1. Matter Review 1

2. 1- Which positively charged particle is found in the nucleus?
2- Where are the nonmetals in the periodic table?
3- What do elements of the same group have in common?
protons
They are all located to the right of the staircase, except hydrogen.
They all have the same number of valence electrons, so they have similar chemical properties.

3. 4- Hydrogen is a nonmetal, but it is in the same column as the alkali metals. Why?
5- What are the elements in the second column of the periodic table called? What do they have in common?
Because hydrogen has only one valence electron, like the alkali metals.
Alkaline earth metals. They all have two valence electrons.

4. 7- What do elements of the same period have in common?
6. In the atomic model of potassium below, which letter represents a valence electron? Explain your answer.
7- What do elements of the same period have in common?
The letter D, because this electron is in the outermost electron shell.
They have the same number of electron shells in their atoms

5. 8- Are the atomic representations below correct Lewis structures
8- Are the atomic representations below correct Lewis structures? If not, explain why. a) B) C)
Correct
Incorrect, because argon has eight valence electrons, not nine and the format of the electrons is wrong
Correct

6. 9) Are the atomic representations below correct according to the Rutherford-Bohr model? If not, explain why A) B)
Correct
Incorrect, the protons should be in the nucleus, and the electrons should be in the shells around the nucleus.

7. Incorrect, an atom must have the same number of protons and electrons, the inner shells are not filled in. C) D)
Incorrect, an atom must have the same number of protons and electrons.

8. C(s) + H2(g) + O2(g)  CH3OH(g)
Question 10A 2 2
C(s) H2(g) + O2(g)  CH3OH(g) 4 4 2
C-H-H-H –O-H C
H-H
O-O
H-H
C-H-H-H –O-H C
H-H
H-H

9. Question 10B Al(s) + O2 (g)  Al2O3(s) 4 3 2 O-O Al-Al-O-O-O Al Al O-O

10. Question 11 2 CuO(s)  2 Cu(s) + O2(g) 8 g = 10 g ? g
The decomposition of 10 g of copper oxide is represented by the following equation: 2 CuO(s)  2 Cu(s) + O2(g)
If you obtain 8 g of copper, what amount of oxygen was released? Explain your answer.
 2 CuO(s)  2 Cu(s) + O2(g)
8 g =
10 g
? g
10 g – 8g = 2g of O2
9/19/2018