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AM3.2b To Use Synthetic Division To Find All Roots, Part 1

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Presentation on theme: "AM3.2b To Use Synthetic Division To Find All Roots, Part 1"— Presentation transcript:

1 10-11-17 AM3.2b To Use Synthetic Division To Find All Roots, Part 1
The current temperature is zero degrees! Pop, when they say the temperature is zero… Does that mean there is no temperature at all? Got ID?

2 Active Learning Assignment?

3 Opener: Find the next numbers in the sequence: (Don’t say it out loud, just wait)
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, ___, ___, ___, … 89 144 233 These is called the Fibonacci Sequence. Each number is the sum of the two previous numbers. These numbers happen in Nature a great deal.

4 Given P(x) = x2 + 7x + 12, then to factor:
PRE-LESSON: Terminology: Given P(x) = x2 + 7x + 12, then to factor: 0 = x2 + 7x + 12 ® 0 = (x + 4)(x + 3) FACTORS Solving: x = -4 or x = -3 ROOTS OR ZEROS OR SOLUTIONS x axis (y = 0) x = -4 x = -3

5 * THE FUNDAMENTAL THEOREM OF ALGEBRA:
Given P(x) can be factored. If P(x) is a polynomial of degree n and n > 0 , then the equation P(x) = 0 has exactly n roots. These roots are complex (real and/or imaginary) numbers and not necessarily unique*. This means that if you have a: 2nd degree polynomial, then there are 2 roots. 3rd degree polynomial, then there are 3 roots. 4th degree polynomial, then there are 4 roots. Etc. *For example, x2 – 6x + 9 = 0 factors to (x – 3) (x – 3) = 0 and the root is “3”, with a multiplicity of 2. Or, you can list 3 twice.

6 LESSON: Given a polynomial equation and one of its roots, use Synthetic Division to find the remaining roots: Same as (x – 2) 2 4 18 -10 2 9 -5 (a) (b) (c) Now, we need to finish factoring by sight or by the quadratic formula.

7 We can factor this by sight or by the quadratic formula.
Thus, the zeros or roots of the polynomial are:

8 Active Learning Assignment: {Ans}
P 61: # 19 {-1, ½, 3} , 20 {-2, -½, 2/3 }


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