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Acids & Bases Titration.

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Presentation on theme: "Acids & Bases Titration."— Presentation transcript:

1 Acids & Bases Titration

2 A. Neutralization Chemical reaction between an acid and a base
Products are a salt (ionic compound) and water

3 ACID + BASE  SALT + WATER
A. Neutralization ACID + BASE  SALT + WATER HCl + NaOH  NaCl + H2O strong strong neutral HC2H3O2 + NaOH  NaC2H3O2 + H2O weak strong basic Salts can be neutral, acidic, or basic Neutralization does not mean pH = 7

4 ACID + BASE  SALT + WATER
A. Neutralization ACID + BASE  SALT + WATER Double replacement reaction Can predict products – ex. antacids in your stomach HCl + Ca(OH)2  2 CaCl2 + H2O 2 strong strong neutral

5 B. Titration standard solution Titration Analytical method in which a standard solution is used to determine the concentration of an unknown solution unknown solution

6 B. Titration Stoichiometry Provides basis for titration Examples:
1 mol HCl will neutralize 1 mol NaOH 2 mol HCl will neutralize 1 mol Mg(OH)2 HCl + NaOH  NaCl + H2O 2HCl + Mg(OH)2  MgCl2 + 2H2O

7 B. Titration Equivalence point
Point at which equal number of moles of H3O+ and OH- are in solution Determined by… indicator color change dramatic change in pH

8 B. Titration Strong acid, strong base Weak acid, strong base

9 B. Titration Endpoint Point at which indicator color changes
Should be close to equivalence point if correct indicator is chosen

10 moles H3O+ = moles OH- MAVA nA = MBVB nB B. Titration M: Molarity
V: volume n: # of H+ ions in the acid or OH- ions in the base

11 B. Titration 50.0 mL of an unknown solution of NaOH are titrated with M HCl. Find the molarity of the NaOH solution if 52.5 mL of acid are required to reach the equivalence point.

12 B. Titration 42.5 mL of 1.3M KOH are required to neutralize 50.0 mL of H2SO4. Find the molarity of H2SO4.


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