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Functions composite
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Starter: find the inverse functions of
Composite functions KUS objectives BAT Find composite functions BAT Find the domain and range of composite functions Starter: find the inverse functions of π π₯ = 1 π₯β2 π π₯ =2 (π₯β7) 2 β π₯ = ( sin π₯ β1) 2 +3
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Find the cost of using 100 cubic feet
WB1 A gas meter indicates the amount of gas in cubic feet used by a consumer. The number of therms of heat from x cubic feet of gas is given by the function f where π π₯ = π₯, π₯ > 0 A particular gas companyβs charge in Β£ for t therms is given by the function g where π π‘ = π‘ Find the cost of using 100 cubic feet Find a single rule for working out the cost given the number of cubic feet of gas used Β£56.36 gf(x) = x + 15
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A composite function is a βfunction of a functionβ e.g.
Notes A composite function is a βfunction of a functionβ e.g. π π =ππ+π π π = π π π 3 5 7 9 β¦ π(π) 9 25 49 81 β¦ ππ(π) 1 2 3 4 β¦
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π π =ππ+π π π = π π 1 2 3 4 β¦ π 5 7 9 π(π) 25 49 81 ππ(π)
WB2 π π₯ =2π₯+1 and π π₯ = π₯ a) find ππ π₯ and ππ π₯ b) find ππ and ππ 4 1 2 3 4 β¦ π 5 7 9 π(π) 25 49 81 ππ(π) π π =ππ+π π π = π π ππ π = π ππ+π = ππ+π π ππ π =π π = ππ and ππ π =π π π =π π π +π ππ π =π ππ =ππ
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a) ππ π₯ ππ 0 b) ππ π₯ ππ 0 Find: ππ π₯ =3 π π β1 ππ 0 =0β1=β1 ππ π₯ =π₯β1
WB3ab π π =ππβπ π π = π π Find: a) ππ π₯ ππ 0 ππ π₯ = (3π₯β1) 3 ππ 0 = (3(0)β1) 3 =β 1 3 b) ππ π₯ ππ 0 ππ π₯ =3 π π β1 ππ π₯ =π₯β1 ππ 0 =0β1=β1
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c) ππ π₯ ππ 1 3 d) ππ π₯ ππ 1 3 Find: ππ π₯ =3(3π₯β1)β1 ππ π₯ =9π₯β4
WB3cd π π =ππβπ π π = π π Find: c) ππ π₯ ππ 1 3 ππ = β4=β1 ππ π₯ =3(3π₯β1)β1 ππ π₯ =9π₯β4 d) ππ π₯ ππ 1 3 ππ π₯ = π/π π ππ = 1/3 9 = 1 27 ππ π₯ = π₯ 9
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a) ππ π₯ ππ 1 2 b) ππ π₯ ππ β3 Find: ππ π₯ = π ( π π +π)+π
WB4ab π π = π π +π π π = π π+π Find: a) ππ π₯ ππ 1 2 ππ π₯ = π ( π π +π)+π ππ = = 4 9 ππ π₯ = 1 π₯ 2 +2 b) ππ π₯ ππ β3 ππ π₯ = π π+π π +π ππ β3 = π βπ+π π +π= π π ππ π₯ = π π+π π +π
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c) π π β1 π₯ π π β1 6 d) π π β1 π₯ π π β1 10 Find:
WB4cd π π = π π +π π π = π π+π Find: π βπ π = π π βπ π βπ π = πβπ c) π π β1 π₯ π π β1 6 π π β1 π₯ = π π βπ π +π ππ 6 = β = 61 36 π π β1 π₯ = 1 π₯ 2 β 2 π₯ +2 d) π π β1 π₯ π π β1 10 π π β1 π₯ = πβπ π +π π π β =10 π π β1 π₯ =π of course!
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1 2π₯+1 π₯ 8β 1 π₯ 1 8 βπ₯ (8βπ₯) 2 ππ π ππ π ππ π 2 π₯ 2 +1 4 π₯ 2 +4π₯+1
WB π π = π π π π =ππ+π π π =πβπ π π = π π Find the composite functions that correspond to: 1 2π₯+1 (8βπ₯) 2 π₯ ππ π ππ π ππ π 8β 1 π₯ 2 π₯ 2 +1 4 π₯ 2 +4π₯+1 ππ π ππ π ππ π 1 8 βπ₯ π₯ 4 7β 2π₯ 2 ππ π ππ π πππ π
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Challenge work in pairs
Choose four integers between 1 and 9 inclusive, called a, b, c, d Write the functions π π₯ = π ππ₯+π and π π₯ = ln (ππ₯+π) Find a) fg(x) b) the inverse β¦ of your neighbours functions
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Composite Domain and range
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Sketch the graph of ππ π₯ and state its domain and range
WB π π = π π π π =π+π Sketch the graph of ππ π₯ and state its domain and range ππ π = (π+π) π Domain π π πΉ Range π>π
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Sketch the graph of ππ π₯ and state its domain and range
WB π π =πβπ π π = ππ Sketch the graph of ππ π₯ and state its domain and range ππ π = π(πβπ) ππ π = ππβπ Domain π>π Range π>π
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ππ π₯ = 2π π(π₯) ππ π₯ = 2π ln 3π₯β2 ππ π₯ =2 3π₯β2 =6π₯ β4
WB The function f is defined by π:π₯β ln 3π₯β2 , π₯ββ, π₯β₯ 2 3 Β The function g is defined by π:π₯β 2π π₯ , π₯ββ a) Find ππ(π₯), giving your answer in its simplest form b) Find the range of ππ(π₯) ππ π₯ = 2π π(π₯) ππ π₯ = 2π ln 3π₯β2 ππ π₯ =2 3π₯β2 =6π₯ β4 This is a linear graph Range ππ(π₯)ββ
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ππ π₯ = 4π 3 ln π₯ ππ π₯ = 4π ln π₯ 3 ππ π₯ =4 π₯ 3 π₯ βπ
WB The function f has domain [ββ, β] and is defined by π π₯ =4 π π₯ The function g has domain [1, β] and is defined by π π₯ =3 ln π₯ Explain why ππ β3 does not exist Find in its simplest form an expression for ππ π₯ stating its domain and range ππ β3 =π( 3 ln (β3) ) but ln (-3) is not possible ππ π₯ = 4π 3 ln π₯ Rules of logarithms ππ π₯ = 4π ln π₯ 3 ππ π₯ =4 π₯ π₯ βπ
Range ππ(π₯)ββ
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π βπ π = π π βπ a) ππ π₯ = 6 b) π π β1 π₯ =2 Solve: ππ π₯ =ππ π π βπ +π
WB10ab π π = π π βπ π π =ππ (π+π) Solve: π βπ π = π π βπ a) ππ π₯ = 6 ππ π₯ =ππ π π βπ +π So ππ π₯ = ln π₯ 2 β4 =6 π₯ 2 β4 = π 6 π₯= π 6 +4 b) π π β1 π₯ =2 π π β1 π₯ = π π βπ π βπ So π π β1 π₯ = π π₯ β1 2 β3=2 π π₯ β1 2 =5 π π₯ =1+ 5 π₯= ln
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π βπ π = πβπ a) ππ π₯ =1 b) ππ β1 π₯ =2 Solve: ππ π₯ = πβ π π π π
WB11ab π π = πβ π π π π =π π π Solve: π βπ π = πβπ a) ππ π₯ =1 ππ π₯ = πβ π π π π So ππ π₯ =3β9 π 2π₯ =1 π 2π₯ = 2 9 π₯= ln 2 9 b) ππ β1 π₯ =2 ππ β1 π₯ =π π πβπ So π π β1 π₯ =π π πβπ =2 πβπ = ln 2 3 π₯=3β ln
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π β1 π₯ = 4βπ₯ , π₯<4 a) ff β6 =4β 4β β6 2 2 =4β β32 2 =β1020
WB12 exam Q π π₯ =4β π₯ xβ€0 Evaluate ππ(β6) F Find an expression for π β1 π₯ Write the domain and range of π β1 π₯ a) ff β6 =4β 4β β =4β β =β1020 b) Let x=4β π¦ 2 β π¦ 2 =4βπ₯ β π¦= 4βπ₯ π β1 π₯ = 4βπ₯ , π₯<4 c) Domain π₯<4 range π₯β€0
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a) Range π π₯ β₯0 b) ππ π₯ =π 1 π₯ = 1 π₯ β10 c) 1 π₯ β10 =3 β 1 π₯ β10=9
WB13 exam Q the functions f and g are defined by π π₯ = π₯β xβ₯ g π₯ = 1 π₯ xβπ
, π₯β 0 a) State the range of f(x) b) Find ππ π₯ c) Solve the equation ππ π₯ = d) find the inverse function π β1 π₯ a) Range π π₯ β₯0 b) ππ π₯ =π 1 π₯ = 1 π₯ β10 c) π₯ β10 =3 β π₯ β10=9 β π₯= 1 19 π) Let π₯= π¦β10 β π β1 π₯ = π₯ 2 +10
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One thing to improve is β
KUS objectives BAT Find composite functions BAT Find the domain and range of composite functions self-assess One thing learned is β One thing to improve is β
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