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2018 Geometry Bootcamp 2018 Circles, Geometric Measurement, and Geometric Properties with Equations 2018 Geometry Bootcamp
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MAFS.912.G-C.1.1 Eric explains that all circles are similar using the argument shown. Let there be two circles, circle A and circle B. There exists a translation that can be performed on circle A such that it will have the same center as circle B. Thus, there exists a sequence of transformations that can be performed on circle A to obtain circle B. Therefore, circle A is similar to circle B. Since circle A and circle B can be any circles, all circles are similar. Which statement could be step 3 of the argument? There exists a reflection that can be performed on circle A such that it will have the same radius as circle B. There exists a dilation that can be performed on circle A such that it will have the same radius as circle B. There exists a reflection that can be performed on circle B such that it will have the same radius as circle A. There exists a dilation that can be performed on circle B such that it will have the same radius as circle A. Groups 1, 2, and 3 B
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2018 Geometry Bootcamp MAFS.912.G-C.1.1 Which describes how Circle C can be transformed to show that Circle D is a similar figure? translation of Circle πΆ: (π₯, π¦)β(π₯+3, π¦+8); dilation of the image with center (4, β1) and scale factor 6 translation of Circle πΆ: (π₯, π¦)β(π₯+8, π¦+3); dilation of the image with center (4, β1) and scale factor 1 6 translation of Circle πΆ: (π₯, π¦)β(π₯+3, π¦+8); dilation of the image with center (4, β1) and scale factor 1 6 translation of Circle πΆ: (π₯, π¦)β(π₯+8, π¦+3); dilation of the image with center (4, β1) and scale factor 6 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.1 Circle π½ is located in the first quadrant with center π, π and radius π . Felipe transforms circle π½ to prove that it is similar to any circle centered at the origin with radius π‘. Which sequence of transformations did Felipe use? Translate Circle J by π₯, π¦ β π₯+π, π¦+π and dilate by a factor of π‘ π . Translate Circle J by π₯, π¦ β π₯+π, π¦+π and dilate by a factor of π π‘ . Translate Circle J by π₯, π¦ β π₯βπ, π¦βπ and dilate by a factor of π‘ π . Translate Circle J by π₯, π¦ β π₯βπ, π¦βπ and dilate by a factor of π π‘ . Groups 2 and 3 C 2018 Geometry Bootcamp
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MAFS.912.G-C.1.2 In the diagram below, π π΄π΅πΆ =268Β°.
2018 Geometry Bootcamp MAFS.912.G-C.1.2 In the diagram below, π π΄π΅πΆ =268Β°. What is the number of degrees in the measure of β π΄π΅πΆ? 134Β° 92Β° 68Β° 46Β° Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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MAFS.912.G-C.1.2 The diagram shows circle πΆ.
2018 Geometry Bootcamp MAFS.912.G-C.1.2 The diagram shows circle πΆ. Which of these statements is true? mβ ππΎπ= 1 2 mβ πππ mβ ππΎπ= 1 2 mβ ππΆπ mβ ππΎπ=mβ ππΆπ mβ ππΎπ=2mβ ππΆπ Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.2 πΆπΎ is the diameter of Circle π. If π π½πΆ =19π₯Β° and π π½πΎ =[9 π₯+2 β6]Β°, find the value of π₯. 4 5 5 6 4 6 Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.2 Maggie and Wei are measuring the distance across a circular fountain indirectly as shown in the diagram. They find that the length of π
π is 15 meters and the length of ππ is 9 meters. π
π is tangent to circle πΉ and point π is on πΉπ . To the nearest meter, what is the diameter of the fountain? Enter your answer in the box. Groups 1, 2, and 3 16 2018 Geometry Bootcamp
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MAFS.912.G-C.1.2 Points A, B, and D lie on circle C.
2018 Geometry Bootcamp MAFS.912.G-C.1.2 Points A, B, and D lie on circle C. Determine the measure of the indicated angles given that πβ π΄= 30Β°. Enter the measures in the boxes. πβ π΅πΆπ·= 60Β° Groups 1, 2, and 3 πβ π΄π΅π·= 90Β° 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.2 The figure below shows concentric circles, both centered at O. Chord XY is tangent to the smaller circle. The radius of the larger circle is 15 cm. The radius of the smaller circle is 12 cm. What is the length of chord XY? 27 cm 24 cm 18 cm 10 cm Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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MAFS.912.G-C.1.3 Quadrilateral πΈπΉπΊπ» is inscribed in a circle as shown.
2018 Geometry Bootcamp MAFS.912.G-C.1.3 Quadrilateral πΈπΉπΊπ» is inscribed in a circle as shown. mβ πΉ= 4π₯+10 Β°, mβ πΊ= 2π₯β5 Β°, and mβ π»= 3π₯β5 Β°. What is the value of π₯? 20 25 38 40 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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MAFS.912.G-C.1.3 Quadrilateral FGHJ and circle O are shown.
2018 Geometry Bootcamp MAFS.912.G-C.1.3 Quadrilateral FGHJ and circle O are shown. Given: mβ π½πΉπΊ=56Β° Which statement, if true, would help prove that quadrilateral FGHJ is inscribed in Circle O and why? mβ πΊπ»π½=56Β°; for a quadrilateral inscribed in a circle, opposite angles are congruent. mβ πΉπΊπ»=124Β°; for a quadrilateral inscribed in a circle, adjacent angles are supplementary. mβ πΊπ»π½=124Β°; for a quadrilateral inscribed in a circle, opposite angles are supplementary. mβ πΉπΊπ»=56Β°; for a quadrilateral inscribed in a circle, adjacent angles are congruent. Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.3 In the circle shown, the measure of β πΆ is 110Β°, and the measure of β π· is 80Β°. Match the correct angle measure to each box for β A and β B. 70Β° 80Β° 110Β° 140Β° 220Β° 100Β° Measure of β A Measure of β B 70Β° Groups 1, 2, and 3 100Β° 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.1.3 Select all statements that are valid when a triangle is inscribed in a circle. the circle is circumscribed about the triangle. the perpendicular bisectors of the triangle may be constructed to find the center of the circle. the center of the circumscribed circle must always be in the interior of the triangle. the vertices of the triangle are equidistant from the center of the circle. the triangle must be isosceles. Groups 2 and 3 2018 Geometry Bootcamp
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MAFS.912.G-C.2.5 Points A, B, D, and E lie on circle C.
2018 Geometry Bootcamp MAFS.912.G-C.2.5 Points A, B, D, and E lie on circle C. What is the length of arc ADB? 8Ο 3 in. 4Ο in. 16 3 Ο in. 8Ο in. Groups 1, 2, and 3 A 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.2.5 A sector is part of a circleβs area that is defined by a central angle. The ratio of the sectorβs area, π΄, to the circleβs area, π π 2 , is identical to the ratio of the central angle, π, to the total measure of the circle, 360Β°. Which option represents the formula for the area of a sector? π΄= 360Β° π π π 2 π΄=ππ π 2 π΄=360Β°π π 2 π΄= π 360Β° π π 2 Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-C.2.5 A spotlight has a beam that travels 100 feet and covers an area intercepted by an 84Β° angle, as shown. To the nearest square foot, what area does the spotlight cover? Enter your answer in the box. 7, 330 Groups 1, 2, and 3 2018 Geometry Bootcamp
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Subtended Central Angle
2018 Geometry Bootcamp MAFS.912.G-C.2.5 The circle with center πΉ is divided into sectors. In circle πΉ, πΈπ΅ is a diameter. The length of πΉπ΅ is 3 units Drag and drop each arc length to its subtended central angle. Subtended Central Angle Arc Length in radians β π΄πΉπ΅ β π΅πΉπΆ β πΆπΉπ· β π΄πΉπΈ 2π 3π 4 Groups 2 and 3 π 2 π 2 π 2π 3π 4 π 4 π 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.1 To find the formula for the area of a circle, the circle can be cut into βslices,β as indicated below. Which statement best describes the process being used? To find the area of a circle, rearrange the pieces to form a βparallelogramβ with a base of ππ and a height of π. To find the area of a circle, rearrange the pieces to form a βparallelogramβ with a base of 2ππ and a height of π. To find the area of a circle, rearrange the pieces to form a βparallelogramβ with a base of ππ and a height of π. To find the area of a circle, rearrange the pieces to form a βparallelogramβ with a base of 1 2 ππ and a height of 2π. Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.1 The cylinder and the cone shown below have the same height, and their bases have the same radius. How does the volume of the cylinder π ππ¦π compare to the volume of the cone π ππππ ? π ππ¦π =2 π ππππ π ππ¦π = 1 3 π ππππ π ππ¦π β π ππππ =3 π ππππ π ππ¦π β π ππππ =2 π ππππ Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.1 A circle with radius π is divided into sectors as shown. The sectors are arranged in a shape that resembles a parallelogram. Which of the given statements are true? Select all that apply. The length of base ππ of the parallelogram πππ
π is approximately equal to 1 2 ππ. The length of base ππ of the parallelogram πππ
π is approximately equal to ππ. The length of base ππ of the parallelogram πππ
π is approximately equal to 2ππ. The height of the parallelogram πππ
π is approximately equal to π. The height of the parallelogram πππ
π is approximately equal to π. The area of the parallelogram πππ
π is approximately equal to 2ππ. The area of the parallelogram πππ
π is approximately equal to 2π π 2 . The area of the parallelogram πππ
π is approximately equal to π π 2 . Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 An ice cream waffle cone can be modeled by a right circular cone with a base diameter of 6.6 centimeters and a volume of 54.45π; cubic centimeters. What is the number of centimeters in the height of the waffle cone? 3 3 4 5 15 24 3 4 Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 To completely cover a spherical ball, a ball company uses a total area of 36 square inches of material. What is the maximum volume the ball can have? 27π cubic inches 36 π cubic inches 36 π cubic inches 27 π cubic inches Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 A regular pyramid has a square base. The perimeter of the base is 36 inches and the height of the pyramid is 15 inches. What is the volume of the pyramid in cubic inches? 180 405 540 1215 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 A soft drink company wants to increase the volume of the cylindrical can they sell soft drinks in by 25%. The company wants to keep the 5-inch height of the can the same. The radius of the can is currently 2.5 inches. Approximately how much should the radius of the can be increased? 0.245 inches 0.250 inches 0.278 inches 0.295 inches Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 Trevon is shopping for an art project for his class of third graders. He wants each of his 30 students to have a ball of modeling clay 10 centimeters in diameter. The modeling clay is sold in cylindrical rolls that are 15 centimeters long and 4 centimeters in diameter. How many rolls of clay does he need to buy? Enter your answer in the box. 84 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 The table shows the approximate measurements of the Great Pyramid of Giza in Egypt and the Pyramid of Kukulcan in Mexico. Pyramid Height (meters) Area of Base (square meters) Great Pyramid of Giza 147 52,900 Pyramid of Kukulcan 30 3,025 Approximately what is the difference between the volume of the Great Pyramid of Giza and the volume of the Pyramid of Kukulcan? Groups 1, 2, and 3 1,945,000 cubic meters 2,562,000 cubic meters 5,835,000 cubic meters 7,686,000 cubic meters B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 Anders is using coats to make plaster figures. He has a cylinder cast that has a diameter of 8 inches and is 24 inches tall. Anders uses a cone- shaped container with a diameter of 12 inches and a height of 16 inches to fill his casts. How many cone-shaped containers full of plaster will he need to completely fill the cylinder cast? Enter your answer in the box. 2 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.1.3 A popcorn container is made from a cone with a portion of the cone removed and sealed, as shown. The removed portion of the cone has a height of 1 3 π. Create an expression, using π, that represents the volume, in cubic centimeters, of the popcorn container. 1 3 π π πβ π π π 3 Groups 2 and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.2.4 The figure shows a plane slicing through a cone. The plane is neither parallel nor perpendicular to the base of the cone, and the plane does not intersect the base of the cone. What is the shape of the cross section created by the slice? Circle Ellipse Parabola Triangle Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.2.4 On the coordinate plane, β³ART is shown with points π
and π plotted on the π¦-axis. What three-dimensional figure is created by rotating β³ART around the π¦-axis? Cone Sphere Cylinder Pyramid Groups 1, 2, and 3 A 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GMD.2.4 Which solid of revolution is produced by rotating the shape below 360Β° about the given axis? A B C D Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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MAFS.912.G-GMD.2.4 Which of the following two-dimensional cross sections are circles? Select all that apply. any cross section of a sphere horizontal cross section of a cube cross section of a cone parallel to its base cross section of a cone perpendicular to its base cross section of a right cylinder parallel to its base cross section of a pyramid perpendicular to its base Groups 1, 2, and 3
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MAFS.912.G-GMD.2.4 What are the possible cross sections of a right circular cone? Select all that apply. Ellipse Triangle Circle Parabola Rectangle Groups 2 and 3
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2018 Geometry Bootcamp MAFS.912.G-GMD.2.4 A triangle has vertices at (0, 0), (0, 9), and (4, 0). If the triangle is revolved about the π₯-axis, what 3-dimensional solid is formed? a pyramid with a square base of 4 units by 4 units and a height of 9 units a pyramid with a square base of 9 units by 9 units and a height of 4 units a cone with a diameter of 8 units and a height of 9 units a cone with a diameter of 18 units and a height of 4 units Groups 2 and 3 D 2018 Geometry Bootcamp
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MAFS.912.G-GPE.1.1 A circle has its center at (β2, 3) and point (4, 6) is on its circumference. What is the correct written equation of the circle? π₯ π¦β2 2 =85 π₯β π¦+2 2 =45 π₯β π¦+3 2 =85 π₯ π¦β3 2 =45 Groups 1, 2, and 3 D
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2018 Geometry Bootcamp MAFS.912.G-GPE.1.1 Write the equation of a circle with a radius of 5 units and a center at (-3, 4)? π₯ π¦β4 2 =25 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.1.1 In the π₯π¦βcoordinate plane shown, points B, E, G, and I are on the circle with center H. Part A What is the equation of the circle with center H? π₯β π¦β2 2 = 10 π₯β π¦β2 2 =10 π₯ π¦+2 2 = 10 π₯ π¦+2 2 =10 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.1.1 In the π₯π¦βcoordinate plane shown, points B, E, G, and I are on the circle with center H. Part B The equation π₯ 2 + π¦ 2 β6π₯+2π¦+5=0 represents the circle with which center? B E G I Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.1.1 What is the radius of the circle with equation π₯ 2 + π¦ 2 +6π₯=54+2π¦? 8 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.1.1 The equation π₯ 2 + π¦ 2 β 4π₯ + 2π¦ = π describes a circle. Part A Determine the y-coordinate of the center of the circle. Enter your answer in the box. -1 Part B The radius of the circle is 7 units. What is the value of b in the equation? Enter your answer in the box. Groups 2 and 3 44 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.4 Select the responses that correctly complete the sentence. Given β³ABC with A(5, 4), B(2, β2), and C(7, β1). β³ABC is classified as because Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.4 β³RST has vertices at R(7, β4), S(12, β12), and T(2, β12). What type of triangle is β³RST? Equilateral Isosceles Scalene Right Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.4 The vertices of quadrilateral EFGH are E(β7, 3), F(β4, 6), G(5, β3), and H(2, β6). What kind of quadrilateral is EFGH? A trapezoid B square C rectangle that is not a square D rhombus that is not a square Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.4 Quadrilateral π
πππ has vertices R(1, 3), S(4, 1), T(1, -3) and U(-2, β1). Which statement about quadrilateral π
πππ is true? Since the diagonals of quadrilateral π
πππ are not congruent, it is not a rectangle. Since the adjacent sides of quadrilateral π
πππ have equal slopes, it is not a rectangle. Since the diagonals of quadrilateral π
πππ are congruent, it is a rectangle. Since the adjacent sides of quadrilateral π
πππ have equal slopes that are negative reciprocals, it is a rectangle. Groups 2 and 3 A 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.5 Consider the line given by the equation 5π₯+2π¦=8. Which of the following gives the equation of a line parallel to the given line but with a different π¦βintercept? y= β5π₯ 2 +4 y= β5π₯ 2 +8 y= β2π₯ 5 +4 y= β2π₯ 5 +8 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.5 Given the line 3π₯β9π¦=18, what is the equation of a line that is perpendicular to the given line at the given lineβs π₯βintercept? π¦= 1 3 π₯β2 π¦= 1 3 π₯+6 π¦=β3π₯+6 π¦=β3π₯+18 Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.5 What is the equation of the line through (3, 7) that is perpendicular to the line through points (-1, -2) and (5, 3)? π=β π π π+ ππ π Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.5 Create the equation of a line that is perpendicular to 2π¦= π₯ and passes through the point β2, 8 . π=βππ+π Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.5 A line segment has endpoints π½(2, 4) and πΏ(6, 8). The point πΎ is the midpoint of π½πΏ. What is an equation of a line perpendicular to π½πΏ and passing through πΎ? π¦ = βπ₯ + 10 π¦ = βπ₯ β 10 π¦ = π₯ + 2 π¦ = π₯ β 2 Groups 2 and 3 A 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.6 On a coordinate plane, the endpoints of line segment π½πΎ are π½(β10, 12) and πΎ(8, β12). Point πΏ lies on segment π½πΎ and divides it into two segments such that the ratio of π½πΏ to πΏπΎ is 5:1. What are the coordinates of point πΏ? β7, 8 β6.4, 7.2 4.4, β7.2 5, β8 Groups 1, 2, and 3 D 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.6 In the π₯π¦βcoordinate plane, the coordinates of point π are (β2, β6), and the coordinates of point π are (18, 9). Point π lies on line segment ππ so that the ratio of the distance from point π to point π to the distance from point π to point π is 2 to 3. What are the coordinates of point π? Enter your answer in the boxes. The coordinates of point π are , 6 Groups 1, 2, and 3 2018 Geometry Bootcamp
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MAFS.912.G-GPE.2.6 A line segment has endpoints π(β9, β4) and π(6, 5). Point π
lies on ππ such as the ratio of ππ
to π
π is 2:1. What are the coordinates of point π
? Enter your answer in the boxes. The coordinates of point π
are , 1 2 Groups 1, 2, and 3
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.6 Point π is between π·(2, 5) and πΉ(5, β1). What are the coordinates of π along the directed π·πΉ if the ratio of π·π to ππΉ is 1:2? Enter the correct coordinates in the boxes. Value of the π₯βcoordinate: Value of the π¦βcoordinate: 3 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.6 Line segment π½πΎ in the π₯π¦-coordinate plane has endpoints with coordinates (β4, 11) and (8, β1). What are two possible locations for point π so that π divides π½πΎ into two parts with lengths in a ratio of 1:3? Indicate both locations. β2, 9 β1, 8 0, 7 1, 6 3, 4 4, 3 5, 2 (6, 1) Groups 2 and 3 B, G 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 On the set of axes below, the vertices of βπππ
have coordinates π β6, 7 , π 2, 1 and π
(β1, β3). What is the area of βπππ
? 10 20 25 50 Groups 1, 2, and 3 C 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 Find the perimeter of the figure. Round to the nearest hundredth. 23.61 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 In β³π΄π΅πΆ, β π΅ is a right angle. The coordinates for each point are π΄(10, 7), π΅(5, 9), and πΆ(3, 4). Rounded to the nearest tenth, what is the area, in square units, of β³π΄π΅πΆ? Enter the area in the box. 14.5 π’πππ‘π 2 Groups 1, 2, and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 A triangle has vertices at (1, 3), (2, β3), and (β1, β1). What is the approximate perimeter of the triangle? 10 14 15 16 Groups 1, 2, and 3 B 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 Given the polygon with vertices P(5, -1), Q(-1, -4), R(-3, 1), and S(0, 3). Find the area and the perimeter of PQRS. Round your answer to the nearest tenth. Enter your answers in the boxes. Area: Perimeter: π ππ’πππ π’πππ‘π π’πππ‘π 29 22.1 Groups 2 and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 What is the perimeter, in grid units, of a regular octagon that has one side with endpoints (-1, 2) and (3, -1)? Enter your answer in the box. 40 Groups 2 and 3 2018 Geometry Bootcamp
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2018 Geometry Bootcamp MAFS.912.G-GPE.2.7 What is the exact perimeter of a parallelogram with vertices at 3, 2 , 4,4 , and (6, 1)? πβ ππ +πβ π Groups 2 and 3 2018 Geometry Bootcamp
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