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Linear Geometry
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You have already completed the bridging booklet
Reminder You have already completed the bridging booklet chapter 9 Linear graphs If you need support with any of the following you MUST see your teacher Rearranging a linear equation to find the gradient and intercept Drawing a line from an equation
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Starter: Ten questions
Linear coord geometry KUS objectives BAT explore gradients of parallel and perpendicular line BAT rearrange and find equations of lines Starter: Ten questions Identify the equation of each of the following line graphs
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Starter: identify linear equations
x Starter: identify linear equations Identify the equations of these lines
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Answers y = 2x + 3 y = 2x - 4 y = 3x + 1 y = -2x + 5 y = x + 2 y = 3
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Notes: General equation of a line
We are used to: gradient y-intercept Another ‘standard way to write the equation of a line is: The General form of the equation of a line
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For each of these equations, i) rearrange it into the form y = mx + c
WB1 gradient and y intercept For each of these equations, i) rearrange it into the form y = mx + c ii) give the gradient iii) give the intercept on the y-axis. 10 Gradient m = -2 Gradient m = 2.5 3 Intercept (0, 10) Intercept (0, 3)
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y y = 3 x x y = 3 x + 1 y = 3 x + 2 y = 3 x + 3 y = 3 x + 4
Notes 1 y = 3 x y = 3 x + 1 y = 3 x + 2 y = 3 x + 3 y = 3 x + 4 y = 3 x + 5 y = 3 x – 1 y = 3 x – 2 x y = 3 x – 3 y = 3 x – 4 The ‘family’ of Parallel lines with equation y = 3x + a
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There are three sets of parallel lines here.
Challenge 1 There are three sets of parallel lines here. Match them up and say what the gradient is for each set.
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General equation intersection points
Why bother with the general equation? Solve these simultaneous equations: Easier to work with:
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General equation intersection points
Why bother with the general equation? Solve these simultaneous equations: The solution is the Intersection point of the two lines (-2, -½)
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Which of these lines are parallel to the line 3x - 2y – 4 = 0
Challenge 2 Which of these lines are parallel to the line 3x - 2y – 4 = 0
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These lines are perpendicular
Notes These lines are perpendicular Define perpendicular = at right angles
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Notes What is each gradient? 1 2 Gradient = ½ 2 Gradient = -2 1
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Notes What is each gradient? Gradient = 3 1 3 3 1 Gradient = -1/3
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PERPENDICULAR LINE IS THE
Notes 1 THE GRADIENT OF A PERPENDICULAR LINE IS THE NEGATIVE RECIPROCAL OF THE OTHER 𝒎 𝟏 × 𝒎 𝟐 =−𝟏
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y x What do you notice? Draw a Perpendicular line to y = 3x
Notes Draw a Perpendicular line to y = 3x What do you notice? The ‘family’ of Perpendicular lines with general equation y = -1/3x + a
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gradient y-intercept 2 -5 Examples: We are used to:
Notes We are used to: gradient y-intercept The Perpendicular line has gradient m2 where: line perpendicular 2 -5 Examples:
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What is the gradient of the lines perpendicular to these?
Practice 1 What is the gradient of the lines perpendicular to these? y = 2x + 1 m = 2 -1/m= -1/2 y = 2 + 4x m = 4 -1/m= -1/4 y = 3x + 2 m = 3 -1/m= -1/3 y + 2x = 2 m = -2 -1/m= 1/2 2y = 3x - 2 m = 3/2 -1/m= -2/3 5y + 2x = 3 m = -2/5 -1/m= 5/2
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WB2 Give the General equation of the perpendicular line to 2𝑥+𝑦−8=0 that goes through (4, 9) Has gradient m1 = -2 So the gradient of a perpendicular line is m2 = ½ When x = 4, y = 9 … so
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WB3 Give the General equation of the perpendicular line to 𝑥+5𝑦−6=0 that goes through ( 3 5 , 7) Has gradient m1 = -1/5 So the gradient of a perpendicular line is m2 = 5 When x = 3/5, y = 7 … so
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First the midpoint of line AB is (−1. 4)
WB4 Two points A(1,2) and B(-3,6) are joined to make the line AB. Find the equation of the perpendicular bisector of AB First the midpoint of line AB is (−1. 4) 𝑚 1 = 6−2 −3−1 =−1 2nd the gradient of line AB is So the perpendicular gradient is 𝑚 2 =1 𝑦=𝑥+ ? When x =1, y = 2 so 𝑦=𝑥+1 Is the perpendicular bisector of line AB
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BAT rearrange and find equations of lines
KUS objectives BAT explore gradients of parallel and perpendicular line BAT rearrange and find equations of lines self-assess One thing learned is – One thing to improve is –
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