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7.3 Use Functions Involving e
Algebra II
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7.3 Natural Base e Much of the history of mathematics is marked by the discovery of special types of numbers like counting numbers, zero, negative numbers, Л, and imaginary numbers. Like Л and ‘i’, ‘e’ denotes a number. Called The Euler Number after Leonhard Euler ( ) It can be defined by: e= … 0! 1! 2! 3! 4! 5! = ½ + 1/6 + 1/24 + 1/ ≈ …. The number e is irrational – its’ decimal representation does not terminate or follow a repeating pattern. The previous sequence of e can also be represented: As n gets larger (n→∞), (1+1/n)n gets closer and closer to ….. Which is the value of e.
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Ex. 1 Simplify the expression.
a.) e3 · e4 = e7 c.) (3e-4x)2 9e(-4x)2 9 e8x b.) 10e3 = 5e2 2e3-2 = 2e
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Ex.2 Simplify the expression.
b.) 2-2e10x= e10x 4 a.) 24e8 = 8e5 3e3
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Using a calculator Evaluate e2 using a scientific calculator
7.389 Evaluate e2 using a scientific calculator Locate the ex button you need to use the second button
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Evaluate e-.06 with a calculator
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f(x) = aerx is a natural base exponential function
Graphing f(x) = aerx is a natural base exponential function If a>0 & r>0 it is a growth function If a>0 & r<0 it is a decay function
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Graphing Ex. 3a Graph y=ex
Remember the rules for graphing exponential functions! The graph goes thru (0,a) and (1,e) (1,2.7) (0,1)
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Graphing 3b Graph y=e-x (1,.368) (0,1)
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Graphing Ex. 4 Graph y=2e0.75x State the Domain & Range
Because a=2 is positive and r=0.75, the function is exponential growth. Plot (0,2)&(1,4.23) and draw the curve. (1,4.23) (0,2)
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A = Pert Using e in real life.
In 7.1 we learned the formula for compounding interest n times a year. In that equation, as n approaches infinity, the compound interest formula approaches the formula for continuously compounded interest: A = Pert
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Ex. 6) Continuously Compounded Interest
You deposit $ into an account that pays 8% annual interest compounded continuously. What is the balance after 1 year?
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Ex. 6) Continuously Compounded Interest
You deposit $ into an account that pays 8% annual interest compounded continuously. What is the balance after 1 year? P = 1000, r = .08, and t = 1 A=Pert = 1000e.08*1 ≈ $
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Assignment
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