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Section 4 Graphing Motion: Distance, Velocity, and Acceleration
WDYS? 1. 2. 3. WDYT? 1. Similarities: 2. Differences: 1-4 Investigate – use a motion detector to explore motion
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Acceleration (p58) EXAMPLE car going down the ramp
When things change speed, it is usually noticeable EXAMPLE car going down the ramp Like velocity there are 3 models for looking at acceleration: Particle model Graphing Math
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Acceleration is a Vector Quantity (p59)
Acceleration means “how fast the velocity changes” EXAMPLE a car can exhibit greater acceleration than a bus, it can go from 0-60mph faster There are 3 ways to change velocity: 1. speed up slow down turn/change direction ***All of these motions involve acceleration because the velocity changes as time elapses***
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Acceleration is a Vector Quantity (p59)
Positive Acceleration an increase in velocity, where the final velocity is greater than the initial velocity EXAMPLE a car goes DOWN a ramp Speeding Up Negative Acceleration a decrease in velocity, where the final velocity is less than the initial velocity EXAMPLE a car goes UP a ramp Slowing Down
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Acceleration is a Vector Quantity (p59)
Velocity is a Vector Quantity has both magnitude (size) and direction Speed is a Scalar Quantity has only magnitude (size), NO direction
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Using the Equation for Acceleration (p61-62)
*** Speed is ALWAYS changing during constant acceleration*** acceleration = change in velocity / change in time a = ∆ v / ∆ t ∆ v = a × ∆ t ∆ t = ∆ v / a ∆ = final - initial Units for acceleration (a) : km/h/h (km/h2) m/s/s (m/s2) velocity (v) : km/h m/s time (t) : h s
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Sample Problem #1
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1-4 Checking Up Questions (p64)
The equation for acceleration is _____. The SI unit for measuring acceleration is _____. The difference between a vector and a scalar quantity is _____. A d-t graph for constant velocity is: A v-t graph for constant acceleration is: 5. The slope of a v-t graph represents _____.
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1-4 Investigate (p52-57) 6a) Draw AND label the d-t and v-t graph from the computer c) d-t graph, slope = _____ d) v-t graph, slope = _____ therefore shows a ______ acceleration
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Comparing Motion GRAPHS (p64)
Car at REST Car at CONSTANT VELOCITY Car at POSITIVE Acceleration Car at NEGATIVE Acceleration d-t Position does NOT change Position changes at a constant rate; STRAIGHT LINE Speeding up; CURVED LINE Slowing down; CURVED LINE v-t Velocity is ALWAYS ZERO The d-t is constant therefore acceleration is constant Increase in speed, therefore slope is positive (upward) Decrease in speed, therefore slope is negative (down)
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1-4 PTG (p68-71) 8. a) a = b) vave = c) d= 9. a) a = c) vf =
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1-4 PTG (p68-71) 10. a) b) 12. a) b) c) d) 13. a) a = b) ∆v = 15. a) a =
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1*4 TOTD
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