Download presentation
Presentation is loading. Please wait.
1
Biology, 9th ed,Sylvia Mader
Chapter 11 Chapter 11 Mendelian Inheritance Mendelian Inheritance
2
Human Genetic Disorders
Outline Blending Inheritance Monohybrid Cross Law of Segregation Modern Genetics Genotype vs. Phenotype Punnett Square Dihybrid Cross Law of Independent Assortment Human Genetic Disorders
3
Gregor Mendel
4
Formulated fundamental laws of heredity in early 1860s
Gregor Mendel Austrian monk Studied science and mathematics at University of Vienna Conducted breeding experiments with the garden pea Pisum sativum Carefully gathered and documented mathematical data from his experiments Formulated fundamental laws of heredity in early 1860s Had no knowledge of cells or chromosomes Did not have a microscope
5
Fruit and Flower of the Garden Pea
6
Mendel’s Monohybrid Crosses: An Example
7
Garden Pea Traits Studied by Mendel
8
Theories of inheritance in Mendel’s time:
Blending Inheritance Theories of inheritance in Mendel’s time: Based on blending Parents of contrasting appearance produce offspring of intermediate appearance Mendel’s findings were in contrast with this He formulated the particulate theory of inheritance Inheritance involves reshuffling of genes from generation to generation
9
Mendel’s Monohybrid Crosses: An Example
10
One-Trait Inheritance
Mendel performed cross-breeding experiments Used “true-breeding” (homozygous) plants Chose varieties that differed in only one trait (monohybrid cross) Performed reciprocal crosses Parental generation = P First filial generation offspring = F1 Second filial generation offspring = F2 Formulated the Law of Segregation
11
Law of Segregation Each individual has a pair of factors (alleles) for each trait The factors (alleles) segregate (separate) during gamete (sperm & egg) formation Each gamete contains only one factor (allele) from each pair Fertilization gives the offspring two factors for each trait
12
Modern Genetics View Each trait in a pea plant is controlled by two alleles (alternate forms of a gene) Dominant allele (capital letter) masks the expression of the recessive allele (lower- case) Alleles occur on a homologous pair of chromosomes at a particular gene locus Homozygous = identical alleles Heterozygous = different alleles
13
Homologous Chromosomes
14
Genotype Versus Phenotype
Refers to the two alleles an individual has for a specific trait If identical, genotype is homozygous If different, genotype is heterozygous Phenotype Refers to the physical appearance of the individual
15
Table listing all possible genotypes resulting from a cross
Punnett Square Table listing all possible genotypes resulting from a cross All possible sperm genotypes are lined up on one side All possible egg genotypes are lined up on the other side Every possible zygote genotypes are placed within the squares
16
Punnett Square Showing Earlobe Inheritance Patterns
17
Try this one MONOHYBRID CROSS Cross a heterozygous tall plant with a heterozygous tall plant (use T = tall and t = short) Determine expected genotype and phenotype ratios.
18
Test cross determines genotype of individual having dominant phenotype
Monohybrid Testcross Individuals with recessive phenotype always have the homozygous recessive genotype However, Individuals with dominant phenotype have indeterminate genotype May be homozygous dominant, or Heterozygous Test cross determines genotype of individual having dominant phenotype
19
One-Trait Test Cross Unknown is Heterozygous
20
One-Trait Test Cross Unknown is Homozygous Dominant
21
IS MY DOG A PURE BREED? Do a test cross: G = golden retriever g = other
22
Not so much!
23
Two-Trait Inheritance
Dihybrid cross uses true-breeding plants differing in two traits Observed phenotypes among F2 plants Formulated Law of Independent Assortment The pair of factors for one trait segregate independently of the factors for other traits All possible combinations of factors can occur in the gametes
24
Try Mendel’s Classic Dihybrid Cross
Cross two heterozygous tall, heterozygous green pod producing plants. Use a punnett square to show expected offspring and complete a phenotype ratio. Key: T = tall G = green pods t = short g = yellow pods
25
Two-Trait (Dihybrid) Cross
26
Hartford’s example
27
Rat Answers
28
Two-Trait Test Cross
32
SOLVING GENETICS PROBLEMS
Rules of Probability *segregation and independent assortment of alleles during meiosis and fertilization are random events *if we know genotype of parents we can predict the EXPECTED genotypes of offspring using rules of probability
33
The probability of all possible outcomes for an event must add up to 1
Probability Scale Scale range: 0-1 The probability of all possible outcomes for an event must add up to 1
34
EVENT PROBABILITY *tossing heads w/normal coin………………1/2 *tossing tails
Common Examples EVENT PROBABILITY *tossing heads w/normal coin………………1/2 *tossing tails 1
35
Probability of rolling 3 on a six-sided die? 1/6
Try a common one Probability of rolling 3 on a six-sided die? 1/6 Probability of rolling a number other than 3? 5/6
36
Random events are independent of one another!
If a couple has 6 sons and tries for the little girl: there is still a ½ chance of getting their wish. Regardless of the past events!
37
LAWS OF PROBABILITY * Rule of multiplication *Rule of addition
39
A: egg w/ t = ½ sperm w/ t = ½
Ex 3 - monohybrid Q: In a Mendelian cross between two heterozygous pea plants (Tt), what is the probability that the offspring will be homozygous recessive? A: egg w/ t = ½ sperm w/ t = ½ overall probability that two will unite is ½ x ½ = ¼
40
A: prob. of egg w/ YR = ½ x ½ = ¼ prob. of sperm w/ YR = ½ x ½ = ¼
Ex 4. Dihybrid cross Q: For YyRr x YyRr, what is the probability of an F2 plant having genotype YYRR? A: prob. of egg w/ YR = ½ x ½ = ¼ prob. of sperm w/ YR = ½ x ½ = ¼ Overall prob. for offspring: ¼ x ¼ = 1/16
41
Ex. 5 Trihybrid Q: What is the probability that a trihybrid cross between two organisms with genotypes AaBbCc and AaBbCc produce an AABBCc offspring? A: Look at each allele pair separately Aa x Aa: prob. of AA = ¼ Bb x Bb: prob. of BB = ¼ Cc x Cc: prob. of Cc = ½ Overall that this will occur simultaneously: ¼ x ¼ x ½ = 1/32
42
Rule of Addition The probability of an event that can occur in two or more independent ways is the sum of the separate probabilities of the different ways. Think heterozygotes!
43
¼ + ¼ = 1/2
44
Ex. 2: monohybrids Q: In a Mendelian cross between pea plants that are heterozygous (Pp), what is the probability of the offspring being heterozygous? A: there are two different ways for this to occur- 1) sperm gives P and egg gives p OR 2) egg gives P and sperm gives p
45
So… sperm gives P and egg gives p ½ X ½ = ¼ 2) egg gives P and sperm gives p OVERALL PROB. of way 1 or way 2 ¼ + ¼ = ½
46
EX 3 - Dihybrid What is the probability that two parents heterozygous for both height and flower color will produce HETEROZYGOUS tall offspring with purple flowers?
47
A: Look at each allele pair separately Aa x Aa: prob. of aa = ¼
Ex 4 Trihybrid Q: What is the probability that a trihybrid cross between two organisms with genotypes AaBbCc and AaBbCc produce an aabbcc offspring? A: Look at each allele pair separately Aa x Aa: prob. of aa = ¼ Bb x Bb: prob. of bb = ¼ Cc x Cc: prob. of cc = ¼ Overall that this will occur simultaneously: ¼ x ¼ x ¼ = 1/64
48
ppyyRr, ppYyrr, Ppyyrr, PPyyrr, and ppyyrr
Ex. 5 Trihybrid Q: PpYyRr x Ppyyrr What is the chance that the offspring will show at least two recessive phenotypes out of the three traits? A: break down the possibilities of all the genotypes that are homozygous recessive for at least two traits: ppyyRr, ppYyrr, Ppyyrr, PPyyrr, and ppyyrr
49
PpYyRr x Ppyyrr ppyyRr ¼ x ½ x ½ = 1/16 ppYyrr ¼ x ½ x ½ = 1/16 Ppyyrr ½ x ½ x ½ = 2/16 PPyyrr ¼ x ½ x ½ = 1/16 ppyyrr ¼ x ½ x ½ = 1/16 6/16 or 3/8 chance of an offspring showing at least 2 of the recessive traits
50
ANALYZING GENETIC DISORDERS
CHAPTER 11 – autosomal disorders CHAPTER 12 – sex-linked and gene-linked and trisomy/monosomy
51
Human Genetic Disorders
Autosome - Any chromosome other than a sex chromosome Genetic disorders caused by genes on autosomes are called autosomal disorders Some genetic disorders are autosomal dominant An individual with AA has the disorder An individual with Aa has the disorder An individual with aa does NOT have disorder Other genetic disorders are autosomal recessive An individual with AA does NOT have disorder An individual with Aa does NOT have disorder, but is a carrier An individual with aa DOES have the disorder
52
Autosomal Recessive Pedigree Chart
53
Example: albinism
54
Autosomal Dominant Pedigree Chart
55
Autosomal Recessive Disorders
Tay-Sachs Disease Progressive deterioration of psychomotor functions Cystic Fibrosis Mucus in bronchial tubes and pancreatic ducts is particularly thick and viscous Phenylketonuria (PKU) Lack enzyme for normal metabolism of phenylalanine
56
Cystic Fibrosis Therapy
57
Autosomal Dominant Disorders
Neurofibromatosis Tan or dark spots develop on skin and darken Small, benign tumors may arise from fibrous nerve coverings Huntington Disease Neurological disorder Progressive degeneration of brain cells Severe muscle spasms Personality disorders
58
A Victim of Huntington Disease
59
Huntington Disease: Normal and Diseased Brain
60
Sex-linked – disorders carried on the X chromosome
Colorblindness Hemophilia Baldness (?)
62
Incomplete and CoDominance
Incomplete - Heterozygote has phenotype intermediate between that of either homozygote (think pink) Phenotype reveals genotype without test cross ADD to Notes – CoDominance – heterozygote phenotype shows both alleles, equal dominance (think spots)
63
Incomplete Dominance
64
ROAN COW - MOO
65
Multiple Allelic Traits
Some traits controlled by multiple alleles The gene exists in several allelic forms (but each individual only has two) ABO blood types The alleles: IA = A antigen on red cells, anti-B antibody in plasma IB = B antigen on red cells, anti-AB antibody in plasma I = Neither A nor B antigens, both antibodies Phenotype (Blood Type) Genotype A (actually AA or AO) IAIA or IAi B (actually BB or BO) IBIB or IBi AB IAIB O (actually OO) ii
66
Inheritance of Blood Type
67
Blood Type Mystery
68
QUICK REVIEW Incomplete vs. Codominance
Mendel proposed independent assortment (not always the case) * linked genes (w/crossing over at times) Mendel proposed complete dominance (not always the case) * incomplete and codominance occurs
70
AB blood type is also example of codominance
71
Blood Type: good for complete dom., codominance and multiple alleles
72
Complete the chart
76
Polygenic Inheritance
Occurs when a trait is governed by two or more genes having different alleles Each dominant allele has a quantitative effect on the phenotype These effects are additive Result in continuous variation of phenotypes
77
Height in Human Beings
78
Frequency Distributions in Polygenic Inheritance
79
Terminology Pleiotropy Codominance Epistasis
A gene that affects more than one characteristic of an individual Sickle-cell (incomplete dominance) Codominance More than one allele is fully expressed ABO blood type (multiple allelic traits) Epistasis A gene at one locus interferes with the expression of a gene at a different locus Human skin color (polygenic inheritance)
80
Pleiotropy
81
Epistasis – disrupts the expected
82
Environment and Phenotype: Himalayan Rabbits
83
Human Genetic Disorders
Review Blending Inheritance Monohybrid Cross Law of Segregation Modern Genetics Genotype vs. Phenotype Punnett Square Dihybrid Cross Law of Independent Assortment Human Genetic Disorders
84
Biology, 9th ed,Sylvia Mader
Chapter 11 Ending Slide Chapter 11 Mendelian Inheritance Mendelian Inheritance
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.