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Graphing exercise Phet Simulation
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Using the Phet Simulation
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A person is moving at a constant rate of 2 m/s from a 0 position with no acceleration. Draw the following graphs for the first 7 seconds Time Displacement 1 2 3 4 5 6 7
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To fill in the displacement column, we need to use the d = v
To fill in the displacement column, we need to use the d = v*t equation. d = 2 m/s * 1 s = 2 meters d = 2 m/s * 2 s = 4 meters d = 2 m/s * 3 s = 6 meters d = 2 m/s * 4 s = 8 meters d = 2 m/s * 5 s = 10 meters d = 2 m/s * 6 s = 12 meters d = 2 m/s * 7 s = 14 meters Time Displacement 1 2 2 4 3 6 4 8 5 10 6 12 7 14
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Using excel, connected scattered
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For the velocity vs. time graph,
2 1 2 3 4 5 6 7
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For the acceleration vs. time graph
0 1 2 3 4 5 6 7
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2. A person is moving with an initial 2 m/s from a 0 position with constant 1 m/s2 acceleration.
For this problem you have to use the equation d = d0 + vit + ½ at2 Our d0 is the starting point which is 0.
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d = vit + ½ at2 d = 2(0) + ½ (1)(0)2 = 0 d = 2(1) + ½ (1)(1)2 = 2.5
Repeating the process d = 6 d = 10.5 d = 16 d = 22.5 d = 30 d = 38.5 Time Displacement 0 1 2.5 2 6 3 10.5 4 16 5 22.5 6 30 7 38.5
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Using vf = vi + at vf = 2 + (1)(0) = 2 vf = 2 + (1)(1) = 3 vf = 2 + (1)(2) = 4 vf = 2 + (1)(3) = 5 vf = 2 + (1)(4) = 6 vf = 2 + (1)(5) = 7 vf = 2 + (1)(6) = 8 vf = 2 + (1)(7) = 9
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Time Velocity 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9
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Time Acceleration 1 1 2 3 4 5 6 7
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A person is moving from an initial position of -5 m with a constant velocity of 3 m/s and an acceleration of m/s2. Draw the following graphs for the first 7 seconds. Using the earlier methods, complete this problem.
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Displacement vs. time -5 1 -2.125 2 0.5 3 2.875 4 5 6.875 6 8.5 7
-5 1 -2.125 2 0.5 3 2.875 4 5 6.875 6 8.5 7 9.875
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