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Chapter 6 Gases 6.6 The Combined Gas Law.

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Presentation on theme: "Chapter 6 Gases 6.6 The Combined Gas Law."— Presentation transcript:

1 Chapter Gases 6.6 The Combined Gas Law

2 Combined Gas Law The combined gas law uses Boyle’s Law, Charles’ Law, and Gay-Lussac’s Law (n is constant). P1 V1 = P2 V2 T1 T2

3 Learning Check A gas has a volume of 675 mL at 35°C and atm pressure. What is the volume(mL) of the gas at -95°C and a pressure of 802 mm Hg (n constant)?

4 Solution Data Table Conditions 1 Conditions 2
T1 = 308 K T2 = -95°C = 178K V1 = 675 mL V2 = ??? P1 = 646 mm Hg P2 = 802 mm Hg Solve for V2 V2 = V1 x P1 x T2 P T1 V2 = mL x mm Hg x 178K = mL 802 mm Hg x 308K

5 Combined Gas Law Calculation
A sample of helium gas has a volume of L, a pressure of atm and a temperature of 29°C. At what temperature (°C) will the helium have a volume of 90.0 mL and a pressure of 3.20 atm (n is constant)? 1. Set up Data Table Conditions 1 Conditions 2 P1 = atm P2 = atm V1 = L (180 mL) V2 = 90.0 mL T1 = 29°C = 302 K T2 = ??

6 Combined Gas Law Calculation (continued)
2. Solve for T2 P1 V1 = P2 V2 T1 T2 T2 = T1 x P2 x V2 P V1 T2 = 302 K x atm x mL = K 0.800 atm mL T2 = 604 K = °C


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