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Statistical Thermodynamics of the Perfect Monatomic Gas

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Presentation on theme: "Statistical Thermodynamics of the Perfect Monatomic Gas"— Presentation transcript:

1 Statistical Thermodynamics of the Perfect Monatomic Gas
Valentim M B Nunes ESTT – IPT May 2015

2 The partition function allows the calculation of the properties of a system from the knowledge of the energy levels of particles.

3 In the case of a monatomic ideal gas the only form of energy is the kinetic energy of translation. To obtain the translational energy levels we use the model of particle of mass m in a box of volume V = a  b  c. Quantum mechanics tells us that: Where p, q and r are the translational quantum numbers, integers ranging between 1 and .

4 For each form of translation we have:

5 As the translational energy varies almost continuously, then:
Translational partition function comes:

6 Knowing the partition function we can calculate the thermodynamic properties of an assembly of N particles that behave like a perfect monatomic gas.

7 We can now calculate the pressure of a perfect gas:
Per mole, N = NA, and we obtain:

8 For the translational entropy:

9 Eliminating the volume and introducing the equation of state, we obtain, in S.I. units, the Sackur-Tetrode equation: Not foreseen by classical thermodynamics! Important! Allows you to calculate the absolute entropy of a monatomic gas. Ex: Argon at K, S°m = J.mol-1.K-1

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11 Per system (molecule) the average kinetic energy is therefore:
Principle of equipartition of energy: each of the three quadratic modes of expression of the translational kinetic energy contributes with 1/2 kBT for energy. This result shows that, in fact,  = 1/kBT

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13 Gas Cp CV He 20.79 12.6 1.63 Ar 12.4 1.667 Xe 1.666


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