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Published byRayssa Tuschinski Álvares Modified over 6 years ago
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South Dakota School of Mines & Technology Data Analysis Industrial Engineering
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Data Analysis Statistical Measures Industrial Engineering
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Aside: Mean, Variance Mean: Variance: xp x discrete ( ) ,
2 ( ) x p
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Example Consider the discrete uniform die example: x 1 2 3 4 5 6
p(x) /6 1/6 1/6 1/6 1/6 1/6 = E[X] = 1(1/6) + 2(1/6) + 3(1/6) + 4(1/6) + 5(1/6) + 6(1/6) = 3.5
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Example Consider the discrete uniform die example: x 1 2 3 4 5 6
p(x) /6 1/6 1/6 1/6 1/6 1/6 2 = E[(X-)2] = (1-3.5)2(1/6) + (2-3.5)2(1/6) + (3-3.5)2(1/6) + (4-3.5)2(1/6) + (5-3.5)2(1/6) + (6-3.5)2(1/6) = 2.92
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å Binomial Mean p ÷ ø ö ç è æ ) 1 ( )! ! xp x ( )
= 1p(1) + 2p(2) + 3p(3) np(n) x n p - = ÷ ø ö ç è æ å ) 1 ( )! !
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å Binomial Mean p ÷ ø ö ç è æ ) 1 ( )! ! xp x ( )
= 1p(1) + 2p(2) + 3p(3) np(n) x n p - = ÷ ø ö ç è æ å ) 1 ( )! ! Miracle 1 occurs = np
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Binomial Measures Mean: Variance: xp ( x ) = np ( ) x
2 ( ) x p = np(1-p)
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Binomial Distribution
0.0 0.1 0.2 0.3 0.4 0.5 1 2 3 4 5 x P(x) 0.0 0.1 0.2 0.3 0.4 0.5 1 2 3 4 5 x P(x) n=5, p=.3 n=8, p=.5 n=20, p=.5 n=4, p=.8 0.0 0.1 0.2 0.3 0.4 0.5 2 4 x P(x) 0.0 0.1 0.2 0.3 0.4 0.5 1 2 3 4 5 6 7 8 P(x) x
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Measures of Centrality
Mean Median Mode
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Measures of Centrality
Mean xp x discrete ( ) , xf x dx continuous ( ) , Sample Mean å = n i x X 1
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Measures of Centrality
Exercise: Compute the sample mean for the student Gpa data 2.4, 2.7, 2.8, 2.9, 3.0, 3.0, 3.1, 3.3, 3.5, 3.9
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Measures of Centrality
Failure Data X 1 . 19 =
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Measures of Centrality
Median Compute the median for the student Gpa data 2.4, 2.7, 2.8, 2.9, 3.0, 3.0, 3.1, 3.3, 3.5, 3.9 . 3 2 = + X )
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Measures of Centrality
Mode Class mark of most frequently occurring interval For Failure data, mode = class mark first interval ( . 5 = X
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Measures of Centrality
Measure Student Gpa Failure Data Mean Median Mode Sample mean X is a blue estimator of true mean m. X m E[ X ] = m u.b.
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Measures of Dispersion
Range Sample Variance
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Measures of Dispersion
Range Compute the range for the student Gpa data 2.4, 2.7, 2.8, 2.9, 3.0, 3.0, 3.1, 3.3, 3.5, 3.9 Min = 2.4 Max = 3.9 Range = = 1.5
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Measures of Dispersion
Variance 2 ( ) x p 2 ( ) x f dx Sample variance x 1 2 - = å n s i
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Measures of Dispersion
Exercise: Compute the sample variance for the student Gpa data 2.4, 2.7, 2.8, 2.9, 3.0, 3.0, 3.1, 3.3, 3.5, 3.9 x 1 2 - = å n s i
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Measures of Dispersion
Exercise: Compute the variance for failure time data s2 =
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An Aside For Failure Time data, we now have three measures for the data Expontial ?? s2 = X 1 . 19 =
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An Aside Recall that for the exponential distribution m = 1/l s2 = 1/l2 If E[ X ] = m and E [s2 ] = s2, then 1/l = 19.1 or 1/l2 = X 1 . 19 = s2 = l 0524 . ˆ = l 0575 . ˆ =
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