Presentation is loading. Please wait.

Presentation is loading. Please wait.

·. ·.'·.'... "".., ,··,··.,,...,. 'I ' I...,...,,,.,,...t' t > '. ·,.. I.'..'. t>IIt>II I 'J,'J, ' ',,....., '. '.,,., ', J,. '. 'I'. I 'I ' " ">

Published byanjali verma Modified over 6 years ago

Similar presentations

Presentation on theme: "·. ·.'·.'... "".., ,··,··.,,...,. 'I ' I...,...,,,.,,...t' t > '. ·,.. I.'..'. t>IIt>II I 'J,'J, ' ',,....., '. '.,,., ', J,. '. 'I'. I 'I ' " ">"— Presentation transcript:

1 ·. ·.'·.'... ""..,. - 1.1.,··,··.,,...,. 'I ' I...,...,,,.,,...t' t > '. ·,.. I.'..'. t>IIt>II I 'J,'J, ' ',,....., '. '.,,., ', J,. '. 'I'. I 'I ' " "> '., \,\, - ",.,",., I.'.'..........-.., I".,... r.. ' '.-.·.-.·..,.,. I,,,...".".. t.. t.,,. ""# '..,... t..,...,...,.·.·, I,............. - "' ' ' I ' I -...,.·,.,.. I. I ',,..,..,, '..'........ I ;.;..,.,...,.,._... I. I..·-..·- ·' - -·' - -,,.., ! I,,.f.f.,. '·.'·..,., 1, - lJlJ I '.----.:: -,,., r,. I ' I I I IJIJ I I, I I,, \ ),. r ;.. ;. '..'.. I'I' / { J / '., '-·--'-·-- 1.. '.., "

2 ) ' \

3

4 '. r

5

6

7

8 ;I1,;I1,

9 /

10

11 ........ :\:\

Download ppt "·. ·.'·.'... "".., ,··,··.,,...,. 'I ' I...,...,,,.,,...t' t > '. ·,.. I.'..'. t>IIt>II I 'J,'J, ' ',,....., '. '.,,., ', J,. '. 'I'. I 'I ' " ">"

Similar presentations

the self-visitation paradox

the self-visitation paradox
Palindrome Example TM M = (, Q, ) =,, 0, 1 Q = {q start, q copy, q left, q test, q halt } x {0, 1}* PAL(x) = 1 if x is a palindrome and 0 otherwise. That.

Palindrome Example TM M = (, Q, ) =,, 0, 1 Q = {q start, q copy, q left, q test, q halt } x {0, 1}* PAL(x) = 1 if x is a palindrome and 0 otherwise. That.
Knowledge The Pop Quiz Paradox. Replies to Gettier The Tripartite Analysis: S knows that p iff i. p is true, ii. S believes that p; iii. S’s belief that.

Knowledge The Pop Quiz Paradox. Replies to Gettier The Tripartite Analysis: S knows that p iff i. p is true, ii. S believes that p; iii. S’s belief that.
Static Scheduling of Jobs in Frames Layout of task schedule for cyclic executive can be formulated as a schedule for jobs in a hyperperiod. This can be.

Static Scheduling of Jobs in Frames Layout of task schedule for cyclic executive can be formulated as a schedule for jobs in a hyperperiod. This can be.
Freedom and Determinism Libertarianism: Part 2. Libertarianism.

Freedom and Determinism Libertarianism: Part 2. Libertarianism.
Chapter 10: Materials Requirements Planning 1 Solutions to Chapter 10 Exercises.

Chapter 10: Materials Requirements Planning 1 Solutions to Chapter 10 Exercises.
Straight Lines.

Straight Lines.
I.1 ii.2 iii.3 iv.4 1+1=. i.1 ii.2 iii.3 iv.4 1+1=

I.1 ii.2 iii.3 iv.4 1+1=. i.1 ii.2 iii.3 iv.4 1+1=
I.1 ii.2 iii.3 iv.4 1+1=. i.1 ii.2 iii.3 iv.4 1+1=

I.1 ii.2 iii.3 iv.4 1+1=. i.1 ii.2 iii.3 iv.4 1+1=
Example 1 Determine whether the stationary point of the following quadratic functions is a local maxima, local minima or saddle point? A point x* is a.

Example 1 Determine whether the stationary point of the following quadratic functions is a local maxima, local minima or saddle point? A point x* is a.
1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.2. 3.4.

Static Scheduling of Jobs in Frames Layout of task schedule for cyclic executive can be formulated as a schedule for jobs in a hyperperiod. This can be.

Static Scheduling of Jobs in Frames Layout of task schedule for cyclic executive can be formulated as a schedule for jobs in a hyperperiod. This can be.
Problems 10/3 1. Ehrenfast’s diffusion model:. Problems, cont. 2. Discrete uniform on {0,...,n}

Problems 10/3 1. Ehrenfast’s diffusion model:. Problems, cont. 2. Discrete uniform on {0,...,n}
VERTICAL AND HORIZONTAL ASYMPTOTES Limits to Infinity and Beyond.

VERTICAL AND HORIZONTAL ASYMPTOTES Limits to Infinity and Beyond.
Национальная процедура одобрения и регистрации проектов (программ) международной технической помощи (исключая представление информации об организации и.

Национальная процедура одобрения и регистрации проектов (программ) международной технической помощи (исключая представление информации об организации и.
8.1.4 Can it still be factored? Factoring Completely I can factor out a common factor.

8.1.4 Can it still be factored? Factoring Completely I can factor out a common factor.
7-4 Remainder and Factor Theorems. Solve. x 3 + 4x 2 - 15x - 18 = 0 If x - 3 is a factor.

7-4 Remainder and Factor Theorems. Solve. x 3 + 4x x - 18 = 0 If x - 3 is a factor.
ALGEBRA II REMAINDER and FACTOR THEOREMS.

ALGEBRA II REMAINDER and FACTOR THEOREMS.
Inverse Functions Notes 3.8. I. Inverse Functions A.) B.) Ex. –

Inverse Functions Notes 3.8. I. Inverse Functions A.) B.) Ex. –
Equivalence Relations

Equivalence Relations

Similar presentations

Ads by Google