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Stacks and Queues
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Abstract Data Types (ADTs)
Abstract Data Type (ADT): A specification of a collection of data and the operations that can be performed on it. Describes what a collection does, not how it does it Consumers of a stack or queue do not need to know how they are implemented. We just need to understand the idea of the collection and what operations it can perform. Stacks usually implemented with arrays Queues often implemented with a linked list
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Stacks and Queues queue stack
Some collections are constrained so clients can only use optimized operations stack: retrieves elements in reverse order as added queue: retrieves elements in same order as added push pop, peek top 3 2 bottom 1 front back 1 2 3 dequeue, first enqueue queue stack
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Stacks Stack: A collection based on the principle of adding elements and retrieving them in the opposite order. Last-In, First-Out ("LIFO") Elements are stored in order of insertion. We do not think of them as having indexes. Client can only add/remove/examine the last element added (the "top"). basic stack operations: push: Add an element to the top. pop: Remove the top element. peek: Examine the top element. push pop, peek analogy: trays of food at the sizzler top 3 2 bottom 1 stack
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Stacks in Computer Science
Programming languages and compilers: method calls are placed onto a stack call=push return=pop compilers use stacks to evaluate expressions Matching up related pairs of things: find out whether a string is a palindrome examine a file to see if its braces { } match convert "infix" expressions to pre/postfix Sophisticated algorithms: searching through a maze with "backtracking" many programs use an "undo stack" of previous operations
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Stack Limitations You cannot loop over a stack in the usual way. Assume we created our own Stack class. Stack<Integer> s = new Stack<Integer>(); ... for (int i = 0; i < s.size(); i++) { do something with s.get(i); } Instead, pop each element until the stack is empty. // process (and destroy) an entire stack while (!s.isEmpty()) { do something with s.pop();
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What Happened to My Stack?
Suppose we're asked to write a method max that accepts a Stack of Integers and returns the largest Integer in the stack: // Precondition: !s.isEmpty() public static void max(Stack<Integer> s) { int maxValue = s.pop(); while (!s.isEmpty()) { int next = s.pop(); maxValue = Math.max(maxValue, next); } return maxValue; The algorithm is correct, but what is wrong with the code?
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What Happened to My Stack?
The code destroys the stack in figuring out its answer. To fix this, you must save and restore the stack's contents: public static void max(Stack<Integer> s) { Stack<Integer> backup = new Stack<Integer>(); int maxValue = s.pop(); backup.push(maxValue); while (!s.isEmpty()) { int next = s.pop(); backup.push(next); maxValue = Math.max(maxValue, next); } while (!backup.isEmpty()) { // restore s.push(backup.pop()); return maxValue;
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Queues queue Queue: Retrieves elements in the order they were added.
First-In, First-Out ("FIFO") Elements are stored in order of insertion but don't have indexes. Client can only add to the end of the queue, and can only examine/remove the front of the queue. Basic queue operations: enqueue (add): Add an element to the back. dequeue (remove): Remove the front element. first: Examine the front element. front back 1 2 3 dequeue, first enqueue analogy: trays of food at the sizzler queue
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Queues in Computer Science
Operating systems: queue of print jobs to send to the printer queue of programs / processes to be run queue of network data packets to send Programming: modeling a line of customers or clients storing a queue of computations to be performed in order Real world examples: people on an escalator or waiting in a line cars at a gas station (or on an assembly line)
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Using Queues As with stacks, must pull contents out of queue to view them. Assume we created our own Queue class. // process (and destroy) an entire queue while (!q.isEmpty()) { do something with q.dequeue(); } To examine each element exactly once. int size = q.size(); for (int i = 0; i < size; i++) { (including possibly re-adding it to the queue) Why do we need the size variable?
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Mixing Stacks and Queues
We often mix stacks and queues to achieve certain effects. Example: Reverse the order of the elements of a queue. Queue<Integer> q = new Queue<Integer>(); q.enqueue(1); q.enqueue(2); q.enqueue(3); // [1, 2, 3] Stack<Integer> s = new Stack<Integer>(); while (!q.isEmpty()) { // Q -> S s.push(q.dequeue()); } while (!s.isEmpty()) { // S -> Q q.enqueue (s.pop()); System.out.println(q); // [3, 2, 1]
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Java Stack Class Stack<String> s = new Stack<String>(); s.push("a"); s.push("b"); s.push("c"); // bottom ["a", "b", "c"] top System.out.println(s.pop()); // "c" Stack has other methods that are off-limits (not efficient) Stack<T>() constructs a new stack with elements of type T push(value) places given value on top of stack pop() removes top value from stack and returns it; throws EmptyStackException if stack is empty peek() returns top value from stack without removing it; size() returns number of elements in stack isEmpty() returns true if stack has no elements
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Java Queue Interface Queue<Integer> q = new LinkedList<Integer>(); q.add(42); q.add(-3); q.add(17); // front [42, -3, 17] back System.out.println(q.remove()); // 42 IMPORTANT: When constructing a queue, you must use a new LinkedList object instead of a new Queue object. Because Queue is an interface. add(value) places given value at back of queue remove() removes value from front of queue and returns it; throws a NoSuchElementException if queue is empty peek() returns front value from queue without removing it; returns null if queue is empty size() returns number of elements in queue isEmpty() returns true if queue has no elements
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Exercises Write a method stutter that accepts a queue of Integers as a parameter and replaces every element of the queue with two copies of that element. [1, 2, 3] becomes [1, 1, 2, 2, 3, 3] Write a method mirror that accepts a queue of Strings as a parameter and appends the queue's contents to itself in reverse order. [a, b, c] becomes [a, b, c, c, b, a]
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