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A Reactions Review FREE RADICAL SUBSTITUTION POLYMERIZATION

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Presentation on theme: "A Reactions Review FREE RADICAL SUBSTITUTION POLYMERIZATION"— Presentation transcript:

1 A Reactions Review FREE RADICAL SUBSTITUTION POLYMERIZATION
ELECTROPHILIC ADDITION ( types) A) Hydration (add water, HOH) B) Halogenation (add H2) C) Bromination (add Br2) D) Hydrohalogenation (add HCl, HBr,HI (acids) ELIMINATION (Dehydrohalogenation) NUCLEOPHILIC SUBSTITUTION (add :OH-,:CN-,H2O, 2:NH3) OXIDATION A) 10 ALCOHOLS TO ALDEHYDES THEN TO CARBOXYLIC ACIDS B) 20 ALCOHOLS TO KETONES

2 REACTIONS OF ORGANIC COMPOUNDS
POLYMERS DIBROMOALKANES KETONES ALKANES ALKENES ALCOHOLS ALDEHYDES HALOGENOALKANES AMINES NITRILES CARBOXYLIC ACIDS CONVERSIONS

3 14 REACTIONS OF ORGANIC COMPOUNDS
POLYMERS DIBROMOALKANES KETONES P F C D ALKANES E ALKENES ALCOHOLS M N A B L ALDEHYDES G HALOGENOALKANES O H I AMINES NITRILES CARBOXYLIC ACIDS

4 Free radical substitution
Initiation Cl2 ——> 2Cl• radicals created Propagation Cl• CH ——> CH3• HCl radicals used and Cl CH3• ——> CH3Cl Cl• then re-generated Termination Cl• + Cl• ——> Cl2 radicals removed Cl• + CH3• ——> CH3Cl CH3• + CH3• ——> C2H6 Summary Due to the lack of reactivity of alkanes you need a very reactive species to persuade them to react. This is done by shining UV light on the mixture (heat could be used) CONVERSIONS

5 ELECTROPHILIC ADDITION OF HBr
(Hydrohalogenation) Reagent Hydrogen bromide... it is electrophilic as the H is slightly positive Condition Room temperature. Equation C2H4(g) HBr(g) ———> C2H5Br(l) bromoethane Mechanism Step 1: As the HBr nears the alkene, the Pi bond breaks The δ positive H joins a carbon (hydrogenation) The :Br ion forms. Also a carbocation (positively charged carbon species) is formed. Step 2 The bromide ion (halogen) is a nucleophile and attacks the carbocation. Br across the double bond. CONVERSIONS

6 ELECTROPHILIC ADDITION OF Br2
Reagent Bromine. (Neat liquid or dissolved in tetrachloromethane, CCl4 ) Conditions Room temperature. No catalyst or UV light required! Equation C2H4(g) + Br2(l) ——> CH2BrCH2Br(l) ,2 - dibromoethane Mechanism It is surprising that bromine should act as an electrophile as it is non-polar. CONVERSIONS

7 ELECTROPHILIC ADDITION with Water
(or HYDRATION) Reagent steam Catalyst Sand coated with sulphuric acid or phosphoric acid (BOTH WAYS) Product alcohol OR Ethene (depending on direction with Chatelier's principle) H2SO4, SiO2 Equation C2H4(g) H2O(g) C2H5OH(g) ethanol ⍙H = -45 KJ/mo So it is no surprise that the mechanism for hydration of alkenes is identical to that of dehydration of alcohols, but in the reverse order of steps. D and M are the same mechanism, in reverse CONVERSIONS

8 ELIMINATION OF WATER (DEHYDRATION)
Reagent/catalyst sulphuric acid (H2SO4) or conc. Conditions reflux at 180°C Equation e.g. C2H5OH(l) CH2 = CH2(g) H2O(l) So it is no surprise that the mechanism for hydration of alkenes is identical (as it is a REVERSABLE reaction) to that of dehydration of alcohols, but in the reverse order of steps. D and M are the same mechanism, in reverse Mechanism CONVERSIONS

9 ELECTROPHILIC ADDITION OF H2
or HYDROGENATION Reagent hydrogen Conditions nickel catalyst - finely divided Product alkanes Equation C2H4(g) H2(g) ———> C2H6(g) ethane Ni Use margarine manufacture (Hydrogenated fats for spreading on bread) CONVERSIONS

10 POLYMERISATION OF ALKENES
ETHENE POLY(ETHENE) PROPENE POLY(PROPENE) CHLOROETHENE POLY(CHLOROETHENE) POLYVINYLCHLORIDE PVC TETRAFLUOROETHENE POLY(TETRAFLUOROETHENE) PTFE “Teflon” CONVERSIONS

11 NUCLEOPHILIC SUBSTITUTION AQUEOUS SODIUM HYDROXIDE
G NUCLEOPHILIC SUBSTITUTION AQUEOUS SODIUM HYDROXIDE Reagent Aqueous* KOH or NaOH Conditions Reflux in aqueous solution (SOLVENT IS IMPORTANT) Product Alcohol Nucleophile hydroxide ion OH¯(aq) Equation e.g. C2H5Br(l) NaOH(aq) ———> C2H5OH(l) NaBr(aq) Mechanism * WARNING It is important to quote the solvent when answering questions. Elimination takes place when ethanol is the solvent The reaction (and the one with water) is known as HYDROLYSIS CONVERSIONS

12 NUCLEOPHILIC SUBSTITUTION
AMMONIA Reagent Aqueous, alcoholic ammonia (in EXCESS) Conditions Reflux in aqueous, alcoholic solution under pressure Product Amine Nucleophile Ammonia (NH3) Equation e.g. C2H5Br NH3 (aq / alc) ——> C2H5NH NH4Br (i) C2H5Br NH3 (aq / alc) ——> C2H5NH HBr (ii) HBr NH3 (aq / alc) ——> NH4Br Mechanism Notes The equation shows two ammonia molecules. The second one ensures that a salt is not formed. Excess ammonia is used to prevent further substitution (SEE NEXT SLIDE) CONVERSIONS

13 NUCLEOPHILIC SUBSTITUTION
POTASSIUM CYANIDE Reagent Aqueous, alcoholic potassium (or sodium) cyanide Conditions Reflux in aqueous , alcoholic solution Product Nitrile (cyanide) Nucleophile cyanide ion (CN¯) Equation e.g. C2H5Br KCN (aq/alc) ———> C2H5CN KBr(aq) Mechanism Importance it extends the carbon chain by one carbon atom the CN group can then be converted to carboxylic acids or amines. Hydrolysis C2H5CN H2O ——> C2H5COOH NH3 K CONVERSIONS

14 ELIMINATION Reagent Alcoholic sodium (or potassium) hydroxide
Conditions Reflux in alcoholic solution Product Alkene Mechanism Elimination Equation C3H7Br NaOH(alc) ———> C3H H2O NaBr Mechanism the OH¯ ion acts as a base and picks up a proton the proton comes from a C atom next to the one bonded to the halogen the electron pair moves to form a second bond between the carbon atoms the halogen is displaced; overall there is ELIMINATION of HBr. With unsymmetrical halogenoalkanes, a mixture of products may be formed. CONVERSIONS

15 OXIDATION OF PRIMARY ALCOHOLS
Primary alcohols are easily oxidised to aldehydes e.g. CH3CH2OH(l) [O] ———> CH3CHO(l) H2O(l) it is essential to distil off the aldehyde before it gets oxidised to the acid CH3CHO(l) [O] ———> CH3COOH(l) OXIDATION TO ALDEHYDES DISTILLATION OXIDATION TO CARBOXYLIC ACIDS REFLUX Aldehyde has a lower boiling point so distils off before being oxidised further Aldehyde condenses back into the mixture and gets oxidised to the acid CONVERSIONS

16 OXIDATION OF ALDEHYDES
Aldehydes are easily oxidised to carboxylic acids e.g. CH3CHO(l) [O] ———> CH3COOH(l) one way to tell an aldehyde from a ketone is to see how it reacts to mild oxidation ALDEHYES are EASILY OXIDISED KETONES are RESISTANT TO MILD OXIDATION TOLLENS’ REAGENT Reagent ammoniacal silver nitrate solution Observation a silver mirror is formed on the inside of the test tube Products silver + carboxylic acid Equation Ag e- ——> Ag CONVERSIONS

17 OXIDATION OF SECONDARY ALCOHOLS
P OXIDATION OF SECONDARY ALCOHOLS Secondary alcohols are easily oxidised to ketones e.g CH3CHOHCH3(l) [O] ———> CH3COCH3(l) H2O(l) The alcohol is refluxed with acidified K2Cr2O7. However, on prolonged treatment with a powerful oxidising agent they can be further oxidised to a mixture of acids with fewer carbon atoms than the original alcohol. CONVERSIONS


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