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Energy & Calorimetry THERMOCHEMISTRY.

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Presentation on theme: "Energy & Calorimetry THERMOCHEMISTRY."— Presentation transcript:

1 Energy & Calorimetry THERMOCHEMISTRY

2 What is “energy”? ENERGY is defined as “the ability to do work”
Work = force x distance (work means moving something!) Different forms of energy include: electrical, solar, chemical, nuclear

3 Categories of Energy POTENTIAL energy of position or “stored” energy
KINETIC energy of motion

4 HEAT ENERGY Energy is absorbed or released as heat in chemical or physical changes – energy involved can be measured DURING PHYSICAL/CHEMICAL CHANGES ENERGY AND MATTER ARE CONSERVED! Heat energy impacts particle motion (atoms, ions, molecules) – more heat, more motion; less heat, less motion

5 Kinetic–Molecular Theory of Matter
Developed in late 19th century to account for behavior of atoms and molecules Based on idea that particles of matter are always in motion – KINETIC ENERGY = ENERGY OF MOTION Used to explain properties of solids, liquids & gases in terms of the energy of particles and forces that act between them

6 HEAT ENERGY Temperature is a measure of the average kinetic energy of the particles in a sample of matter Heat, represented by “q” for “Q”uanity of heat, is energy that transfers from one object to another because of a temperature difference between them Heat flows from an object of higher temperature to one with a lower temperature

7 HEAT ENERGY Heat flow is measured in two common units:
the calorie and the joule Food is usually measured in Calories: 1 Calorie = 1 kilocalorie = 1000 calories A JOULE is the SI unit of heat as well as all other forms of energy and is abbreviated J 4.184 J = 1 calories

8 MEASURING HEAT GAINED/LOST
Q = m t cp Q = quantity of heat m = mass in grams t = change in temperature Cp = specific heat of the substance

9 SPECIFIC HEAT A physical property of matter that describes how well a substance can absorb or release heat It is a measure of how many joules of energy the substance absorbs or loses per gram for each degree change in temperature Specific heat unit: J/g-C

10 Specific Heat The amount of heat required to raise the temperature of one gram of substance by one degree Celsius. Ex Cp water = J/g-C

11 Specific Heat Calculation
Cp = Q__ m x t Temperature Change Calculation t = Q___ cp x m

12 A Bomb Calorimeter

13 A Cheaper Calorimeter

14 Table of Specific Heats

15 Calculations involving Specific Heat
Q = m x T x cp m = mass in grams Q = Heat lost or gained T = Temperature change cp = Specific Heat

16 Sample problem How much heat is absorbed when 250 g of water is heated from 27 C to 85 C? Q = m x t x cp Q = (250 g) ( 58 C) (4.184 J/g-C) = 60668 J

17 Temperature Temperature Scales Name Melting Temp Boiling Temp
ice water C Celsius C C K Kelvin K K F Fahrenheit 32 F F

18 PHASE CHANGE Involves PHYSICAL CHANGES from solid to liquid, liquid to solid, liquid to gas, etc Particles absorb or release heat during phase changes NOTE: THE TEMPERATURE OF THE MATTER DOES NOT CHANGE DURING A PHASE CHANGE!

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20 PHASE CHANGE The heat absorbed or released during a phase change changes the position of the particles to one another DURING A PHASE CHANGE, THERE IS A CHANGE IN THE POSITION OF THE PARTICLES TO ONE ANOTHER AND THUS A CHANGE IN POTENTIAL ENERGY During a temperature change the heat absorbed or released affects the AVERAGE KINETIC ENERGY OF THE MOLECULES

21 HEAT AND MATTER KINETIC ENERGY – energy of motion
KINETIC ENERGY CHANGES WITH TEMPERATURE CHANGES POTENTIAL ENERGY – energy of position POTENTIAL ENERGY CHANGES DURING PHASE CHANGES

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23 Common Phase Changes condensation deposition vaporization sublimation
Fusion/melting Freezing/crystallization

24 Phase Differences Solid – definite volume and shape; particles packed
in fixed positions. Liquid – definite volume but indefinite shape; particles close together but not in fixed positions Gas – neither definite volume nor definite shape; particles are at great distances from one another

25 Three Phases

26 CALCULATIONS INVOLVING HEAT INFORMATION:
CP ice = 2.06 J/gC Cp water = J/g C Cp steam = 2.02 J/gC Heat of fusion for ice= 334 J/g (Heat of crystallization) Heat of vaporization of water = 2260 J/g (Heat of condensation)

27 Temperature Change Q = m t Cp ice = m t (2.06 J/g-C)
Q = m t Cp water = m t (4.184 J/g-C) Q = m t Cp steam = m t (2.02 J/g-C)

28 Phase Change (Remember, no T change during Phase Change)
Q = m x heat of fusion = m x 334 J/g (heat added to melt each gram of ice) Q = m x heat of vaporization =m x 2260 J/g (heat added to boil each gram of water)


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