Download presentation
Presentation is loading. Please wait.
Published byKristin Murphy Modified over 6 years ago
1
CHEMISTRY 161 Chapter 5
2
Classification of Matter
solid liquid gas
3
1. Gases substances that exist in the gaseous phase under normal atmospheric conditions T = 25oC p = 1 atm
4
HF, HCl, HBr, HI CO, CO2 CH4, NH3, H2S, PH3 NO, NO2, N2O SO2
5
Jupiter (H2, He) Io (SO2)
6
Helix Nebula Orion Nebula
7
Hindenburg (1937)
8
molecules/atoms of gas are constantly in motion
2. Pressure Ar molecules/atoms of gas are constantly in motion
9
Atmospheric Pressure
10
Standard Atmospheric Pressure
760 mm at 273 K at sea level Torricelli barometer 1 atm = 760 mm Hg = 760 torr pressure of the atmosphere is balanced by pressure exerted by mercury
11
SI units force pressure = area p = F / A [p] = Nm-2 = kg m-1 s-2 = Pa
12
pressure measurement manometer
13
3. Gas Laws 3.1. pressure p versus volume V
3.2. temperature T versus volume V 3.3. volume V versus amount n p, V, T, n
14
(temperature is constant)
3.1. Boyle’s Law pressure – volume relationship (temperature is constant) Boyle ( )
15
p ∞ 1/V
16
p ∞ 1/V p = const/V p × V = const p1 × V1 = const p2 × V2 = const
p1 × V1 = p2 × V2
17
(pressure is constant)
3.2. Gay-Lussac’s Law temperature – volume relationship (pressure is constant) Gay-Lussac ( )
18
V ∞ T
19
V ∞ T V = const’ ×T V/T = const’ V1 / T1 = const’ V2 / T2 = const
V1 / T1 = V2 / T2
20
(pressure and temperature
3.3. Avogadro’s Law amount – volume relationship (pressure and temperature are constant) Avogadro ( )
21
2 H2(g) + O2(g) → 2 H2O(l) n ∞ V
22
n ∞ V n = const’’ × V n/V = const’’ n1 / V1 = const’’
n1 / V1 = n2 / V2
23
SUMMARY p ∞ 1/V V ∞ T n ∞ V 3.1. Boyle’s Law 3.2. Gay-Lussac’s Law
3.3. Avogadro’s Law p ∞ 1/V V ∞ T n ∞ V
24
Homework Chapter 5, p problems
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.