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Class 9: Area, Consumer Surplus, Integration

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Presentation on theme: "Class 9: Area, Consumer Surplus, Integration"— Presentation transcript:

1 Class 9: Area, Consumer Surplus, Integration
q D(q) Demand Function Revenue

2 What is Total Possible Revenue?
Demand Function Total Possible Revenue The total possible revenue is the money that the producer would receive if everyone who wanted the good, bought it at the maximum price that he or she was willing to pay.

3 Consumer Surplus q D(q) Revenue Consumer Surplus Not Sold Demand Function The total extra amount of money that people who bought the good would have been willing to pay is called the consumer surplus.

4 Finding Areas What is the area of the region R that is enclosed between the x-axis and the graph of f(x) = 2x  x2/2, for x between 1 and 4?

5 Finding Areas What is the area of the region R that is enclosed between the x-axis and the graph of f(x) = 2x  x2/2, for x between 1 and 4?

6 For n = 6 rectangles Sum of areas called S6
= f(m1)x + f(m2)x + f(m3)x + f(m4)x + f(m5)x + f(m6)x =

7 More rectangles: Larger n
As n increases, the value of Sn increases, getting closer and closer to the true are under the curve.

8 Integral Notation We write the value of the midpoint sum as n gets very large by an integral

9 Find Revenue from Buffalo Dinners Not Sold: Optimum price and quantity are $19.19 and 2300
1000 2000 3000 4000 5000 $8 $16 $24 $32 Not Sold Consumer Surplus q = 2,300 D(2,300) = $19.99 Revenue $45,977 2,300 $19.99 Demand Function D(q) =  q2  q $0 4014

10 Find Consumer Surplus for Dinners
1000 2000 3000 4000 5000 $8 $16 $24 $32 Not Sold Consumer Surplus q = 2,300 D(2,300) = $19.99 Revenue $45,977 2,300 $19.99 Demand Function D(q) =  q2  q $0


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