Pg. 120

54 D. Electrolysis of Brine
Concentrated aqueous solution of NaCl Obtained from seat water or dissolving rock salt in H2O Used to produce chlorine, hydrogen, and sodium hydroxide Ions in brine: Na+, Cl-, H+ (from H2O), OH- (from H2O)

55

56 2H+ + 2e-  H2 Na+ Cl- 2Cl-  Cl2 + 2e- H+ OH-

57 Check-Up - #11 – Pg. 122

58 E. The Electrolytic Purification of Copper
Copper  smelting in furnace (water pipes) Not pure enough for electrical wiring because even small impurities reduce conductivity Need 99.99% pure copper Done through electrolysis

59 Anode decreases in thickness
Cu  Cu2+ + 2e- Cu2+ + 2e-  Cu Cu atoms deposited on cathode Cu2+ Cathode increases in thickness When “full,” cathode is removed and replaced

60 Check-Up - #12 – Pg. 123


Download ppt "Redox Reactions and Electrolysis"

Similar presentations


Ads by Google