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General Physics (PHY 2140) Lecture 27 Modern Physics Quantum Physics

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1 General Physics (PHY 2140) Lecture 27 Modern Physics Quantum Physics
Blackbody radiation Plank’s hypothesis Chapter 27 9/16/2018

2 If you want to know your progress so far, please send me an request at 9/16/2018

3 Lightning Review Last lecture: Modern physics
Relativistic energy, momentum Relativistic addition of velocities Review Problem: You are packing for a trip to another star, to which you will be traveling at 0.99c. Should you buy smaller sizes of your clothing, because you will be skinnier on the trip? Can you sleep in a smaller cabin than usual, because you will be shorter when you lie down? 9/16/2018

4 Reminder (for those who don’t read syllabus)
Reading Quizzes (bonus 5%): It is important for you to come to class prepared, i.e. be familiar with the material to be presented. To test your preparedness, a simple five-minute quiz, testing your qualitative familiarity with the material to be discussed in class, will be given at the beginning of some of the classes. No make-up reading quizzes will be given. There could be one today… … but then again… 9/16/2018

5 26.9 Relativistic Energy The definition of kinetic energy requires modification in relativistic mechanics KE = mc2 – mc2 The term mc2 is called the rest energy of the object and is independent of its speed The term mc2 is the total energy, E, of the object and depends on its speed and its rest energy 9/16/2018

6 Relativistic Energy – Consequences
A particle has energy by virtue of its mass alone A stationary particle with zero kinetic energy has an energy proportional to its inertial mass E = mc2 The mass of a particle may be completely convertible to energy and pure energy may be converted to particles 9/16/2018

7 Energy and Relativistic Momentum
It is useful to have an expression relating total energy, E, to the relativistic momentum, p E2 = p2c2 + (mc2)2 When the particle is at rest, p = 0 and E = mc2 Massless particles (m = 0) have E = pc This is also used to express masses in energy units mass of an electron = 9.11 x kg = MeV 9/16/2018

8 Problem: relativistic proton
A proton in a high-energy accelerator is given a kinetic energy of 50.0 GeV. Determine the momentum and the speed of the proton. 9/16/2018

9 Recall that E2 = p2c2 + (mc2)2. This can be used to solve for p:
A proton in a high-energy accelerator is given a kinetic energy of 50.0 GeV. Determine (a) the momentum and (b) the speed of the proton. Recall that E2 = p2c2 + (mc2)2. This can be used to solve for p: Given: E = 50.0 GeV Find: p = ? v =? Thus, Similarly with velocity: 9/16/2018

10 QUICK QUIZ A photon is reflected from a mirror. True or false: (a) Because a photon has a zero mass, it does not exert a force on the mirror. (b) Although the photon has energy, it cannot transfer any energy to the surface because it has zero mass. (c) The photon carries momentum, and when it reflects off the mirror, it undergoes a change in momentum and exerts a force on the mirror. (d) Although the photon carries momentum, its change in momentum is zero when it reflects from the mirror, so it cannot exert a force on the mirror. False True 9/16/2018

11 Example 1: Pair Production
An electron and a positron are produced and the photon disappears A positron is the antiparticle of the electron, same mass but opposite charge Energy, momentum, and charge must be conserved during the process The minimum energy required is 2me = 1.04 MeV 9/16/2018

12 Example 2: Pair Annihilation
In pair annihilation, an electron-positron pair produces two photons The inverse of pair production It is impossible to create a single photon Momentum must be conserved 9/16/2018

13 Quantum Physics 9/16/2018

14 Introduction: Need for Quantum Physics
Problems remained from classical mechanics that relativity didn’t explain: Blackbody Radiation The electromagnetic radiation emitted by a heated object Photoelectric Effect Emission of electrons by an illuminated metal Spectral Lines Emission of sharp spectral lines by gas atoms in an electric discharge tube 9/16/2018

15 Development of Quantum Physics
Development of ideas of quantum mechanics Also called wave mechanics Highly successful in explaining the behavior of atoms, molecules, and nuclei Quantum Mechanics reduces to classical mechanics when applied to macroscopic systems Involved a large number of physicists Planck introduced basic ideas Mathematical developments and interpretations involved such people as Einstein, Bohr, Schrödinger, de Broglie, Heisenberg, Born and Dirac 9/16/2018

16 26.1 Blackbody Radiation An object at any temperature is known to emit electromagnetic radiation Sometimes called thermal radiation Stefan’s Law describes the total power radiated The spectrum of the radiation depends on the temperature and properties of the object Stefan’s constant emissivity 9/16/2018

17 Blackbody Blackbody is an idealized system that absorbs incident radiation of all wavelengths If it is heated to a certain temperature, it starts radiate electromagnetic waves of all wavelengths Cavity is a good real-life approximation to a blackbody 9/16/2018

18 Blackbody Radiation Graph
Experimental data for distribution of energy in blackbody radiation As the temperature increases, the total amount of energy increases Shown by the area under the curve As the temperature increases, the peak of the distribution shifts to shorter wavelengths 9/16/2018

19 Wien’s Displacement Law
The wavelength of the peak of the blackbody distribution was found to follow Wein’s Displacement Law λmax T = x 10-2 m • K λmax is the wavelength at the curve’s peak T is the absolute temperature of the object emitting the radiation 9/16/2018

20 The Ultraviolet Catastrophe
Classical theory did not match the experimental data At long wavelengths, the match is good Rayleigh-Jeans law At short wavelengths, classical theory predicted infinite energy At short wavelengths, experiment showed no energy This contradiction is called the ultraviolet catastrophe 9/16/2018

21 Planck’s Resolution En = n h ƒ
Planck hypothesized that the blackbody radiation was produced by resonators Resonators were submicroscopic charged oscillators The resonators could only have discrete energies En = n h ƒ n is called the quantum number ƒ is the frequency of vibration h is Planck’s constant, h=6.626 x J s Key point is quantized energy states 9/16/2018


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