Presentation is loading. Please wait.

Presentation is loading. Please wait.

Teacher Window 1676385 1777396 1776182 1576544 1776897 1776395 1777116 Window 1777489 1776490 1777267 1776201 1777323 1776111 1677097 1777597 1776879.

Similar presentations


Presentation on theme: "Teacher Window 1676385 1777396 1776182 1576544 1776897 1776395 1777116 Window 1777489 1776490 1777267 1776201 1777323 1776111 1677097 1777597 1776879."— Presentation transcript:

1 Teacher Window Window

2 Acids & bases Basic Chemistry

3 Definition of the pH in H2O
Water molecules dissociate to give hydronium (H3O+) hydroxide (OH-) and ions: (autoprotolysis or self-ionization) 2H2O H3O+ + OH- In neutral water at 25 °C, [H3O+] = [OH-] = 10-7 M. The P operator indicates -log10: pH = -log10([H3O+]) = 7 in neutral water Addition of acid to water leads to pH < 7, ACIDIC Addition of base to water leads to pH > 7, BASIC/ ALKALINE

4 Importance and applications
Some examples: pH of human blood ≈ ; pathology indicator Acids and bases are very important in industrial processes: As reactants: Ammonium nitrate production As catalysts: Formation of carbocations in oil refining Control of pH and understanding of acid-base chemistry is important in virtually all scientific research structure design & maintenance, safety…..

5 Lewis acids & bases Do not necessarily comprise a different group!
….A different feature is emphasized: Lewis base: electron-pair donor; Lewis acid: electron-pair acceptor Example:

6 Typical acids & bases Acids: Hydrogen halides (HF, HCl, HBr, HI)
Oxyacids (H2CO3, H3PO4, HNO3, HNO2…) (Lewis acids) High-charge (transition) metals (Al3+ , Cr3+, Fe3+) Bases Alkali and alkaline earth hydroxides (NaOH, KOH, Ca(OH)2…) Alkali and alkaline earth oxides (K2O, CaO, MgO…) Metal hydrides (LiH, NaH, KH….)

7 Acid dissociation constant Ka; pKa = -log(Ka)
The strength of acids and bases is described by their equilibrium constants General acid HA: HA+ H2O H3O+ + A- Equilibrium constant K: 𝐾= 𝑎 H3O+ 𝑎[A−] 𝑎 HA 𝑎[H2O] ≈ H3O+ A− HA H2O …But the concentration of water is almost constant: 𝐾 𝑎 =K H2O = H3O+ [A−] HA Acid dissociation constant Ka; pKa = -log(Ka)

8 General base B: B + H2O BH+ + OH- 𝐾 𝑏 = BH+ [OH−] B
The strength of acids and bases is described by their equilibrium constants General base B: B + H2O BH+ + OH- 𝐾 𝑏 = BH+ [OH−] B Base dissociation constant Kb; pKb = -log(Kb)

9 Acid-base conjugate pairs
HA/A- and B/BH+ are both acid/base conjugates: HA B A BH Acid Base Conjugate base Conjugate acid Reactions always proceed in the direction of the weaker acid and base! pKa + pKb = pKw ; The conjugate base of a strong acid is a very weak base (non-reactive); The conjugate base of a weak acid is a weak base

10 Acid-base conjugate pairs

11 While-> HF < HCl < HBr < HI?
Acid strength: Why? NH3 < H2O < HF ? Electronegativity: N (3.04) < O (3.44) < F (3.98) While-> HF < HCl < HBr < HI? Bond dissociation energies (kJ/mol): HI (287) < HBr (354) < HCl (419) < HF (543)

12 pH calculation in aqueous solutions
Strong acids (pKa < 0) dissociate completely: [H3O+] = CHA, pH = -log(CHA) Weak acids dissociate negligibly, so [HA] ≈ CHA 𝐾 𝑎 = H3O+ [A−] HA [H3O+] = [A-] = X X2 = Ka[Ha] ≈ KaCHA X = [H3O+] = 𝐾 𝑎 𝐶 𝐻𝐴 pH = −log 𝐾 𝑎 𝐶 𝐻𝐴 = 1 2 (𝐾 𝑎 −𝑙𝑜𝑔 (𝐶 𝐻𝐴 ))

13 Summary Reactions proceed to yield the weaker acid and base
Acids are proton donors or electron-pair acceptors Bases are proton acceptors or electron-pair donors pKa of acids and pKb of bases describes their strength; the lower pKa (pKb) the stronger the acid (base) The strength of a conjugate base is easily deduced from the strength of the acid: pKa + pKb = pKw Reactions proceed to yield the weaker acid and base The pH of a strong acid in aqueous solution: pH ≈ -log(CHA) The pH of a weak acid in aqueous solution: pH ≈ (𝐾 𝑎 −𝑙𝑜𝑔 (𝐶 𝐻𝐴 ))

14 Let’s look at Henry’s law…
The concentration of a gas dissolved in any liquid is proportional to it pressure in the atmosphere/gas in contact with the liquid: C = KP, with K the constant, C the concentration in the liquid, and P the partial pressure Henry’s constants for water at 25 °C Gas K (mol L-1 atm-1) CO2­­­­­­­­­­­­ 3.4×10-2 N2 7×10-4 He 3.7×10-4 But note: 𝐻 2 𝐶 𝑂 3 (𝑎𝑞) 𝐶 𝑂 2(𝑎𝑞) =1.8 ×10 −3 Finally: for H2CO3, Ka1 = 2.5×10-4; Ka2 =4.7×10-11


Download ppt "Teacher Window 1676385 1777396 1776182 1576544 1776897 1776395 1777116 Window 1777489 1776490 1777267 1776201 1777323 1776111 1677097 1777597 1776879."

Similar presentations


Ads by Google