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Ch. 10 Chemical Quantities

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Presentation on theme: "Ch. 10 Chemical Quantities"— Presentation transcript:

1 Ch. 10 Chemical Quantities

2 3 Methods of Measuring Counting Mass Volume

3 Example 1 If 0.20 bushel is 1 dozen apples, and a dozen apples has a mass of 2.0 kg, what is the mass of .050 bushel of apples?

4 Example 1 Count: 1 dozen apples = 12 apples
Mass: 1 dozen apples = 2.0 kg apples Volume: 1 dozen apples = 0.20 bushels apples Conversion Factors: 1 dozen k.g dozen 12 apples 1 dozen bushels

5 Example 1 0.50 bushel x 1 dozen x 2.0 kg = 0.20 bushel 1 dozen

6 Avogadro’s Number Named after the Italian scientist Amedo Avogadro di Quaregna 6.02 x 10 23

7 Mole (mol) 1 mol = 6.02 x 10 23 representative particles
Representative particles: atoms, molecules ions, or formula units (ionic compound)

8 Mole (mol) Moles= representative x mol particles x 10 23

9 Example 2 (atoms  mol) How many moles is 2.80 x atoms of silicon?

10 Example 2 2.80 x 10 24 atoms Si x 1 mol Si 6.02 x 10 23 atoms Si

11 Example 3 (mol  molecule)
How many molecules of water is moles?

12 Example 3 0.360 mol H2O x 6.02 x 10 23 molecules H2O 1 mol H2O

13 The Mass of a Mole of an Element
The atomic mass of an element expressed in grams = 1 mol of that element = molar mass Molar mass S Molar mass Hg Molar mass C Molar mass Fe

14 6.02 x atoms S 6.02 x atoms Hg 6.02 x atoms C 6.02 x atoms Fe

15 Example 4 (mol  gram) If you have 4.5 mols of sodium, how much does it weigh?

16 Example 4 .45 mol Na x 23 g Na = g Na = 1.0 x 10 2 g Na 1 mol Na

17 Example 5 (grams  atoms)
If you have 34.3 g of Iron, how many atoms are present?

18 Example 5 34.3 g Fe x 1 mol Fe x 6.02 x 10 23 atoms 55.8 g Fe 1 mol Fe
=3.70 x atoms Fe

19 The Mass of a Mole of a Compound
To find the mass of a mole of a compound you must know the formula of the compound H2O  H= 1 g x 2 O= 16 g 18 g = 1 mole = 6.02 x 10 23 molecules

20 Example 6 (gram  mol) What is the mass of 1 mole of sodium hydrogen carbonate?

21 Example 6 Sodium Hydrogen Carbonate = NaHCO3 Na=23 g H=1 g C=12 g
O=16 g x3 84 g NaHCO3 = 1 mol NaHCO3

22 Mole-Volume Relationship
Unlike liquids and solids the volumes of moles of gases at the same temperature and pressure will be identical

23 Avogadro’s Hypothesis
States that equal volumes of gases at the same temperature and pressure contain the same number of particles Even though the particles of different gases are not the same size, since the gas particles are spread out so far the size difference is negligible

24 Standard Temperature and Pressure (STP)
Volume of a gas changes depending on temperature and pressure STP= 0oC (273 K) 101.3 kPa (1 atm)

25 Standard Temperature and Pressure (STP)
At STP, 1 mol = 6.02 X 1023 particles = 22.4 L of ANY gas= molar volume

26 Conversion Factors AT STP 1 mol gas L gas 22.4 L gas mol gas

27 Example 7 At STP, what volume does 1.25 mol He occupy?

28 Example 7 1.25 mol He x L He = 28.0 L He 1 mol He

29 Example 8 If a tank contains 100. L of O2 gas, how many moles are present?

30 Example 8 100. L O2 X 1 mol O2 = 4.46 mol O2 22.4 L O2

31 Calculating Molar Mass from Density
The density of a gas at STP is measured in g/L This value can be sued to determine the molar mass of gas present

32 Example 9 A gaseous compound of sulfur and oxygen has a density of 3.58 g/L at STP. Calculate the molar mass.

33 Example 9 1 mol gas x 22.4 L gas X 3.58 g gas = 1 mol gas 1 L gas
Molar Mass= 80.2 g

34 Percent Composition The relative amounts of the elements in a compound
These percentages must equal 100

35 Percent Composition %element = mass of element x 100 mass of compound

36 Example 10 Find the percentage of each element present in Al2 (CO3)3

37 Example 10 Al2(CO3)3 Al= 27 g x 2 = 54 g / 234 g x 100=23%
C= 12 g x 3 = 36 g/ 234 g x 100= 15% O = 16 g x 9 = 144 g / 234 g x 100=62% 234 g Al2(CO3)3


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