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6.1 β Properties of Exponents
Todayβs learning goal: students will be able to use zero and negative exponents Use properties of exponents Solve real βlife problems involving exponents.
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Core Concept Example: 4 β2 = 1 4 2 Example: π βπ = 1 π π , where aβ 0
Zero Exponent For any nonzero number a, a0 = 1. The power of 00 is undefined. Example: 40 =1 Example: a0 = 1, where aβ 0 Negative Exponent For any integer n and any nonzero number a, a-n is the reciprocal of an. Example: 4 β2 = Example: π βπ = 1 π π , where aβ 0
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Example 1 - Example 2- c. 4π₯ 0 π¦ β3
Evaluate each expression a = b. (β2) β4 = 1 (β2) 4 = 1 β2ββ2ββ2ββ2 1 Example 2- = 1 16 Simplify the expression c. 4π₯ 0 π¦ β3 = 4π₯ 0 π¦ 3 =4 π¦ 3
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You Try- Evaluate each expression 1. (β9) 0 = b. 3 β3 = 1 3 3 = 1 3β3β3 = 1 27 1 Simplify the expression using only positive exponents c. β β d. 3 β2 π₯ β5 π¦ 0 = π₯ 5 = 1 9π₯ 5 = β1β2 2 =β4
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Core Concept β Product of Powers Property
To multiply powers with the same base, add their exponents. 4 6 β 4 3 = 4 9 To prove this, lets look at the expanded form of the equation: 4 6 means 4β4β4β4β4β4 4 3 means 4β4β4 So, 4 6 β 4 3 means 4β4β4β4β4β4β4β4β4 which is equivalent to 4 9
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Example 3 β multiplying with exponents
= 3β3β3β3β3β3β3β3= 3 8 b. π₯ 3 β π₯ 5 = π₯ 8 c. π₯ π β π₯ π = π₯ π+π d. 2 π β 2 π = 2 π+π
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Core Concept β Quotient of Powers Property
To divide powers with the same base, subtract their exponents = 4 6β3 = 4 3 To prove this, lets look at the expanded form of the equation: 4β4β4β4β4β4 4β4β4 = 4 3
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Example 4 β dividing with exponents
Evaluate each expression a. (β4) 2 (β4) 7 b = = 1 (β4) 5 =β 1 β4ββ4ββ4ββ4ββ4 =(β4) 2β7 = (β4) β5 =β 5 9β6 = 5 3 =125 c β β5 2 = 3β3β3β5β5β5 3β5β5 =3β3β5=45
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Core Concept β power of a power property
To find a power of a power, multiply the exponents ( 4 6 ) 3 = 4 18 To prove this, lets look at the expanded form of the equation: ( 4 6 ) 3 means 4 6 β 4 6 β 4 6 Which would be 4β4β4β4β4β4β4β4β4β4β4β4β4β 4β4β4β4β4 So, ( 4 6 ) 3 means 4 18
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Example 4 β Power to a Power
Evaluate each expression a. ( π§ 4 ) β3 b. ( 6 β2 ) β1 = = 1 π§ 12 =π§ 4ββ3 = π§ β12 6 β2ββ1 = 6 2 =36 c. ( π€ 12 ) 5 = π€ 60
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Core Concept β Power of a product
To find a power of a product, find the power of each factor and multiply (3β2) 5 = 3 5 β or (ππ) π = π π β π π = π π π π Example 5 Evaluate each expression a. (β1.5π¦) 2 b. ( π β10 ) 3 = =(β1.5) 2 β π¦ 2 = 2.25π¦ 2 π 3 (β10) 3 =β π c. ( 3π 2 ) 4 = π = 81 π 4 16
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Example 5 β Solving a real-life problem
A jellyfish emits about 1.25 x 10 8 particles of light, or photons, in 6.25 x 10 β4 second. How many photons does the jellyfish emit each second? Write you answer in scientific notation and in standard form. a π₯ π₯ 10 β4 = π₯ β4 =0.2 π₯ =2 π₯ The jellyfish emits 200,000,000,000 photons per second.
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You try! It takes the Sun about 2.3 x years to orbit the center of the Milky Way. It takes Pluto about 2.5 x years to orbit the Sun. How many times does Pluto orbit the Sun while the Sun completes one orbit around the center of the Milky Way? Write you answer in scientific notation. 2.3 π₯ π₯ 10 2 = π₯ =0.92 π₯ 10 6 =9.2 π₯ 10 5
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