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CHEMISTRY 161 Chapter 5 www.chem.hawaii.edu/Bil301/welcome.html.

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Presentation on theme: "CHEMISTRY 161 Chapter 5 www.chem.hawaii.edu/Bil301/welcome.html."— Presentation transcript:

1 CHEMISTRY 161 Chapter 5

2 REVISION 1. ideal gas equation p × V = n × R × T R = 8.314 J / mol / K
2. molar volume Vm = 22.4 l 3. Dalton’s Law p = p1 + p2 + …

3 1. Kinetic Molecular Theory of Gases
macroscopic (gas cylinder) microscopic (atoms/molecules) Maxwell ( ) Boltzmann ( )

4 Kinetic Energy of Gases
physical properties of gases can be described by motion of individual gas atoms/molecules each macroscopic and microscopic particle in motion holds an energy (kinetic energy)

5 kinetic energy = energy of an object in motion
SI Units of Energy energy = force × distance W = F × Δs [W] = [F] × [s] [W] = N m = kg m2 s-2 = J Joule ( ) kinetic energy = energy of an object in motion

6 Assumptions of the Kinetic Theory of Gases
gases are composed of atoms/molecules which are separated from each other by a distance l much more than their own diameter d d = m l = 10-3 m….. few m molecules are mass points with negligible volume l

7 2. gases are constantly in motion in random reactions
and hold a kinetic energy gases collide and transfer energy (billiard ball model)

8 F(inter) = 0 p(inter) = 0 3. gases atoms/molecules
do not exert forces on each other (absence of intermolecular interactions) F(inter) = 0 p(inter) = 0

9 Gas Diffusion

10 Ekin = ½ m u2 Ekin = ½ m u2 T ∞ ½ m u2 const T = ½ m u2
4. the average kinetic energy of a gas molecule/atom is proportional to the temperature Ekin = ½ m u2 Ekin = ½ m u2 u12 + u22 + u32 + … + uN2 u2 = N T ∞ ½ m u2 const T = ½ m u2

11 1. Compressibility of gases
Applications 1. Compressibility of gases p ∞ 1/V

12 2. Kinetic energy of gases
Ekin = ½ m u2 ∞ T p ∞ T

13 2. Distribution of Molecular Speeds
Maxwell-Boltzmann distribution

14 activation energy

15 Quantification Ekin = ½ m u2 = const T Ekin = ½ M u2 = const’ T
Ekin = ½ M u2 = 3/2 R T root mean square speed urms =√ (3 R T / M)

16 Calculate the RMS of molecular helium at 25oC
1. apply urms =√ (3 R T / M) 2. calculate numbers and SI units 1360 ms-1

17 deviation of ideal gas law
3. Real Gases p × V = n × R × T (n = 1) deviation of ideal gas law at high pressures p ≈ 90 atm

18 North America Nebula p << atm

19 (van der Waals equation) (p + (a n2 / V2) ) (V – n b) = n R T
ideal gas law p V = n R T real gas law (van der Waals equation) (p + (a n2 / V2) ) (V – n b) = n R T corrected volume (volume occupied by molecules) corrected pressure (additional pressure/force from attraction)

20 REVISION 1. Kinetic Molecular Theory of Gases
2. Distribution of Molecular Speeds Ekin = ½ M u2 = 3/2 R T 3. Real Gas Law (p + (a n2 / V2) ) (V – n b) = n R T

21 Homework Chapter 5, p ` problems


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