1. DBMAN 4
Examples
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2. SELECT Displayed order of suffixes
INTO
FROM
WHERE
GROUP BY
HAVING
UNION/MINUS
INTERSECT
ORDER BY
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3. Zero
List the name, job and income for the workers who work in Dallas or Chicago.
Let’s use the operator IN
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4. Solution using the IN SELECT ename, job, sal+isnull(comm, 0)
FROM emp, dept
WHERE
emp.deptno=dept.deptno AND
upper(dept.loc) IN ('DALLAS', 'CHICAGO');
FROM emp
WHERE deptno IN (
SELECT deptno FROM dept
WHERE upper(loc) IN ('DALLAS', 'CHICAGO') );
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5. BAD Solution using manual join
SELECT
ename, job, sal+isnull(comm, 0)
FROM
emp, dept
WHERE
emp.deptno=dept.deptno AND
upper(dept.loc)='DALLAS' OR
upper(dept.loc)='CHICAGO';
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6. GOOD Solution using manual join
SELECT
ename, job, sal+isnull(comm, 0)
FROM
emp, dept
WHERE
emp.deptno=dept.deptno AND
(upper(dept.loc)='DALLAS' OR
upper(dept.loc)='CHICAGO');
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7. PREFERRED Solution using inner join
SELECT
ename, job, sal+isnull(comm, 0)
FROM
emp INNER JOIN dept ON emp.deptno=dept.deptno
WHERE
upper(dept.loc)='DALLAS' OR
upper(dept.loc)='CHICAGO';
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8. First
List the name of the workers, their salary, the name of their boss, the boss' departments' location and the sum salary of that place.
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9. CHOOSING TABLES AND FIELDS
Sum salary of a location  join EMP and DEPT, use sum()
Worker name and income  EMP D
Boss name and income  join EMP D and EMP F, use EMP F
Place of the boss' department  join EMP F and DEPT
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10. SALARIES IN A DEPARTMENT
A simple multi-table GROUP BY
EMP_1 <deptno, deptno> DEPT_1, and then sum(sal) grouped by the LOC field
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11. SALARIES CREATE VIEW sumSalaries AS SELECT sum(emp.sal) as dept_sal,
dept.loc as dept_loc
FROM emp, dept
WHERE emp.deptno=dept.deptno
GROUP BY dept.loc;
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12. WORKERS-BOSSES-BOSS' DATA
Workers' name and salary  EMP_2
Boss' name and salary  join EMP_2 and EMP_3, use fields in EMP_3
Boss' department's name  Join EMP_3 and DEPT_2
EMP_2 <empno, mgr> EMP_3 EMP_3 <deptno, deptno> DEPT_2
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13. WORKERS-BOSSES-BOSS' DATA
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14. WORKERS-BOSSES-BOSS' DATA
CREATE VIEW workerData AS SELECT work.ename as work_name, work.sal as work_sal, boss.ename as boss_name, boss.sal as boss_sal, dept.loc as boss_loc FROM emp work, emp boss, dept WHERE work.mgr=boss.empno and boss.deptno=dept.deptno;
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15. RESULT WORKERS-BOSSES-BOSS' DATA data1 / workerData
SUM-SALARIES  data2 / sumSalaries
data1 <boss_loc, dept_loc> data2
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16. (SELECT work.ename as work_name, work.sal as work_sal,
SELECT * FROM
(SELECT work.ename as work_name,
work.sal as work_sal,
boss.ename as boss_name,
boss.sal as boss_sal,
dept.loc as boss_loc
FROM emp work, emp boss, dept
WHERE work.mgr=boss.empno and boss.deptno=dept.deptno) data1,
(SELECT sum(emp.sal) as dept_sal,
dept.loc as dept_loc
FROM emp, dept
WHERE emp.deptno=dept.deptno
GROUP BY dept.loc) data2
WHERE data1.boss_loc=data2.dept_loc
ORDER BY boss_name, work_name;
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17. PREFERRED solution with views
SELECT * FROM workerData INNER JOIN sumSalaries ON (workerData.boss_loc=sumSalaries.dept_loc) ORDER BY boss_name, work_name; THIS IS ALWAYS THE PREFERRED WAY!
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18. Second
List the number of employees for each boss, along with their departments, average income, and the difference between that average and the boss' income.
Now do we need the department of the boss (A), or the workers (B)???
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19. CHOOSING FIELDS AND TABLES
Number of employees, their average income  GROUP BY EMP.MGR
Department  Joining EMP and DEPT
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20. GROUP BY EMP.MGR
We can create a table that looks like boss_id – avg.income – num.of.workers, that can be joined to the other tables
How to join: that depends if we interpret the exercise as "A" or "B"
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21. Worker's number and average income
SELECT avg(sal+isnull(comm, 0)) as avg_work_sal, count(*) as work_num, mgr as boss_id FROM emp GROUP BY mgr  Inline view: Data  After this: joining tables
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22. Joining tables (A)
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23. Joining tables (B)
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24. Joining tables (A)
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25. SELECT emp.ename as boss_name,
emp.sal+isnull(emp.comm, 0) as boss_sal,
data.avg_work_sal as boss_worker_sal,
data.work_num as boss_worker_num,
dept.loc as boss_loc,
emp.sal+isnull(emp.comm, 0) data.avg_work_sal as sal_delta
FROM
( SELECT avg(sal+isnull(comm, 0)) as avg_work_sal,
count(*) as work_num,
mgr as boss_id
FROM emp
GROUP BY mgr
) data, emp, dept
WHERE data.boss_id=emp.empno and
emp.deptno=dept.deptno;
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26. Joining tables (B)
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27. SELECT d.ename as work_name, f.ename as boss_name,
f.sal+isnull(f.comm, 0) as boss_sal,
data.avg_work_sal as boss_worker_sal,
data.work_num as boss_worker_num,
dept.loc as worker_loc,
f.sal+isnull(f.comm, 0) -data.avg_work_sal as sal_delta FROM
(SELECT avg(sal+isnull(comm, 0)) as avg_work_sal,
count(*) as work_num,
mgr as boss_id
FROM emp
GROUP BY mgr
) data, emp d, emp f, dept
WHERE data.boss_id=f.empno and f.empno=d.mgr and
d.deptno=dept.deptno ;
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28. Third
List the jobs according to the departments, and the number of workers, the minimum and maximum salaries according to that job. Order the list by the department (ascending) and job (descending).
... “that job” = ???
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29. JOB-DATA  DATA1 SELECT count(*) as Work_Num,
min(sal+isnull(comm, 0)) as Minimum,
max(sal+isnull(comm, 0)) as Maximum,
avg(sal+isnull(comm, 0)) as Average,
job
FROM emp
GROUP BY job;
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30. DEPARTMENTS AND JOBS  DATA2
SELECT distinct loc, job
FROM emp, dept
WHERE emp.deptno=dept.deptno
ORDER BY loc;
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31. RESULT (A) SELECT * FROM (SELECT distinct dept.deptno, loc, job
FROM emp, dept
WHERE emp.deptno=dept.deptno) data2,
(SELECT count(*) as Work_Num,
min(sal+isnull(comm, 0)) as Minimum,
max(sal+isnull(comm, 0)) as Maximum,
avg(sal+isnull(comm, 0)) as Average,
job
FROM emp
GROUP BY job) data1
WHERE data1.job=data2.job
ORDER BY data2.deptno asc, data1.job desc;
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32. RESULT (B)
SELECT count(*) as Work_Num, min(sal+isnull(comm, 0)) as Minimum, max(sal+isnull(comm, 0)) as Maximum, avg(sal+isnull(comm, 0)) as Average, job, deptno FROM emp GROUP BY job, deptno ORDER BY deptno asc, job desc;
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33. Fourth
Display every worker’s name, their department’s name, their boss’ name. The list should include the income parameter for both the boss and the worker.
Income parameter: (income) – (the average income of those who entered the company the same year)
AvgIncomes: year + avgIncome
IncomeParameters: empno + incomeParam
WorkerData: workerName + bossName + deptName + workerId + bossId
Result: WorkerData + IncomeParameters via workerId + IncomParameters via bossId
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