1. General Physics (PHY 2140) Lecture 12 Electricity and Magnetism
Magnetic fields and force
Application of magnetic forces
Chapter 19
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2. The Physics Resource Center Room 172 of Physics Research Building.
Department of Physics and Astronomy
announces the Fall 2003 opening of
The Physics Resource Center
on Monday, September 22 in
Room 172 of Physics Research Building.
Hours of operation:
Mondays, Tuesdays, Wednesdays AM to 6 PM
Thursdays and Fridays AM to 3 PM
Undergraduate students taking PHY will be able to get assistance in this Center with their homework, labwork and other issues related to their physics course.
The Center will be open: Monday, September 22 to Wednesday, December 10, 2003.
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3. Lightning Review Last lecture: DC circuits Kirchoff’s rules RC circuit
Magnetism
Magnets
Review Problem: The three light bulbs in the circuit all have the same resistance. Given that brightness is proportional to power dissipated, the brightness of bulbs B and C together, compared with the brightness of bulb A, is
1. twice as much.
2. the same.
3. half as much.
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4. Last lecture: Magnetic Field
Convenient to describe the interaction at a distance between magnets with the notion of magnetic field.
Magnetic objects are surrounded a magnetic field.
Moving electrical charges are also surrounded by a magnetic field (in addition to the electrical field).
A vector quantity: magnitude and direction…
The letter B is used to represent magnetic fields.
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5. Magnetic Field Direction
The magnetic field direction (of a magnet bar) can studied with a small compass. 1 N S
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6. Magnetic Field Lines 1 N S
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7. Applications: A “bit” of history
IBM introduced the first hard disk in 1957, when data usually was stored on tapes. It consisted of 50 platters, 24 inch diameter, and was twice the size of a refrigerator.
It cost $35,000 annually in leasing fees (IBM would not sell it outright). It’s total storage capacity was 5 MB, a huge number for its time!
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8. Magnetic Field of the Earth
A small magnetic bar should be said to have north and south seeking poles. The north of the bar points towards the North of the Earth.
The geographic north corresponds to a south magnetic pole and the geographic south corresponds to a magnetic north.
The configuration of the Earth magnetic resemble that of a (big) magnetic bar one would put in its center.
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9. Magnetic Field of the Earth
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10. Magnetic Field of the Earth
Near the ground, the field is NOT parallel to the surface of the Earth.
The angle between the direction of the magnetic field and the horizontal is called dip angle.
The north and south magnetic pole do not exactly correspond to the south and north geographic north.
South magnetic pole found (in 1832) to be just north of Hudson bay in Canada – 1300 miles from the north geographical pole.
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12. More on the Magnetic Field of the Earth
The difference between the geographical north and the direction pointed at by a compass changes from point to point and is called the magnetic declination.
Source of the field : charge-carrying convection currents in the core of the earth.
In part related to the rotation of the earth
The orientation of the field “flips” and changes over time – every few million years…
Basalt rocks
Other planets (e.G. Jupiter) are found to have a magnetic field.
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13. Mini-quiz No problem using the compass in Australia.
You travel to Australia for a business trip and bring along your American-made compass. Does the compass work correctly in Australia???
No problem using the compass in Australia.
North pole of the compass will be attracted to the South geographic pole…
The vertical component of the field is different (opposite) but that cannot be detected with normal operation of the compass.
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14. 19.3 Magnetic Fields
Stationary charged particles do NOT interact with a magnetic field.
Charge moving through a magnetic field experience a magnetic force.
Value of the force is maximum when the charge moves perpendicularly to the field lines.
Value of the force is zero when the charge moves parallel to the field lines.
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15. Magnetic Fields in analogy with Electric Fields
Distribution of charge creates an electric field E(r) in the surrounding space.
Field exerts a force F=q E(r) on a charge q at r
Magnetic Field:
Moving charge or current creates a magnetic field B(r) in the surrounding space.
Field exerts a force F on a charge moving q at r
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16. Strength of the Magnetic Field
Define the magnetic field, B, at a given point in space in terms of the magnetic force imparted on a moving charge at that point.
Observations show that the force is proportional to
The field
The charge
The velocity of the particle
The sine of the angle between the field and the direction of the particle’s motion.
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17. Strength and direction of the Magnetic Force on a charge in motionB +q v
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18. Magnetic Field Magnitude
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19. Magnetic Field Units [F] = newton [v] = m/s [q] = C [B] = tesla (T).
Also called weber (Wb) per square meter.
1 T = 1 Wb/m2.
1 T = 1 N s m-1 C-1.
1 T = 1 N A-1 m-1.
CGS unit is the Gauss (G)
1 T = 104 G.
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20. Right Hand Rule
Provides a convenient trick to remember the spatial relationship between F, v, and B.
Consider the motion of positive charge
Direction of force reversed if negative charge.
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21. Example: Proton traveling in Earth’s magnetic field.
A proton moves with a speed of 1.0 x 105 m/s through the Earth’s magnetic field which has a value of 55 mT a particular location. When the proton moves eastward, the magnetic force acting on it is a maximum, and when it moves northward, no magnetic force acts on it. What is the strength of the magnetic force? And what is the direction of the magnetic field?
V = 1.0 x 105 m/s
B = 55 mT
Northward or southward.
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22. 19.4 Magnetic Force on Current-carrying conductor.
A magnetic force is exerted on a single charge in motion through a magnetic field.
That implies a force should also be exerted on a collection of charges in motion through a conductor I.e. a current.
And it does!!!
The force on a current is the sum of all elementary forces exerted on all charge carriers in motion.
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23. 19.4 Magnetic Force on Current
If B is directed into the page we use blue crosses representing the tail of arrows indicating the direction of the field,
If B is directed out of the page, we use dots.
If B is in the page, we use lines with arrow heads.
x x x x
x x x x x
x x x x x x
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24. Force on a wire carrying current in a magnetic field.
Bin
x x x x
x x x x x
x x x x x x
x x x x
x x x x x
x x x x x x
x x x x
x x x x x
x x x x x x
Bin
Bin
I = 0 I I
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25. Force on a wire carrying current in a magnetic field.
x x x x
x x x x x
x x x x x x x
x x x x x x x
x x x x x x x
x x x x x x x
x x x x x vd q A
Magnetic Field and Current at right angle from each other.
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26. Force on a wire carrying current in a magnetic field.
General Case: field at angle q relative to current. B
B sin q q I
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27. Voice Coil
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28. Mini-Quiz
In a lightning strike, there is a rapid flow of negative charges from a cloud to the ground. In what direction is a lightning strike deflected by the Earth’s magnetic field?
Reasoning:
Negative charge flow down.
Positive Current upward.
B field direction Geo South to Geo North
Answer:
Force towards the west. I
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29.                                                                                         
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30. Example: Wire in Earth’s B Field
A wire carries a current of 22 A from east to west. Assume that at this location the magnetic field of the earth is horizontal and directed from south to north, and has a magnitude of 0.50 x 10-4 T. Find the magnetic force on a 36-m length of wire. What happens if the direction of the current is reversed?
B=0.50 x 10-4 T.
I = 22 A
l = 36 m
Fmax = BIl
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31. 19.5 Torque on a Current Loop
Imagine a current loop in a magnetic field as follows: B I b a
a/2 F
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32. I F B B F
a/2 b F F a
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33. In a motor, one has “N” loops of current
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34. Example: Torque on a circular loop in a magnetic field
A circular loop of radius 50.0 cm is oriented at an angle of 30.0o to a magnetic field of 0.50 T. The current in the loop is 2.0 A. Find the magnitude of the torque. B
r = m
q = 30o
B = 0.50 T
I = 2.0 A
N = 1
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35. 19.6 Galvanometer/Applications
Device used in the construction of ammeters and voltmeters.
Scale
Current loop or coil
Magnet
Spring
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36. Galvanometer used as Ammeter
Typical galvanometer have an internal resistance of the order of 60 W - that could significantly disturb (reduce) a current measurement.
Built to have full scale for small current ~ 1 mA or less.
Must therefore be mounted in parallel with a small resistor or shunt resistor.
Galvanometer
60 W Rp
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37. The equivalent resistance of the circuit is also small!
Galvanometer
60 W Rp
Let’s convert a 60 W, 1 mA full scale galvanometer to an ammeter that can measure up to 2 A current.
Rp must be selected such that when 2 A passes through the ammeter, only A goes through the galvanometer.
Rp is rather small!
The equivalent resistance of the circuit is also small!
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38. Galvanometer used as Voltmeter
Finite internal resistance of a galvanometer must also addressed if one wishes to use it as voltmeter.
Must mounted a large resistor in series to limit the current going though the voltmeter to 1 mA.
Must also have a large resistance to avoid disturbing circuit when measured in parallel. Rs
Galvanometer
60 W
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39. Maximum voltage across galvanometer:
60 W Rs
Maximum voltage across galvanometer:
Suppose one wish to have a voltmeter that can measure voltage difference up to 100 V:
Large resistance
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40. 19.7 Motion of Charged Particle in magnetic field
Bin
Consider positively charge particle moving in a uniform magnetic field.
Suppose the initial velocity of the particle is perpendicular to the direction of the field.
Then a magnetic force will be exerted on the particle and make follow a circular path.
´ ´ ´ ´ ´ ´ ´
´ ´ ´ ´ ´ ´ ´ F v q r
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41. The magnetic force produces a centripetal acceleration.
The particle travels on a circular trajectory with a radius:
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42. Example: Proton moving in uniform magnetic field
A proton is moving in a circular orbit of radius 14 cm in a uniform magnetic field of magnitude 0.35 T, directed perpendicular to the velocity of the proton. Find the orbital speed of the proton.
r = 0.14 m
B = 0.35 T
m = 1.67x10-27 kg
q = 1.6 x C
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