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CHEMISTRY 161 Chapter 5 www.chem.hawaii.edu/Bil301/welcome.html.

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Presentation on theme: "CHEMISTRY 161 Chapter 5 www.chem.hawaii.edu/Bil301/welcome.html."— Presentation transcript:

1 CHEMISTRY 161 Chapter 5

2 Classification of Matter
solid liquid gas

3 1. Gases substances that exist in the gaseous phase under normal atmospheric conditions T = 25oC p = 1 atm

4 HF, HCl, HBr, HI CO, CO2 CH4, NH3, H2S, PH3 NO, NO2, N2O SO2

5 Jupiter (H2, He) Io (SO2)

6 Helix Nebula Orion Nebula

7 Hindenburg (1937)

8 molecules/atoms of gas are constantly in motion
2. Pressure Ar molecules/atoms of gas are constantly in motion

9 Atmospheric Pressure

10 Standard Atmospheric Pressure
760 mm at 273 K at sea level Torricelli barometer 1 atm = 760 mm Hg = 760 torr pressure of the atmosphere is balanced by pressure exerted by mercury

11 SI units force pressure = area p = F / A [p] = Nm-2 = kg m-1 s-2 = Pa

12 pressure measurement manometer

13 3. Gas Laws 3.1. pressure p versus volume V
3.2. temperature T versus volume V 3.3. volume V versus amount n p, V, T, n

14 (temperature is constant)
3.1. Boyle’s Law pressure – volume relationship (temperature is constant) Boyle ( )

15 p ∞ 1/V

16 p ∞ 1/V p = const/V p × V = const p1 × V1 = const p2 × V2 = const
p1 × V1 = p2 × V2

17 (pressure is constant)
3.2. Gay-Lussac’s Law temperature – volume relationship (pressure is constant) Gay-Lussac ( )

18 V ∞ T

19 V ∞ T V = const’ ×T V/T = const’ V1 / T1 = const’ V2 / T2 = const
V1 / T1 = V2 / T2

20 (pressure and temperature
3.3. Avogadro’s Law amount – volume relationship (pressure and temperature are constant) Avogadro ( )

21 2 H2(g) + O2(g) → 2 H2O(l) n ∞ V

22 n ∞ V n = const’’ × V n/V = const’’ n1 / V1 = const’’
n1 / V1 = n2 / V2

23 SUMMARY p ∞ 1/V V ∞ T n ∞ V 3.1. Boyle’s Law 3.2. Gay-Lussac’s Law
3.3. Avogadro’s Law p ∞ 1/V V ∞ T n ∞ V

24 Homework Chapter 5, p problems


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