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Concept Questions A wire, initially carrying no current, has a radius that starts decreasing at t = 0. As it shrinks, which way does current begin to.

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Presentation on theme: "Concept Questions A wire, initially carrying no current, has a radius that starts decreasing at t = 0. As it shrinks, which way does current begin to."— Presentation transcript:

1 Concept Questions A wire, initially carrying no current, has a radius that starts decreasing at t = 0. As it shrinks, which way does current begin to flow in the loop? A) Clockwise B) Counter-clockwise C) No current D) Insufficient information Calculate flux downwards – we get EMF clockwise Flux is decreasing Derivative of flux is negative EMF is positive clockwise Current will flow clockwise Right hand rule – B-field downwards Reinforces magnetic field Tries to keep the B-flux constant The current that flows will then create a magnetic field, which inside the loop, will A) Strengthen it B) Weaken it C) No change D) Insufficient information

2 What if we used a superconductor?
Concept Question What happens as I drop the magnet into the copper tube? A) Falls as usual B) Falls slower C) Falls faster D) Floats constant E) Pops back up and out N S S N As magnet falls, some places have magnetic fields that diminish Current appears, replacing magnetic field This acts like a magnet, pulling it back up At bottom end, current appears to oppose change This repels the magnet, slowing it down S N Current is only caused by motion of magnet If motion stops, resistance stops current If motion is small, opposition will be small It doesn’t stop, it goes slowly What if we used a superconductor?

3 Concept Question What is Kirchoff’s law for the loop shown?
A) E + L (dI /dt) = 0 B) E – L (dI /dt) = 0 C) None of the above D) I don’t know Kirchoff’s law for switches I + L E The voltage change for an inductor is L (dI/dt) Negative if with the current Positive if against the current

4 Concept Question In the steady state, with the switch closed, how much current flows through R2? How much current flows through R2 the moment after we open the switch? A) 0 A B) 6 A C) 3 A D) 2 A E) None of the above R2 = 4  6 A 6 A 6 A L R1 = 2  + E = 12 V In the steady state, the inductor is like a wire Both ends of R2 are at the same potential: no current through R2 The remaining structure had current I = E/R1 = 6 A running through it I = E /R1 = 6 A Now open the switch – what happens? Inductors resist changes in current, so the current instantaneously is unchanged in inductor It must pass through R2 I = 6 A

5 Loop has unin-tended inductance
Concept Question The circuit at right is in a steady state. What will the voltmeter read as soon as the switch is opened? A) 0.l V B) 1 V C) 10 V D) 100 V E) 1000 V R1 = 10  L I = 1 A V R2 = 1 k + E = 10 V The current remains constant at 1 A It must pass through resistor R2 The voltage is given by V = IR Note that inductors can produce very high voltages Inductance causes sparks to jump when you turn a switch off + Loop has unin-tended inductance

6 Energy sloshes back and forth
Concept Question A capacitor with charge on it has energy U = Q2/2C, but Q is constantly changing. Where does the energy go? A) It is lost in the resistance of the wire B) It is stored as kinetic energy of the electrons C) It is stored in the inductor D) Hollywood! I Q C L Let’s find the energy in the capacitor and the inductor Energy sloshes back and forth

7 Concept Question If the voltage from a source looks like the graph below, about what voltage should it be labeled? 0 V B) 170 V C) 120 V D) 85 V E) It should be labeled some other way Average voltage is zero, but that doesn’t tell us anything Maximum voltage 170 V is an overstatement Power is usually proportional to voltage squared

8 Concept Question A 60 W light bulb is plugged into a standard outlet (Vrms = 120 V). What is the resistance of the bulb? A) 15  B) 30  C) 60  D) 120  E) 240 

9 Capacitors and Resistors Combined
Capacitors and resistors both limit the current – they both have impedance Resistors: same impedance at all frequencies Capacitors: more impedance at low frequencies Concept Question The circuit at right might be designed to: Let low frequencies through, but block high frequencies Let high frequencies through, but block low frequencies Let small currents through, but not big currents Let big currents through, but not small currents

10 Impedance Table Resistor Capacitor Inductor Impedance R Phase
Vector Direction right down up Inductors are good for Blocking low frequencies Blocking high frequencies Blocking large currents Blocking small currents

11 Concept Question In the mystery box at right, we can put a 2.0 F capacitor, a 4.0 H inductor, or both (in series). Which one will cause the greatest current to flow through the circuit? A) The capacitor B) The inductor C) both D) Insufficient information 1.4 k ? 60 Hz 170 V 2.0 F We want to minimize impedance Make the vector sum as short as possible Recall, capacitors point down, inductors up The sum is shorter than either separately L= 4.0 H 1.3 k 1.5 k 1.4 k

12 Concept Question L C R f Vmax
How will XL and XC compare at the frequency where the maximum power is delivered to the resistor? A) XL > XC B) XL < XC C) XL = XC D) Insufficient information Resonance happens when XL = XC. This makes Z the smallest It happens only at one frequency Same frequency we got for LC circuit

13 Concept Question In the example we just did, we found only some frequencies get through What happens if this is impossible to meet, because 1/RC > R/L? A) The inequality gets reversed, R/L <  < 1/RC B) Pretty much everything gets blocked C) Only a very narrow frequency range gets through C L R f Vmax = 5 V

14 Concept Question Voltage
When the voltage shown in blue was passed through two components in series, the current shown in red resulted. What two components might they be? A) Capacitor and Inductor B) Inductor and Resistor C) Capacitor and Resistor Current The phase shift represents how the timing of the current compares to the timing of the voltage When it is positive, the current lags the voltage It rises/falls/peaks later When it is negative, the current leads the voltage It rises/falls/peaks earlier

15 Concept Question A transformer has 10,000 V AC going into it, and it is supposed to produce 120 V AC, suitable for household use. If the primary winding has 5,000 turns, how many should the secondary have? A) 120 B) 240 C) 60 D) None of the above N1 =5000 N2 =? V1 = 10 kV V2 = 120 V

16 Concept Question A wave has an electric field given by
What does the magnetic field look like? A) B) C) D) The magnitude of the wave is B0 = E0 / c The wave is traveling in the z-direction, because of sin(kz - t). The wave must be perpendicular to the E-field, so perpendicular to j The wave must be perpendicular to direction of motion, to k It must be in either +i direction or –i direction If in +i direction, then E  B would be in direction j  i = - k, wrong So it had better be in the –i direction

17 Concept Question Radio Waves Microwaves Red Infrared Orange
Which of the following waves has the highest speed in vacuum? A) Infrared B) Orange C) Green D) It’s a tie E) Not enough info Radio Waves Microwaves Infrared Visible Ultraviolet X-rays Gamma Rays f Increasing  Increasing Red Orange Yellow Green Blue Violet

18 Cross-Section To calculate the power falling on an object, all that matters is the light that hits it Example, a rectangle parallel to the light feels no pressure Ask yourself: what area does the light see? This is called the cross section If light of intensity S hits an absorbing sphere of radius a, what is the force on that sphere? A) a2S/c B) 2a2S/c C) 4a2S/c As viewed from any side, a sphere looks like a circle of radius a The cross section for a sphere, then, is a2

19 End of material for Test 3
Equations for Test 3 Faraday’s Law Transformers: Power and Pressure Impedance: Inductors: Units: Frequency, Wavelength Speed of Light End of material for Test 3


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