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Assume object does not vary in y
Signal equation for constant Gx gradient, no y gradient Assume object does not vary in y How does s(t) and F(m) relate? For F(m), look first at F(0) and then F(1)? How does the phase across f(n) applied by the kernel change between these 2 Fourier points? Between F(2) and F(1)?
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Lecture 5 MR: Spatial Resolution, etc.
Readout vs. Phase Encode Recall, Readout Gx t t Phase Encode Gy Gy t ty Each phase encode adds an incremental phase shift across the FOV. Phase shift over FOVy
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Phase encode number 0, 1, 2, 3, 4, 5, 6 y=FOV/2
Turn off the readout gradient and look at the phase of individual signal spins at 5 locations along the y axis. We will first look at the ky=0 phase encode and then move up in k-space. The phase of the spins at each y level are written for each phase encode below. Phase encode number 0, 1, 2, 3, 4, 5, 6 5 4 3 2 1 Gy t y=FOV/2 0, p, 2p, 3p, 4p, 5p, 6p y=FOV/4 0, p/2, p, 3 p/2, 2p, 5p/2, 3p y=0 0, 0, 0 , , , 0, y=-FOV/4 0, -p/2, p,-3 p/2,-2p,-5p/2,-3p y=-FOV/2 0, -p, -2p, -3p, -4p, -5p, 6p
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Readout Direction Note: Each excitation line across kx (fast)
Next measure sample new ky (slow) For a given time sampling rate, use an anti-aliasing filter (LPF) I(t) sreceive LPF A/D cos(ot) Bandwidth is set so it’s width is
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Readout Direction (2) We should never have aliasing in readout direction. FOV is free in the readout direction. Note: If we have hardware (receiver speed), we can increase the sampling rate, increase the low pass filter cutoff, to reduce t - If we reduce kx, what happens to FOV? - SNR effects? - Where should we place the long axis?
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Aliasing in Phase Encode Direction
Referenced to 2D FT Referred to as “phase wrap” Left) ky = 1/FOV Right) sampling ky = 2/FOV
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Phase encode number 0, 1, 2, 3, 4, 5, 6 y=FOV/2
Turn off the readout gradient and look at the phase of individual signal spins at 5 locations along the y axis. We will first look at the ky=0 phase encode and then move up in k-space. Phase encode number 0, 1, 2, 3, 4, 5, 6 5 4 3 2 1 Gy t y=FOV/2 0, p, 2p, 3p, 4p, 5p, 6p y=FOV/4 0, p/2, p, 3 p/2, 2p, 5p/2, 3p y=0 0, 0, 0 , , , 0, y=-FOV/4 0, -p/2, p,-3 p/2,-2p,-5p/2,-3p y=-FOV/2 0, -p, -2p, -3p, -4p, -5p, 6p
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Aliasing in Phase Encode Direction
Ignore x encoding and look at phase of individual spins after each phase encoding step when ky = 2/FOV Phase encode number 0, , , , 4, , y=FOV2 0, 2 p, 4 p, p , 8 p , 10 p, 12 p y=FOV/4 0, p, 2p, p, 4p, p, 6p y=0 0, 0, , , , , y=-FOV/4 0, -p , -2p, -3 p, -4p, -5p, -6p y=-FOV/2 0, -2p, -4p, -6p, -8p, -10p, -12p
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Why didn’t neck wrap around?
Sagittal Phase Wrap Phase direction Frequency Direction Why didn’t neck wrap around?
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Spatial Resolution Why? Main Lobe Width = in x, in y
Definition: Spatial Resolution Element True for large kx # of samples · spatial resolution = FOV
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k-Space Acquisition ky kx Phase Direction One line of k-space
Encode Sampled Signal DAQ kx ky Phase Direction One line of k-space acquired per TR Frequency Direction
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Fast Fourier Transform
FFT
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Characteristics of Rectilinear Sampling
Unaliased FOV kx Spatial Resolution ky
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512 x 512 8 x 8
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512 x 512 16 x 16
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512 x 512 32 x 32
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512 x 512 64 x 64
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512 x 512 128 x 128
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512 x 512 256 x 256
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Resolution is lower, bigger pixels
Avoiding Aliasing Phase Encode Direction need “small”, but 1) If we increase Npe to compensate for reducing ky scan time increases Resolution depends on FOV increases 2) Same Npe reducing ky reduce wky What happens? Resolution is lower, bigger pixels FOV increases same scan time
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2D FT or Spin Warp Gx t Tread Gy max Gy t Why this 2? extent in kx
about kx = 0 Gy max Gy t Why this 2?
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Fundamental Limits – What are they?
Limits to Resolution - Max gradient strength (<4 G/cm) (<1 G/cm) Readout duration As Tread , T2 decay blurs FOVy vs. For fixed scan time, improved resolution costs in FOV. - Sequence-dependent effects Gibbs Ringing Fundamental Limits – What are they?
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