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NATIONAL CENTER FOR CASE STUDY TEACHING IN SCIENCE

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Presentation on theme: "NATIONAL CENTER FOR CASE STUDY TEACHING IN SCIENCE"— Presentation transcript:

1 NATIONAL CENTER FOR CASE STUDY TEACHING IN SCIENCE
A Presentation to Accompany the Case Study: Life Tables, Darwin’s Finches, and the Dynamics of Small Island Populations A Case Study Adaptation of Grant & Grant 1992 Whitley R Lehto, Shannon M Murphy, Mayra C Vidal, and Robin M Tinghitella University of Denver, Denver, CO

2 Describing and Measuring Populations
Different ways we measure and estimate populations: Their size (mark and recapture) Their relative abundance Their distribution (dispersion) Can describe the dynamics of populations with demography Different measured or calculated quantities tell us how populations change and grow: Age Structure Mortality Life Expectancy Reproductive Rate

3 Survivorship Curves Graphical representation of the number of individuals surviving to each age for a group (within a population or species). Survivorship Curve for Dall Mountain Sheep Data from Murie 1944

4 Life Tables Standardized presentation of age structure data
Cohort life table: tracks a group of individuals born at the same time until the last individual dies Static life table: sample of population and ages of individuals at one time point A life table for Dall sheep at Denali National Park, Alaska (data from Murie, 1944) Age in Years (X) Number Alive at Start of Age (Nx) Proportion Surviving as Fraction of Newborn (Lx) Number Dying in Age Interval (Dx) 608 1.000 121 1 487 0.801 7 2 480 0.789 8 3 472 0.776 4 465 0.765 18 5 447 0.735 28 6 419 0.689 29 390 0.641 42 348 0.572 80 9 268 0.441 114 10 154 0.253 95 11 59 0.097 55 12 0.0066 13 0.003 14 0.000

5 Life Tables Warm-up Life tables can provide information on survivorship, deaths, and mortality rate. How do we calculate these? Find a partner. Fill in the table on the LIFE TABLES WARM-UP using the provided formulas and their descriptions.

6 Isolated Populations Often small and experience unique ecology
Island populations How they persist despite genetic drift and variable environments is a long-standing question in ecology and evolutionary biology

7 Case Study: Background
Galapagos Island Finches Grant and Grant 1992 Galapagos Islands Geospiza scandens (Common cactus-finch) Daphne Major Geospiza fortis (Medium ground-finch)

8 Finch Life Tables: Cohorts of Different Species
Complete Table 3 in Part II of the case study handout. Values from life table warm-up were taken from the finch life tables; those values are filled in for you in Table 2. MAKE SURE YOU GOT THE SAME ANSWERS! Complete the Questions 1–4. #4: Remember all graph components: don’t forget the “year” labels and arrows G. scandens G. fortis

9 Survivorship in a Changing Environment: Same-Species Cohorts Differing in Year
View the graph in Part III of the handout. Complete Questions 1–4.

10 Net Reproductive Rate = R0
Reproduction: Same-Species Cohorts Differing in Year Net Reproductive Rate = R0 The expected number of (female) offspring produced by an average (female) individual over its lifetime If R0>1, population is increasing If R0=1, population is stable If R0<1, population is decreasing

11 Reproduction: Same-Species Cohorts Differing in Year
Complete Part IV of the case study handout and answer the questions. Note: The Grants tracked the reproduction of a subset of the cohorts they were studying by tracking the fledglings each year.

12 lx=Proportion Surviving to x (Nx/N0)
Life Tables Warm-up Age Class (x) Number Alive (Nx) lx dx qx 82  1.00 1 42 2 25 3 17 lx=Proportion Surviving to x (Nx/N0) the proportion of individuals surviving to each age class with respect to the initial number of individuals

13 lx=Proportion Surviving to x (Nx/N0)
Life Tables Warm-up Age Class (x) Number Alive (Nx) lx dx qx 82  1.00 1 42  0.512 2 25  0.305 3 17 0.207  N0/N0 = 82/82 = 1.00 N1/N0 = 42/82 = 0.512 N2/N0 = 25/82 = 0.305 lx=Proportion Surviving to x (Nx/N0)

14 the proportion of individuals dying between age classes x and x+1
Life Tables Warm-up Age Class (x) Number Alive (Nx) lx dx qx 82  1.00  0.488 1 42  0.512 2 25  0.305 3 17 0.207  dx=Proportion Dying between x and x+1 (lx-lx+1) the proportion of individuals dying between age classes x and x+1

15 Life Tables Warm-up dx=Proportion Dying between x and x+1 (lx-lx+1)
Age Class (x) Number Alive (Nx) lx dx qx 82  1.00  0.488 1 42  0.512 0.207  2 25  0.305  0.098 3 17 …  l0-l1 = = 0.488 l1-l2 = = 0.207 l2-l3 = = 0.098 Question to pose to students: Why can’t you calculate the last one of these? That was shaded in on your warm up for a reason. Answer: Need lx for x=4 to calculate it. dx=Proportion Dying between x and x+1 (lx-lx+1)

16 qx=Mortality Rate (dx/lx)
Life Tables Warm-up Age Class (x) Number Alive (Nx) lx dx qx 82  1.00  0.488 0.488 1 42  0.512 0.207  2 25  0.305  0.098 3 17 …  qx=Mortality Rate (dx/lx) the proportion dying in a given age class as compared to the proportion surviving to that age class

17 qx=Mortality Rate (dx/lx)
Life Tables Warm-up Age Class (x) Number Alive (Nx) lx dx qx 82  1.00  0.488 0.488 1 42  0.512 0.207  0.405 2 25  0.305  0.098 0.302 3 17 …  d0/l0 = 0.488/1.00 = 0.488 d1/l1 = 0.207/0.512 = 0.405 d2/l2 = 0.098/0.305 = 0.302 qx=Mortality Rate (dx/lx)

18 Reproduction: Same-Species Cohorts Differing in Year
G. scandens 1978 cohort females Age Class (x) Number Alive (Nx) lx mx lxmx 90 1.000 0.000 1 39 0.433 0.051 2 33 0.367 0.667 3 30 0.333 1.500 N0/N0 = 90/90 = 1.00 N1/N0 = 39/90 = 0.433 N2/N0 = 33/90 = 0.367 lx=Proportion Surviving to x (Nx/N0)

19 Reproduction: Same-Species Cohorts Differing in Year
G. scandens 1978 cohort females Age Class (x) Number Alive (Nx) lx mx lxmx 90 1.000 0.000 1 39 0.433 0.051 0.022 2 33 0.367 0.667 0.245 3 30 0.333 1.500 ? l0m0 = 1.000*0.000 = 0.000 l1m1 = 0.433*0.051 = 0.022 l2m2 = 0.367*0.667 = 0.245

20 Reproduction: Same-Species Cohorts Differing in Year
Σ(lx*mx*x) Generation Time Tc = Σ(lx*mx) G. scandens 1978 cohort females l0m0 *0= 0.000*0= 0.000 Age Class (x) Number Alive (Nx) lx mx lxmx 90 1.000 0.000 1 39 0.433 0.051 0.022 2 33 0.367 0.667 0.245 3 30 0.333 1.500 l1m1*1 = 0.022*1 = 0.022 l2m2 *2= 0.245*2 = 0.490 + l12m12 *12= . . . Numerator of Tc

21 Image Credits Slide 1- Left: Image of Charles Darwin taken in Photo credit: Herbert Rose Barraud ( ). Right: Image of Peter and Rosemary Grant conducting research on Daphne Major in the Galapagos Islands. Photo credit: K.T. Grant. Original caption: “Peter and Rosemary Grant on Daphne Major, capturing and measuring finches. Their work documented the evolution of finches in the genus Geospiza in real time.” Appeared in New York Times article “In Darwin’s Footsteps” by Jonathan Weiner, published online Slide 3-Dall sheep. Slide 4-Dall sheep. Slide 6-Image of different habitat islands (as described in Wilson and Bossert 1971). Slide 7 Map of Galapagos Islands (Ecuador, South America). (Image on the left.) Photo credit: Common Cactus Finch Geospiza scandens Santa Cruz Island, Galapagos Islands. (Upper image on the right.) Photo credit: Medium Ground Finch Geospiza fortis Santa Cruz, Galapagos. (Lower image on the right.) Photo credit: Slide 8-Images of G. fortis and G. scandens from Grant, PR and Grant, BR Conspecific versus heterospecific gene exchange between populations of Darwin's finches. Phil. Trans. R. Soc. B, 365:


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