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FATIGUE • Fatigue = failure under cyclic stress.

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Presentation on theme: "FATIGUE • Fatigue = failure under cyclic stress."— Presentation transcript:

1 FATIGUE • Fatigue = failure under cyclic stress.
• Stress varies with time. --key parameters are S and sm • Key points: Fatigue... --can cause part failure, even though smax < sc. --causes ~ 90% of mechanical engineering failures. 17

2 FATIGUE DESIGN PARAMETERS
• Fatigue limit, Sfat: --no fatigue if S < Sfat • Sometimes, the fatigue limit is zero! 18

3 FATIGUE MECHANISM • Crack grows incrementally • Failed rotating shaft
typ. 1 to 6 increase in crack length per loading cycle crack origin • Failed rotating shaft --crack grew even though Kmax < Kc --crack grows faster if • Ds increases • crack gets longer • loading freq. increases. 19

4 IMPROVING FATIGUE LIFE
1. Impose a compressive surface stress (to suppress surface cracks from growing) --Method 1: shot peening --Method 2: carburizing 2. Remove stress concentrators. 20

5 PROCESSING USING DIFFUSION (1)
• Case Hardening: --Diffuse carbon atoms into the host iron atoms at the surface. --Example of interstitial diffusion is a case hardened gear. • Result: The "Case" is --hard to deform: C atoms "lock" planes from shearing. --hard to crack: C atoms put the surface in compression. 21

6 MEASURING ELEVATED T RESPONSE
• Elevated Temperature Tensile Test (T > 0.4 Tmelt). • Generally, . . . 22

7 CREEP • Occurs at elevated temperature, T > 0.4 Tmelt
• Deformation changes with time. Adapted from Figs and 8.27, Callister 6e. 23

8 SECONDARY CREEP • Most of component life spent here.
• Strain rate is constant at a given T, s --strain hardening is balanced by recovery stress exponent (material parameter) . activation energy for creep (material parameter) strain rate material const. applied stress • Strain rate increases for larger T, s 24

9 CREEP FAILURE • Failure: along grain boundaries.
• Estimate rupture time S 590 Iron, T = 800C, s = 20 ksi g.b. cavities applied stress 24x103 K-log hr • Time to rupture, tr temperature function of applied stress 1073K Ans: tr = 233hr time to failure (rupture) 25

10 SUMMARY • Engineering materials don't reach theoretical strength.
• Flaws produce stress concentrations that cause premature failure. • Sharp corners produce large stress concentrations and premature failure. • Failure type depends on T and stress: -for noncyclic s and T < 0.4Tm, failure stress decreases with: increased maximum flaw size, decreased T, increased rate of loading. -for cyclic s: cycles to fail decreases as Ds increases. -for higher T (T > 0.4Tm): time to fail decreases as s or T increases. 26


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