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Dates of … Quiz 5.4 – 5.5 Chapter 5 homework quiz Chapter 5 test
Both sides of one note card 2nd Quarter project work day
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Sections 5.4 – 5.5
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Two events are disjoint if __________.
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Two events are disjoint if they can not happen on the same opportunity.
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If A and B are disjoint events, then
P(A and B) is _____.
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If A and B are disjoint events, then
P(A and B) is 0.
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Two events are independent if __________.
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Two events are independent if the occurrence of one event does not change the probability that the other event will happen.
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Two events are independent if the occurrence of one event does not change the probability that the other event will happen. Two events are independent if and only if P(A) = P(A B).
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Two events are independent if and only if P(A) = P(A B).
P(A and B) = P(A) ● P(B), where P(A) > 0 and P(B) > 0.
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What is the Addition Rule for any two events A and B?
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P(A or B) = P(A) + P(B) – P(A and B)
What is the Addition Rule for any two events A and B? P(A or B) = P(A) + P(B) – P(A and B)
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What is the Multiplication Rule?
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Multiplication Rule The probability that event A and event B both happen is given by: P(A and B) = P(A)●P(B A) or P(A and B) = P(B)●P(A B)
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Multiplication Rule for Independent Events
P(A and B) = P(A) ● P(B), where P(A) > 0 and P(B) > 0.
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P(at least one success) = ?
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P(at least one success) =
1 – P(no successes)
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 650 Did Not Survive Total 1640 2000
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 650 Did Not Survive 1350 Total 1640 360 2000
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 650 Did Not Survive 1350 Total 1640 360 2000 P(A) = P(A I B)
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 650 Did Not Survive 1350 Total 1640 360 2000 P(A) = P(A I B) P(Survived) = P(Survived I Male)
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 650 Did Not Survive 1350 Total 1640 360 2000
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived x 650 Did Not Survive 1350 Total 1640 360 2000
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 533 650 Did Not Survive 1350 Total 1640 360 2000
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Complete this table so that the events survived and male are independent. Show your work.
Male Female Total Survived 533 117 650 Did Not Survive 1107 243 1350 Total 1640 360 2000
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Page 335, P32
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Page 335, P32 Right-Handed Left-Handed Total Blue Eyes
_______________________________ Brown Eyes Total
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Page 335, P32 Right-Handed Left-Handed Total Blue Eyes 2 10
_______________________________ Brown Eyes Total
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Page 335, P32 P(Right-handed I Brown eyes) = ?
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Page 335, P32
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Page 335, P32 Are the events right-handed and brown eyes independent?
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Page 335, P32 Are the events right-handed and brown eyes independent? P(A) = P(A B)? Is P(right-handed) = P(right-handed brown eyes)?
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Page 335, P32 P(right-handed) = 24/30 = 0.8
P(right-handed brown eyes) = 16/20 = 0.8 these are independent events.
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Page 335, P32 Are the events right-handed and brown eyes independent? P(B) = P(B A)?
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Page 335, P32 Are the events right-handed and brown eyes independent?
Is P(brown eyes) = P(brown eyes right-handed)?
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Page 335, P32 P(brown eyes) = 20/30 = 2/3
P(brown eyes right-handed) = 16/24 = 2/3 these are independent events.
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Page 346, E59
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Page 346, E59
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Page 346, E59
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Page 346, E59
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Page 346, E59
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Page 346, E59
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Page 346, E59
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Page 347, E63
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Page 347, E63 a. P(Type O blood and Rh-positive) =
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Page 347, E63
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Page 347, E63 b. P(Type O blood or Rh-positive) =
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Page 347, E63 b. P(Type O blood or Rh-positive) =
Are these disjoint events?
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Page 347, E63 b. P(Type O blood or Rh-positive) =
Are these disjoint events? No So need to avoid double-counting outcomes.
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Page 347, E63
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Page 347, E63 c. Make a table that summarizes this situation.
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Page 347, E63 c Rh-positive Yes No Total Yes Type O No Total
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Page 347, E63 c. Rh-positive Yes No Total Yes 2.1 42 Type O No
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Page 347, E63
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Review Continued
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Page 338, E51
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Positive Negative Total
Page 338, E51 Test Result Positive Negative Total Yes Disease No Total ,000
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Disease occurs in about 3% of population.
Page 338, E51 Disease occurs in about 3% of population. Test Result Positive Negative Total Yes Disease No Total ,000
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Disease occurs in about 3% of population.
Page 338, E51 Disease occurs in about 3% of population. Test Result Positive Negative Total Yes ,000 Disease No Total ,000
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Positive Negative Total
Page 338, E51 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive result 6% of time for people without the disease.
Page 338, E51 Positive result 6% of time for people without the disease. Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive result 6% of time for people without the disease.
Page 338, E51 Positive result 6% of time for people without the disease. Test Result Positive Negative Total Yes ,000 Disease No 6%(97000) = ,000 5820 Total ,000
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Positive Negative Total
Page 338, E51 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive Negative Total
Page 338, E51 Negative result 0.5% of time for people with the disease Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive Negative Total
Page 338, E51 Negative result 0.5% of time for people with the disease Test Result Positive Negative Total Yes 0.5%(3000) ,000 Disease = 15 No ,000 Total ,000
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Positive Negative Total
Page 338, E51 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive Negative Total
Page 338, E51 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive Negative Total
Page 338, E51(b) ≈ 0.088 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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Positive Negative Total
Page 338, E51(c) ≈ 0.661 Test Result Positive Negative Total Yes ,000 Disease No ,000 Total ,000
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You are going to draw two cards from a standard deck of cards
You are going to draw two cards from a standard deck of cards. What must happen to ensure pairs of successive selections are independent?
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You are going to draw two cards from a standard deck of cards
You are going to draw two cards from a standard deck of cards. What must happen to ensure pairs of successive selections are independent? The first card must be replaced in the deck before the second card is drawn.
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Suppose you roll a fair die and get a 3 seven times in a row
Suppose you roll a fair die and get a 3 seven times in a row. What is the probability you will get a 3 on the next roll?
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Suppose you roll a fair die and get a 3 seven times in a row
Suppose you roll a fair die and get a 3 seven times in a row. What is the probability you will get a 3 on the next roll? The die has no memory so each roll is an independent event. P(3 on next roll) = 1/6
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The proportion of 18-year-olds who are registered to vote is approximately 15%.
Describe how to use the following lines from a random digit table to simulate taking a sample of ten 18-year-olds and recording whether they are registered to vote.
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Model Registered to vote: 01 - 15 Not registered to vote: 16 – 99, 00
or Registered to vote: Not registered to vote: 15 – 99
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.)
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 EduBallot online voting instructions
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 EduBallot online voting instructions
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 Sample 2 EduBallot online voting instructions
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 Sample 2 EduBallot online voting instructions
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 Sample 2 Sample 3 EduBallot online voting instructions
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b. Start at the beginning of the first line, take three samples of size 10, and compute the sample proportion for each sample. (Do not start a new line for each sample. Start where the previous sample finished.) Sample 1 Sample 2 Sample 3 EduBallot online voting instructions
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b. Sample 1: Using the assignment 01–15 for registered 18-year-olds, you’ll find the sample proportion is 2/10 or 0.2. Using the assignment 00–14 for registered 18-year-olds, you’ll find the sample proportion is 1/10 or 0.1. Sample 2: Using either assignment from part a, you’ll find the sample proportion is 0/10 or 0. Sample 3: Using either assignment from part a, you’ll find the sample proportion is 0/10, or 0.
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Questions?
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