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PROPERTIES OF ACIDS & BASES

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Presentation on theme: "PROPERTIES OF ACIDS & BASES"— Presentation transcript:

1 PROPERTIES OF ACIDS & BASES

2 WHAT IS AN ACID? A compound that donates a hydrogen ion (H+) when dissociated

3 ACID PROPERTIES aqueous solutions have a sour taste
change the color of acid-base indicators when reacted with an active metal, releases hydrogen gas Zn (s) + H2SO4 (aq)  ZnSO4 (aq) + H2 (g)

4 ACID PROPERTIES when reacted with base, produces salt and water
HCl (aq) + NaOH (aq)  NaCl (s) + H2O (l) conduct electric current Turns litmus paper red

5 STRONG VS. WEAK ACIDS Strong acids dissociate completely
Every H+ ion breaks off Weak acids dissociate incompletely A few H+ ions break off then reform

6 WHAT IS A BASE? A compound that accepts a hydrogen ion (H+) OR
contains OH- ion

7 BASE PROPERTIES aqueous solutions of bases have a bitter taste
bases change the color of acid base indicators dilute aqueous solutions of bases feel slippery

8 BASE PROPERTIES when reacted with acid, produces salt and water
conduct electric current Turns litmus paper blue

9 Learning Check Describe the solution in each of the following as:
1) acid 2) base or 3)neutral A. soda B. soap C. coffee D. wine E. water F. grapefruit

10 Relationship of [H3O+] and [OH-]
Section 1 What Are Acids and Bases? Chapter 15 Relationship of [H3O+] and [OH-]

11 DIFFERENT DEFINITIONS
SHOULD BE MEMORIZED

12 ARRHENIUS ACID A chemical compound that increases the concentration of H+ ions in solution Good for calculating pH BASE A chemical compound that increases the concentration of OH- ions in solution Good for calculation pOH Limited to bases containing OH-

13 HCl  H+(aq) + Cl-(aq) Arrhenius Definition NaOH  Na+(aq) + OH-(aq)
In aqueous solution… Acids form hydrogen ions (H+) water HCl  H+(aq) + Cl-(aq) In aqueous solution… Bases form hydroxide ions (OH-) water NaOH  Na+(aq) + OH-(aq)

14 Brønsted-Lowry Classification, continued
Section 1 What Are Acids and Bases? Chapter 15 Brønsted-Lowry Classification, continued Brønsted-Lowry Acids Donate Protons, continued

15 BRONSTED-LOWRY ACID A molecule or ion that is a proton (H+) donor BASE
A molecule or ion that is a proton (H+) acceptor Includes compounds w/o OH-

16 HCl + H2O  Cl– + H3O+ acid conjugate base base conjugate acid
Brønsted-Lowry Acids are proton (H+) donors Bases are proton (H+) acceptors HCl + H2O  Cl– + H3O+ acid conjugate base base conjugate acid

17 HCl + H2O  Cl– + H3O+ acid conjugate base base conjugate acid

18 Acids and bases come in pairs...
A conjugate base is the remainder of the original acid, after it donates it’s hydrogen ion A conjugate acid is the particle formed when the original base gains a hydrogen ion General equation is: HA(aq) + H2O(l) H3O+(aq) + A-(aq) Acid Base Conj acid Conj base

19 Examples 1.HCl + NH3 NH4+ + Cl– 2.OH– + HCN  H2O + CN–
3. PO43– + HNO3  NO3– + HPO42- 4.HCO3– + HCl H2CO3 + Cl–

20 Why don’t we like this definition?
LEWIS ACID Electron pair acceptor BASE Electron pair donator Why don’t we like this definition?

21 HCl(aq) + H2O(l)  H3O+(aq) + Cl–(aq)
Hydronium Ion H3O+ Often the term H+ for convenience, it is more accurate to use H3O+ HCl(aq) + H2O(l)  H3O+(aq) + Cl–(aq) H Cl O +

22 Amphoteric - can be an acid or a base
Ex.1- Water as a base Amphoteric - can be an acid or a base (ex. water) H2O + HNO3  H3O+ + NO3– B A CA CB

23 Ex. 2- Water as an acid NH3 + H2O  NH4+ + OH- B A CA CB

24 Acid-Base Titrations and pH

25 pH pH < 7 is acidic pH = 7 is neutral pH > 7 is basic

26 [H+] = concentration in molarity
Calculating pH pH = - log [H+] pH = power of Hydrogen [H+] = concentration in molarity

27 Calculating pOH pOH = - log [OH-] pOH = power of Hydroxide
[OH-] = concentration in molarity pH + pOH = 14

28 CALCULATING pH FROM CONCENTRATION
SAMPLE PROBLEM A What is the pH of a 1 x 10-3 M HCl solution?

29 SAMPLE PROBLEM B What is the pH of a 2.5 x 10-2 M H2SO4 solution?

30 SAMPLE PROBLEM C What is the pH of a 2.5 x 10-2 M NaOH solution?

31 [H3O+] CALCULATING CONCENTRATION FROM pH [H3O+] = 10-pH
[H3O+] = concentration of acid (N) Look for your log button. Above it – 10x To access it, hit 2nd F key Hit log key

32 [OH-] = concentration of base (M)
[OH-] = 10-pOH [OH-] = concentration of base (M) [H3O+] [OH-] = 1.0 x 10-14

33 SAMPLE PROBLEM D What is the concentration of a HCl solution with pH of 5.6?

34 SAMPLE PROBLEM E What is the concentration of a Mg(OH)2 solution with pH of 5.6?

35 NEUTRALIZATION REACTIONS

36 NEUTRALIZATION REACTIONS
The reaction of an acid and a base to form salt & water H+ ions react with OH- to form water Predict products as in a double replacement rxn (partner swap) HCl (aq) + NaOH (aq)  H2O (l) + NaCl (s)

37 PRACTICE REACTIONS HCl + LiOH  HNO3 + Ca(OH)2  H2SO4 + Al(OH)3 

38 PRACTICE REACTIONS HCl + LiOH  H2O + LiCl
2 HNO3 + Ca(OH)2  2 H2O + Ca(NO3)2 3 H2SO Al(OH)3  6 H2O + Al2(SO4)3

39 TITRATIONS MA VA = MB VB

40 NORMALITY & NEUTRALIZATION REACTIONS
MA VA = MB VB Where: MA = molarity of acid VA = volume of acid MB = molarity of base VB = volume of base

41 NORMALITY & NEUTRALIZATION REACTIONS
What volume of a 0.25 M HCl solution is needed to neutralize 36 mL of 0.30 Mg(OH)2 M? Step 1: Start with what you know. NA = (0.25 M) (1) = 0.25 N VA = X mL NB = (0.30 M) (2) = 0.60 N VB = 36 mL


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