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Warm Up Solve for x: π π ππβ π π +ππ= π π π+π π π π+π =βππ
I can complete the unit circle Warm Up Solve for x: π π ππβ π π +ππ= π π π+π π π π+π =βππ
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Warm Up Solve for x: π π ππβ π π +ππ= π π π+π
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Warm Up Solve for x: π π π+π =βππ
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Homework Questions
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What is the Unit Circle?
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Is there another way to solve?
Unit Circle Solve for π¦ sin 30 =π¦ π¦= 1 2 Solve for π₯ 60Β° cos 30 =π₯ π₯=.86660 Is there another way to solve? 1 π¦ 30Β° π₯
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Unit Circle 1 2 2 + π₯ 2 = 1 2 Solve for π₯ 1 4 + π₯ 2 =1 π₯ 2 = 3 4
π₯ 2 = 1 2 1 4 + π₯ 2 =1 π₯ 2 = 3 4 π₯= 3 4 π₯= Solve for π₯ 60Β° 1 π¦ 30Β° π₯
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What we know so farβ¦
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What we know so farβ¦ π π π π ππ
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Unit Circle Solve for π₯ cos 45 =π₯ π₯= 45Β° 1 π¦ 45Β° π₯
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Unit Circle Solve for π₯ Is there another way to solve for π₯?
π₯ 2 + π¦ 2 = 1 2 π₯ 2 + π₯ 2 =1 2 π₯ 2 =1 π₯ 2 = 1 2 π₯= 1 2 π₯= 45Β° 1 π₯ π¦ 45Β° π₯
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Unit Circle Solve for π₯ cos 45 =π₯ π₯= 45Β° 1 π¦ 45Β° π₯
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Unit Circle Solve for π₯ Is there another way to solve for π₯?
π₯ 2 + π¦ 2 = 1 2 π₯ 2 + π₯ 2 =1 2 π₯ 2 =1 π₯ 2 = 1 2 π₯= 1 2 π₯= 45Β° 1 π₯ π¦ 45Β° π₯
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Unit Circle Solve for π₯ and π¦ π₯= 1 2 π¦= 30Β° 1 π¦ 60Β° π₯
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Unit Circle Using what we have discussed about patterns, try to fill in the first quadrant
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What we know so farβ¦ π π π π π π π π ππ ππ
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Unit Circle Solve for π₯ and π¦ π₯= 1 2 π¦= 30Β° 1 π¦ 60Β° π₯
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What we know so farβ¦ π π π π ππ π π π π π π ππ π π π π ππ ππ π π π
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In this case, π, ππ π‘βπ πππππππππ πππππ, and the calculation gives the angle of rotation:
165Β° 180βπΒ° 195Β° 360βπΒ° 245Β° 180+πΒ° πΒ° 15Β°
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Reference Angles A devious person created a new ride similar to The Screamer. On this ride, the circle rotates every 12Β°. At 12Β° a rider is 15 feet off the ground. What other angles is the rider the same distance from the ground? 180β12Β°=168Β° Β°=192Β° 360β12Β°=348Β°
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Reference Angles A rider is 45 feet from the ground when the angle of rotation is 134Β°. What other angles is the rider the same distance from the ground? 180βπΒ°=134Β° π= Β°=226Β° 360β46Β°=314Β°
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Reference Angles A reference angle helps find repeating patterns in a circle.ππ πΒ° is the given angle on the unit circle: the reference angle, πΌ, will be: Quadrant II: 180βπΒ° Quadrant III: 180+πΒ° Quadrant IV: 360βπΒ° } And the π πππ ππ πππ π is equal to sin πΌ ππ πππ πΌ
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More on reference angles
A reference angle is always a 1st quadrant angle A reference angle is always positive Reference angles are always determined by measuring to the X-axis, NEVER to the Y-axis
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Reference Angles Identify the reference angle for each angle (Hint what quadrant would the angle be in?): 133Β° 245Β° 18Β° 359Β° 47Β° 65Β° 18Β° 1Β°
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Unit Circle Using what we have discussed about patterns and reference angles, try to fill in the rest of the unit circle keeping in mind when values are positive or negative based on the coordinate grid.
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π π π π π π ππ π π π π πππ ππ π π π π πππ ππ πππ ππ πππ π
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π π π π βπ π π π π π ππ π π π π β π π π π πππ ππ π π β π π π π π π πππ ππ πππ ππ πππ π βπ π π π
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πππ πππ πππ πππ πππ πππ πππ πππ
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πππ πππ πππ πππ πππ β π π βπ π π π βπ π πππ πππ β π π β π π β π π π π β π π βπ π β π π πππ π π π βπ
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Notes: Unit Circle Points on the unit circle are (πππ π, π πππ) Find the exact value of sinβ‘(150Β°) sin 150Β° = 1 2 Find the exact value of cosβ‘(210Β°) cos 210Β° =β 3 2
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Homework Textbook: , , 8-67
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