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9.6 Solving Rational Equations
4/30/2014
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Vocabulary 2 3 = 6 9 If π π = π π Then aβπ=πβπ Then 2β9=3β6 18 = 18
Rational Equation: Equation that shows two rational expressions or fractions are equal. 2 3 = 6 9 Then 2β9=3β6 18 = 18 Example: If π π = π π Then aβπ=πβπ Cross Multiply:
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Example 1 Solve for x: = π₯ 7 3β7=4βπ₯ 21=4π₯ 4 21 4 =π₯
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Example 2 2(π₯+3)=3βπ₯ 2π₯+6=3π₯ β2π₯ β2π₯ 6=π₯ 2 3 = 6 9 2β9=3β6 18 = 18
Solve for x: = π₯ π₯+3 To check: = 6 6+3 2 3 = 6 9 2β9=3β6 18 = 18 2(π₯+3)=3βπ₯ 2π₯+6=3π₯ β2π₯ β2π₯ 6=π₯
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Example 3 2 π₯β2 =π₯ π₯β2 2π₯β4= π₯ 2 β2π₯ β2π₯+4 β2π₯+4 0= π₯ 2 β4π₯+4
Solve for x: 2 π₯β2 = π₯ π₯β2 Or if you just look at the problem you can easily see that for the 2 fractions to be equal x must be 2! 2 π₯β2 =π₯ π₯β2 2π₯β4= π₯ 2 β2π₯ β2π₯ β2π₯+4 0= π₯ 2 β4π₯+4 0=(π₯β2)(π₯β2) 2=π₯ 2 is called an Extraneous solution because it leads to a division by 0 in the original equation. Always check for extraneous solutions! If x = 2, what happens to the denominator? Yes, it becomes 0 and you cannot divide by 0. So there is NO SOLUTION!
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Example 4 π₯ π₯β1 =2 π₯+5 π₯ 2 βπ₯ =2π₯+10 β2π₯β10 β2π₯β10 π₯ 2 β3π₯β10=0
Solve for x: π₯ π₯+5 = 2 π₯β1 To check: = 2 5β1 5 10 = 2 4 20=20 π₯ π₯β1 =2 π₯+5 π₯ 2 βπ₯ =2π₯+10 β2π₯β10 β2π₯β10 π₯ 2 β3π₯β10=0 (π₯β5)(π₯+2) =0 π₯= 5,β2 To check: β2 β2+5 = 2 β2β1 β2 3 = 2 β3
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Now weβre going to solve rational equations where one side contains addition or subtraction. Ex. 2 π₯ π₯ =2 How? By multiplying each term by the least common denominator (LCD). That will get rid of all fractions!!!
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Example 5 2 π₯ 2 + 3 π₯ =2 2+3π₯= 2π₯ 2 β2β3π₯ β3π₯β2 0 = 2π₯ 2 β3π₯β2
Solve for x: π₯ π₯ =2 Whatβs the LCD? LCD: π₯ 2 2 π₯ π₯ =2 2+3π₯= 2π₯ 2 β2β3π₯ β3π₯β2 0 = 2π₯ 2 β3π₯β2 0=(π₯β2)(2π₯+1) β 1 2 , 2=π₯ β’π₯ 2 β’π₯ 2 β’π₯ 2 1 2(-2) = 2 2 -4 1 -2 -3
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Example 6 Solve for x: 8+ 2 π₯β1 = 2π₯ π₯β1
8+ 2 π₯β1 = 2π₯ π₯β1 8(π₯β1)+ 2 π₯β1 (π₯β1)= 2π₯ π₯β1 (π₯β1) 8π₯β8+2=2π₯ 8π₯β6=2π₯ β2π₯+6 β2π₯+6 6π₯=6 π₯=1 LCD: π₯β1 Multiply each term by LCD Distributive Prop No Solution
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Example 7 Solve for x: 2 π₯β1 + 3 π₯ =2
LCD: π₯(π₯β1) Multiply each term by LCD Distributive Prop Factor using Big X
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Homework: 9.6 p.503 #21-41 odd only Since you can check your answers in the back of the book (and you should), you must show work!!! βIβm glad I know sign language, itβs pretty handyβ
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