Presentation is loading. Please wait.

Presentation is loading. Please wait.

Lecture 9: Speech Recognition (I) October 26, 2004 Dan Jurafsky

Similar presentations


Presentation on theme: "Lecture 9: Speech Recognition (I) October 26, 2004 Dan Jurafsky"— Presentation transcript:

1 Lecture 9: Speech Recognition (I) October 26, 2004 Dan Jurafsky
LING 138/238 SYMBSYS 138 Intro to Computer Speech and Language Processing Lecture 9: Speech Recognition (I) October 26, 2004 Dan Jurafsky 11/9/2018 LING 138/238 Autumn 2004

2 Outline for ASR this week
Acoustic Phonetics ASR Architecture The Noisy Channel Model Five easy pieces of an ASR system Feature Extraction Acoustic Model Lexicon/Pronunciation Model Decoder Language Model Evaluation 11/9/2018 LING 138/238 Autumn 2004

3 Acoustic Phonetics Sound Waves
11/9/2018 LING 138/238 Autumn 2004

4 Waveforms for speech Waveform of the vowel [iy]
Frequency: repetitions/second of a wave Above vowel has 28 reps in .11 secs So freq is 28/.11 = 255 Hz This is speed that vocal folds move, hence voicing Amplitude: y axis: amount of air pressure at that point in time Zero is normal air pressure, negative is rarefaction 11/9/2018 LING 138/238 Autumn 2004

5 She just had a baby What can we learn from a wavefile?
Vowels are voiced, long, loud Length in time = length in space in waveform picture Voicing: regular peaks in amplitude When stops closed: no peaks: silence. Peaks = voicing: .46 to .58 (vowel [iy], from second .65 to .74 (vowel [ax]) and so on Silence of stop closure (1.06 to 1.08 for first [b], or 1.26 to 1.28 for second [b]) Fricatives like [sh] intense irregular pattern; see .33 to .46 11/9/2018 LING 138/238 Autumn 2004

6 Examples from Ladefoged
pad bad spat 11/9/2018 LING 138/238 Autumn 2004

7 Spectra New idea: spectra (singular spectrum)
Different way to view a waveform Fourier analysis: every wave can be represented as sum of many simple waves of different frequencies. Articulatory facts: The vocal cord vibrations create harmonics The mouth is an amplifier Depending on shape of mouth, some harmonics are amplified more than others 11/9/2018 LING 138/238 Autumn 2004

8 Part of [ae] waveform from “had”
Note complex wave repeating nine times in figure Plus smaller waves which repeats 4 times for every large pattern Large wave has frequency of 250 Hz (9 times in .036 seconds) Small wave roughly 4 times this, or roughly 1000 Hz Two little tiny waves on top of peak of 1000 Hz waves 11/9/2018 LING 138/238 Autumn 2004

9 A spectrum Spectrum represents these freq components
Computed by Fourier transform, algorithm which separates out each frequency component of wave. x-axis shows frequency, y-axis shows magnitude (in decibels, a log measure of amplitude) Peaks at 930 Hz, 1860 Hz, and 3020 Hz. 11/9/2018 LING 138/238 Autumn 2004

10 Spectrogram 11/9/2018 LING 138/238 Autumn 2004

11 Formants Vowels largely distinguished by 2 characteristic pitches.
One of them (the higher of the two) goes downward throughout the series iy ih eh ae aa ao ou u (whisper iy eh uw) The other goes up for the first four vowels and then down for the next four. creaky voice iy ih eh ae (goes up) creaky voice aa ow uh uw (goes down) These are called "formants" of the vowels, lower is 1st formant, higher is 2nd formant. 11/9/2018 LING 138/238 Autumn 2004

12 How formants are produced
Q: why do vowels have different pitches if the vocal cords are same rate? A: mouth as "amplifier"; amplifies different frequencies Formants are result of differen shapes of vocal tract. Any body of air will vibrate in a way that depends on its size and shape. Air in vocal tract is set in vibration by action of focal cords. Every time the vocal cords open and close, pulse of air from the lungs, acting like sharp taps on air in vocal tract, Setting resonating cavities into vibration so produce a number of different frequencies. 11/9/2018 LING 138/238 Autumn 2004

13 How to read spectrograms
bab: closure of lips lowers all formants: so rapid increase in all formants at beginning of "bab” dad: first formant increases, but F2 and F3 slight fall gag: F2 and F3 come together: this is a characteristic of velars. Formant transitions take longer in velars than in alveolars or labials 11/9/2018 LING 138/238 Autumn 2004

14 She came back and started again
1., lots of high-freq energy 3. closure for k 4. burst of aspiration for k 5. ey vowel;faint 1100 Hz formant is nasalization 6. bilabial nasal short b closure, voicing barely visible. 8. ae; note upward transitions after bilabial stop at beginning 9. note F2 and F3 coming together for "k" 11/9/2018 LING 138/238 Autumn 2004

15 Spectrogram for “She just had a baby”
11/9/2018 LING 138/238 Autumn 2004

16 Perceptual properties
Pitch: perceptual correlate of frequency Loudness: perceptual correlate of power, which is related to square of amplitude 11/9/2018 LING 138/238 Autumn 2004

17 Speech Recognition Applications of Speech Recognition (ASR) Dictation
Telephone-based Information (directions, air travel, banking, etc) Hands-free (in car) Speaker Identification Language Identification Second language ('L2') (accent reduction) Audio archive searching 11/9/2018 LING 138/238 Autumn 2004

18 LVCSR Large Vocabulary Continuous Speech Recognition
~20,000-64,000 words Speaker independent (vs. speaker-dependent) Continuous speech (vs isolated-word) 11/9/2018 LING 138/238 Autumn 2004

19 LVCSR Design Intuition
Build a statistical model of the speech-to-words process Collect lots and lots of speech, and transcribe all the words. Train the model on the labeled speech Paradigm: Supervised Machine Learning + Search 11/9/2018 LING 138/238 Autumn 2004

20 Speech Recognition Architecture
Speech Waveform Spectral Feature Vectors Phone Likelihoods P(o|q) Words 1. Feature Extraction (Signal Processing) 2. Acoustic Model Phone Likelihood Estimation (Gaussians or Neural Networks) 5. Decoder (Viterbi or Stack Decoder) 4. Language Model (N-gram Grammar) 3. HMM Lexicon 11/9/2018 LING 138/238 Autumn 2004

21 The Noisy Channel Model
Search through space of all possible sentences. Pick the one that is most probable given the waveform. 11/9/2018 LING 138/238 Autumn 2004

22 The Noisy Channel Model (II)
What is the most likely sentence out of all sentences in the language L given some acoustic input O? Treat acoustic input O as sequence of individual observations O = o1,o2,o3,…,ot Define a sentence as a sequence of words: W = w1,w2,w3,…,wn 11/9/2018 LING 138/238 Autumn 2004

23 Noisy Channel Model (III)
Probabilistic implication: Pick the highest prob S: We can use Bayes rule to rewrite this: Since denominator is the same for each candidate sentence W, we can ignore it for the argmax: 11/9/2018 LING 138/238 Autumn 2004

24 A quick derivation of Bayes Rule
Conditionals Rearranging And also 11/9/2018 LING 138/238 Autumn 2004

25 Bayes (II) We know… So rearranging things 11/9/2018
LING 138/238 Autumn 2004

26 Noisy channel model likelihood prior 11/9/2018
LING 138/238 Autumn 2004

27 The noisy channel model
Ignoring the denominator leaves us with two factors: P(Source) and P(Signal|Source) 11/9/2018 LING 138/238 Autumn 2004

28 Five easy pieces Feature extraction Acoustic Modeling
HMMs, Lexicons, and Pronunciation Decoding Language Modeling 11/9/2018 LING 138/238 Autumn 2004

29 Feature Extraction Digitize Speech Extract Frames 11/9/2018
LING 138/238 Autumn 2004

30 Digitizing Speech 11/9/2018 LING 138/238 Autumn 2004

31 Digitizing Speech (A-D)
Sampling: measuring amplitude of signal at time t 16,000 Hz (samples/sec) Microphone (“Wideband”): 8,000 Hz (samples/sec) Telephone Why? Need at least 2 samples per cycle max measurable frequency is half sampling rate Human speech < 10,000 Hz, so need max 20K Telephone filtered at 4K, so 8K is enough 11/9/2018 LING 138/238 Autumn 2004

32 Digitizing Speech (II)
Quantization Representing real value of each amplitude as integer 8-bit (-128 to 127) or 16-bit ( to 32767) Formats: 16 bit PCM 8 bit mu-law; log compression LSB (Intel) vs. MSB (Sun, Apple) Headers: Raw (no header) Microsoft wav Sun .au 40 byte header 11/9/2018 LING 138/238 Autumn 2004

33 Frame Extraction . . . A frame (25 ms wide) extracted every 10 ms
a a a3 Figure from Simon Arnfield 11/9/2018 LING 138/238 Autumn 2004

34 MFCC (Mel Frequency Cepstral Coefficients)
Do FFT to get spectral information Like the spectrogram/spectrum we saw earlier Apply Mel scaling Linear below 1kHz, log above, equal samples above and below 1kHz Models human ear; more sensitivity in lower freqs Plus Discrete Cosine Transformation 11/9/2018 LING 138/238 Autumn 2004

35 Final Feature Vector 39 Features per 10 ms frame:
12 MFCC features 12 Delta MFCC features 12 Delta-Delta MFCC features 1 (log) frame energy 1 Delta (log) frame energy 1 Delta-Delta (log frame energy) So each frame represented by a 39D vector 11/9/2018 LING 138/238 Autumn 2004

36 Acoustic Modeling Given a 39d vector corresponding to the observation of one frame oi And given a phone q we want to detect Compute p(oi|q) Most popular method: GMM (Gaussian mixture models) Other methods MLP (multi-layer perceptron) 11/9/2018 LING 138/238 Autumn 2004

37 Acoustic Modeling: MLP computes p(q|o)
11/9/2018 LING 138/238 Autumn 2004

38 Gaussian Mixture Models
Also called “fully-continuous HMMs” P(o|q) computed by a Gaussian: 11/9/2018 LING 138/238 Autumn 2004

39 Gaussians for Acoustic Modeling
A Gaussian is parameterized by a mean and a variance: Different means P(o|q): P(o|q) is highest here at mean P(o|q is low here, very far from mean) P(o|q) o 11/9/2018 LING 138/238 Autumn 2004

40 Training Gaussians A (single) Gaussian is characterized by a mean and a variance Imagine that we had some training data in which each phone was labeled We could just compute the mean and variance from the data: 11/9/2018 LING 138/238 Autumn 2004

41 But we need 39 gaussians, not 1!
The observation o is really a vector of length 39 So need a vector of Gaussians: 11/9/2018 LING 138/238 Autumn 2004

42 Actually, mixture of gaussians
Each phone is modeled by a sum of different gaussians Hence able to model complex facts about the data Phone A Phone B 11/9/2018 LING 138/238 Autumn 2004

43 Gaussians acoustic modeling
Summary: each phone is represented by a GMM parameterized by M mixture weights M mean vectors M covariance matrices Usually assume covariance matrix is diagonal I.e. just keep separate variance for each cepstral feature 11/9/2018 LING 138/238 Autumn 2004

44 ASR Lexicon: Markov Models for pronunciation
11/9/2018 LING 138/238 Autumn 2004

45 The Hidden Markov model
11/9/2018 LING 138/238 Autumn 2004

46 Formal definition of HMM
States: a set of states Q = q1, q2…qN Transition probabilities: a set of probabilities A = a01,a02,…an1,…ann. Each aij represents P(j|i) Observation likelihoods: a set of likelihoods B=bi(ot), probability that state i generated observation t Special non-emitting initial and final states 11/9/2018 LING 138/238 Autumn 2004

47 Pieces of the HMM Observation likelihoods (‘b’), p(o|q), represents the acoustics of each phone, and are computed by the gaussians (“Acoustic Model”, or AM) Transition probabilities represent the probability of different pronunciations (different sequences of phones) States correspond to phones 11/9/2018 LING 138/238 Autumn 2004

48 Pieces of the HMM Actually, I lied when I say states correspond to phones Actually states usually correspond to triphones CHEESE (phones): ch iy z CHEESE (triphones) #-ch+iy, ch-iy+z, iy-z+# 11/9/2018 LING 138/238 Autumn 2004

49 Pieces of the HMM Actually, I lied again when I said states correspond to triphones In fact, each triphone has 3 states for beginning, middle, and end of the triphone. 11/9/2018 LING 138/238 Autumn 2004

50 A real HMM 11/9/2018 LING 138/238 Autumn 2004

51 Cross-word triphones Word-Internal Context-Dependent Models
‘OUR LIST’: SIL AA+R AA-R L+IH L-IH+S IH-S+T S-T Cross-Word Context-Dependent Models SIL-AA+R AA-R+L R-L+IH L-IH+S IH-S+T S-T+SIL 11/9/2018 LING 138/238 Autumn 2004

52 Summary ASR Architecture Five easy pieces of an ASR system
The Noisy Channel Model Five easy pieces of an ASR system Feature Extraction: 39 “MFCC” features Acoustic Model: Gaussians for computing p(o|q) Lexicon/Pronunciation Model HMM: Next time: Decoding: how to combine these to compute words from speech! 11/9/2018 LING 138/238 Autumn 2004


Download ppt "Lecture 9: Speech Recognition (I) October 26, 2004 Dan Jurafsky"

Similar presentations


Ads by Google